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01/10/14 1 1 Prof. Dr. José Eduardo Damas Martins Reações de derivados de ácidos carboxílicos 2 Prof. Dr. José Eduardo Damas Martins SUBSTITUIÇÃO NUCLEOFÍLICA NO CARBONO ACÍLICO 01/10/14 2 3 Prof. Dr. José Eduardo Damas Martins É a principal reação realizada por derivados de ácidos carboxílicos. 4 Prof. Dr. José Eduardo Damas Martins Cloreto de ácido Anidrido Éster Amidas Derivados de ácido carboxílico 01/10/14 3 5 Prof. Dr. José Eduardo Damas Martins Adição nucleofílica Instável Relembremos a reação de formação de Hemi-acetais O HO OR OH ROH Hemiacetal 6 Prof. Dr. José Eduardo Damas Martins A ins tab i l idade é dev ido à facilidade com que o grupo RO─ é expulso da molécula Intermediário instável Grupo de saída 01/10/14 4 7 Prof. Dr. José Eduardo Damas Martins Grupos que podem ser expulsos de uma molécula, levando consigo a carga negativa, são chamados de “Grupos de partida ou de saída” Cl Br IRO RCO2RS, , , , , 8 Prof. Dr. José Eduardo Damas Martins Se o nucleófilo é também um grupo de saída, há a chance de, após a adição, ele ser eliminado e portanto a reação se torna “rreversível” O HO OR OH ROH Hemiacetal 01/10/14 5 9 Prof. Dr. José Eduardo Damas Martins O mesmo pode acontecer caso o material de partida contenha um potencial grupo de saída Instável Cetona continua reagindo Substituição nucleofílica acílica 10 Prof. Dr. José Eduardo Damas Martins Substituição nucleofílica acílica R X O + Nu R Nu O + X Derivado de ác. carboxílico 01/10/14 6 11 Prof. Dr. José Eduardo Damas Martins Mecanismo R X O Nu R Nu O + X X O Nu Grupo de saída Intermediário tetraédrico instável 12 Prof. Dr. José Eduardo Damas Martins Hidrólise R OR O R O O + RO OR O OH Grupo de saída OH H2O H R O O Na NaOH + ROH Sal de ácido carboxílico 01/10/14 7 13 Prof. Dr. José Eduardo Damas Martins Intermediário tetraédrico instável R Cl O R Cl O OCH3 HOCH3 Py H Py R Cl O OCH3 Observe a reação 14 Prof. Dr. José Eduardo Damas Martins Possibilidades: R Cl O OCH3 R OCH3 O + Cl 1) R Cl O OCH3 R Cl O 2) + OCH3 01/10/14 8 15 Prof. Dr. José Eduardo Damas Martins Cl─ ─OCH3 Cloreto Metóxi 16 Prof. Dr. José Eduardo Damas Martins O ânion mais estável tem preferência a sair 01/10/14 9 17 Prof. Dr. José Eduardo Damas Martins “Geralmente”o melhor grupo de saída é aquele que for a base mais estável, ou seja, a base mais fraca R Cl O OCH3 R OCH3 O + Cl 18 Prof. Dr. José Eduardo Damas Martins Como determinar quem é a base mais fraca? 01/10/14 10 19 Prof. Dr. José Eduardo Damas Martins Para isso, pode-se utilizar os valores de pKaH 20 Prof. Dr. José Eduardo Damas Martins Ácido forte = Base conjugada fraca Ácido fraco = Base conjugada forte HA + H2O H3O + A ácido base base conjugada ácido conjugado 01/10/14 11 21 Prof. Dr. José Eduardo Damas Martins pka = -log Ka Quanto menor o pka, maior é a acidez [H3O ] [A]Ka = [HA] 22 Prof. Dr. José Eduardo Damas Martins pKaH é o pKa da espécie protonada (ácido conjugado) pKaH de X = pKa HX pKaH de Cl = pKa HCl = -7 Exemplo: 01/10/14 12 23 Prof. Dr. José Eduardo Damas Martins R Cl O OCH3 R OCH3 O + Cl Cl HCl CH3O CH3OH Ac. conjugado Ac. conjugado pKaH = pKa = 7− pKaH = pKa = 15CH3OHCH3O- Cl HCl- 24 Prof. Dr. José Eduardo Damas Martins O HCl é um ácido mais forte que o metanol, portanto sua base conjugada, Cl− , é mais fraca. 01/10/14 13 25 Prof. Dr. José Eduardo Damas Martins portanto o Cl− , é melhor grupo de saída que o CH3O− . 26 Prof. Dr. José Eduardo Damas Martins Geralmente, quanto menor o pkaH, melhor o grupo de saída 01/10/14 14 27 Prof. Dr. José Eduardo Damas Martins Reatividade de derivados de ácido carboxílico 28 Prof. Dr. José Eduardo Damas Martins A reatividade depende da estrutura do derivado de ácido carboxílico R X O 01/10/14 15 29 Prof. Dr. José Eduardo Damas Martins Mais reativo Menos reativo 30 Prof. Dr. José Eduardo Damas Martins Por que as amidas são os derivados de ácidos carboxílicos menos reativos ? R NH2 O 01/10/14 16 31 Prof. Dr. José Eduardo Damas Martins A estabilização por ressonância explica a baixa reatividade Carbonila de amidas é menos eletrofílica 32 Prof. Dr. José Eduardo Damas Martins the hierarchy. We’ve seen that this hierarchy is partly due to how good the leaving group