Prévia do material em texto
<p>/ / 1 STTR : T= 400°C + Us=7,5m - Z=10m us - SA= K'Capb - a(t) K.CAO 1 + KACA - 1 1+ Eq. dx = = 1 dz FAO dz 1+ KACA CA Do Ac L dz dx = 1 (1-x) FAO 2 dx = 1 -</p><p>/ / 10 1+3.02(1-x) dx = 1 dz = 7.5 = 1,6869 5 0,741 74,1% C</p><p>/ / 2 STTR Co = Eq dx - md J2 Ed= 15000cal 80 kgcd mol Lei do als = 2.5 m - K. alt) Us FAO = t de It Kd. a da a = = - = = - lne + = - lna = kd.t - D alt) = e PA = E= (1+8x) dx = e (1+x) 2 (1+x) dx K fb AcPto e MAD DOMINGOS</p><p>/ dx = (1-x) = 773K 0.189 exp = 773 673 k exp 673 773 15 dx = X-4 0,9118 X- L X= 0,4425 44,25%</p><p>/ / 3 W= 100 Kg -4 B = dm3 dx = 5 min lei t Lei do Kd a2 = It u 1 W Us a a L CA= x) Fao = dx = 1+ kd.w Us u W = said 4 Ent u l l = dw 4 u 1-X Do -5 = 0.3 kg In = 1.2322 1-X (1.2322) 1 = e = 70,8% 3,429</p><p>/ / de leite 4 1000 = R FAO : CAO = h I 1 tq 2.) dx = = 200 FAO - CA = CAO (1 at XA W dx - 200 dx = dw 5000 5000 XA = 200. XA = 5000 1 -XA 5000 100 a - D XA = 100a so Ca 1-XA 1- XA It 100a CAO 1-XA = 1000 = CA = 141000 CAO b total no inicial: XA 100.1 = 0.99 99%</p><p>C - do = 10 a -D = It a alt) = e XA = -0.5.12 = 0,198 19,8% a eq = 100a que e - 1+100a X1=0,984 Xs Xa Xo = X10 = 0.402 X=0,698 X7 = 0.751 X11 = 0,290 0.647 X12 = 0,198 69.8%</p>