Solução de Exercícios de Integral Dupla

Prévia do material em texto

@ "') fJ.\X+Y,+1)c&~::: r(frx+y.H) dx.)..IY
= J. (~ -t Xy -h< 1.1- ) dy
r ((t + 27 -t 2. ) - ( t -t y + 1) ) d>-
o
= r ((Lf «» y) - (r + y)) p( y
..,
z: t (~-I- y) ~y
= s. y -+- _{z.. lu
-s=- .."..,----z. Z- - .3 .-
@ f r (x 4- 2. 7 ) /y'& z: f (f{u.Jy ).Iy).6:
=" f ()(y + yZ luZ) ct<
= r (t:» + '-< ) dx,
- xl -+- L(x t -
::: 1 -I- l.f
- 5-
a/1-
G) J. t" (t+"I.y)dyti<. = f( f (x-r.;y)rIx },(Y
:: f1( ~ -4-t y »; C )pY
= r("':1- 10y ) dy
~
-== ~~ y -f ~yZ- J
Z- <
-= ez . 4 -+ S· 16) -. ( ::>-z.,. - • z, +~. 4J
- ('5o -t 5 16) - t= -t '>- '1 )
_ (<;'0 - 2-:» -I- (s ,;(6 - ·4)
-= 7'> + $ (?6-Lf)
- z ~ -+ ./2.
uf) tL l.J
o
z ( )( +- ,) y) tiY d< z: J.e: z,( jol (X + 1Y )dy ) p/x
= 1.(" ( ><y +y r- ) Á
./42=1 (zx+-1-)Á-
-,:: x 2. -t 2. >< }o .•...?.
- (~1..)?+ z .e... ,z
-- ú:, .J) (~ z.) l' t )
J------7L =J-f ~ -1..( á -.,~-0, -z
• ...I!L ( ?J. )
f) lJf\y,dyd< -= l~(fxy2.dy)A:
o ~ f ( Kf 1.3 j ;
-= ) (", ()'7 X3 ) tA.
=J ~('1 x!.( ) dx.
o
:::- q~ Jl = q·3$
5" Õ s:
I'
Jy';" y' dy = J~' d;::- = -t J J..•.•' ~
.2z-
~2-
Z- (3/2-)
.3/z..
-::: ..i- (Lf+YZ.)
3
.e« = Lj.fy2.
d<A .s: z-yd'y
k =- ydy
"Z--
v (j) :::rr ()(~cJy)tlx.dy "" f(f ()t'+o>yJJ, )cly
~»~XZ-L -f ZXY/J - f (i- -I "~),1r
_ Ly -f y'Z.{" -:::...L -f '-:::- ~
rJ- o z, 2-#
A(/f) :::j' (<Zj dy A.
I> J.(J
..f( Y t:~t)~
= J (;(1_ J(l)eJ<
()
:: ~ -~ I3 "1 ()
1::::-T - 4- -12--'-1
.2. ~-)Cl.. t(y 4_')A {IO z:J J ..Jy tb. :: dx.1,_ "-J. 1 fi -.J
:.J
L
Z(t" )(7 -( ) - C-t JA
==l
L
(8-2 ~ - - •.3 L.'l.- .3-.,t..
=-('6 -1)- (- ~)
- 3~ _ :l-"- z
- II - '3 2. - q,- -- - .s .3
~