is (the ones at the top are best), and partly due to how good the nucleophile needed to make the derivative is (the ones at the bottom are best). most reactive acid chlorides (acyl chlorides) acid anhydrides esters amides least reactive Delocalization and the electrophilicity of carbonyl compounds All of these derivatives will react with water to form carboxylic acids, but at very different rates. Hydrolysing an amide requires boiling in 10% NaOH or heating overnight in a sealed tube with concentrated HCl. Amides are the least reactive towards nucleophiles because they exhibit the great- est degree of delocalization. You met this concept in Chapter 7 and we shall return to it many times more. In an amide, the lone pair on the nitrogen atom can be stabilized by overlap with the π* orbital of the carbonyl group—this overlap is best when the lone pair occupies a p orbital (in an amine, it would occupy an sp3 orbital). The molecular orbital diagram shows how this interaction both lowers the energy of the bonding orbital (the delocalized nitrogen lone pair), making it neither basic nor nucleophilic, and raises the energy of the π* orbital, making it less ready to react with nucleophiles. Esters are similar but, because the oxygen lone pairs are lower in energy, the effect is less pronounced. The greater the degree of delocalization, the weaker the C=O bond becomes. This is most clearly R NH2 O R OR1 O R O O R1 O R Cl O Not all carboxylic acid derivatives are equally reactrive 287 R O Cl R O OH R O O R O OH O H2O fast at 20 ˚C H2O slow at 20 ˚C R O OEt R O NH2 R O OH R O OH H2O only on heating with acid or base catalyst H2O only on prolonged heating with strong acid or base catalyst H N C O R H H N O H R H N O H R molecular orbital diagram shows how energy of orbitals changes as lone pair and C=O π* interact isolated lone pair on N isolated C=O π* orbital new, stabilized lower-energy lone pair orbitals overlap empty π* orbital lone pair in p orbital new higher-energy π* orbital allow orbitals to interact Velocidades de hidrólise de derivados de ácido carboxílico Rápida a 20 0C the hierarchy. We’ve seen that this hierarchy is partly due to how good the leaving group is (the ones at the top are best), and partly due to how good the nucleophile needed to make the derivative is (the ones at the bottom are best). most reactive acid chlorides (acyl chlorides) acid anhydrides esters amides least reactive Delocalization and the electrophilicity of carbonyl compounds All of these derivatives will react with water to form carboxylic acids, but at very different rates. Hydrolysing an amide requires boiling in 10% NaOH or heating overnight in a sealed tube with concentrated HCl. Amides are the least reactive towards nucleophiles because they exhibit the great- est degree of delocalization. You met this concept in Chapter 7 and we shall return to it many times more. In an amide, the lone pair on the nitrogen atom can be stabilized by overlap with the π* orbital of the carbonyl group—this overlap is best when the lone pair occupies a p orbital (in an amine, it would occupy an sp3 orbital). The molecular orbital diagram shows how this interaction both lowers the energy of the bonding orbital (the delocalized nitrogen lone pair), making it neither basic nor nucleophilic, and raises the energy of the π* orbital, making it less ready to react with nucleophiles. Esters are similar but, because the oxygen lone pairs are lower in energy, the effect is less pronounced. The greater the degree of delocalization, the weaker the C=O bond becomes. This is most clearly R NH2 O R OR1 O R O O R1 O R Cl O Not all carboxylic acid derivatives are equally reactrive 287 R O Cl R O OH R O O R O OH O H2O fast at 20 ˚C H2O slow at 20 ˚C R O OEt R O NH2 R O OH R O OH H2O only on heating with acid or base catalyst H2O only on prolonged heating with strong acid or base catalyst H N C O R H H N O H R H N O H R molecular orbital diagram shows how energy of orbitals changes as lone pair and C=O π* interact isolated lone pair on N isolated C=O π* orbital new, stabilized lower-energy lone pair orbitals overlap empty π* orbital lone pair in p orbital new higher-energy π* orbital allow orbitals to interact Lenta a 20 0C Cloreto de ácido Anidrido 01/10/14 17 33 Prof. Dr. José Eduardo Damas Martins the hierarchy. We’ve seen that this hierarchy is partly due to how good the leaving group is (the ones at the top are best), and partly due to how good the nucleophile needed to make the derivative is (the ones at the bottom are best). most reactive acid chlorides (acyl chlorides) acid anhydrides esters amides least reactive Delocalization and the electrophilicity of carbonyl compounds All of these derivatives will react with water to form carboxylic acids, but at very different rates. Hydrolysing an amide requires boiling in 10% NaOH or heating overnight in a sealed tube with concentrated HCl. Amides are the least reactive towards nucleophiles because they exhibit the great- est degree of delocalization. You met this concept in Chapter 7 and we shall return to it many times more. In an amide, the lone pair on the nitrogen atom can be stabilized by overlap with the π* orbital of the carbonyl group—this overlap is best when the lone pair occupies a p orbital (in an amine, it would occupy an sp3 orbital). The molecular orbital diagram shows how this interaction both lowers the energy of the bonding orbital (the delocalized nitrogen lone pair), making it neither basic nor nucleophilic, and raises the energy of the π* orbital, making it less ready to react with nucleophiles. Esters are similar but, because the oxygen lone pairs are lower in energy, the effect is less pronounced. The greater the degree of delocalization, the weaker the C=O bond becomes. This is most clearly R NH2 O R OR1 O R O O R1 O R Cl O Not all carboxylic acid derivatives are equally reactrive 287 R O Cl R O OH R O O R O OH O H2O fast at 20 ˚C H2O slow at 20 ˚C R O OEt R O NH2 R O OH R O OH H2O only on heating with acid or base catalyst H2O only on prolonged heating with strong acid or base catalyst H N C O R H H N O H R H N O H R molecular orbital diagram shows how energy of orbitals changes as lone pair and C=O π* interact isolated lone pair on N isolated C=O π* orbital new, stabilized lower-energy lone pair orbitals overlap empty π* orbital lone pair in p orbital new higher-energy π* orbital allow orbitals to interact Só ocorre com aquecimento e catálise ácida ou básica the hierarchy. We’ve seen that this hierarchy is partly due to how good the leaving group is (the ones at the top are best), and partly due to how good the nucleophile needed to make the derivative is (the ones at the bottom are best). most reactive acid chlorides (acyl chlorides) acid anhydrides esters amides least reactive Delocalization and the electrophilicity of carbonyl compounds All of these derivatives will react with water to form carboxylic acids, but at very different rates. Hydrolysing an amide requires boiling in 10% NaOH or heating overnight in a sealed tube with concentrated HCl. Amides are the least reactive towards nucleophiles because they exhibit the great- est degree of delocalization. You met this concept in Chapter 7 and we shall return to it many times more. In an amide, the lone pair on the nitrogen atom can be stabilized by overlap with the π* orbital of the carbonyl group—this overlap is best when the lone pair occupies a p orbital (in an amine, it would occupy an sp3 orbital). The molecular orbital diagram shows how this interaction both lowers the energy of the bonding orbital (the delocalized nitrogen lone pair), making it neither basic nor nucleophilic, and raises the energy of the π* orbital, making it less ready to react with nucleophiles. Esters are similar but, because the oxygen lone pairs are lower in energy, the effect is less pronounced. The greater the degree of delocalization, the weaker the C=O bond becomes. This is most clearly R NH2 O R OR1 O R O O R1 O R Cl O Not all carboxylic acid derivatives are equally reactrive 287 R O Cl R O OH R O O R O OH O H2O fast at 20 ˚C H2O slow at 20 ˚C R O OEt R O NH2 R O OH R O OH H2O only on heating with acid or base catalyst H2O only on prolonged heating with strong acid or base catalyst H N C O R H H N O H R H N O H R molecular orbital diagram shows how energy of orbitals changes as lone pair and C=O π* interact isolated lone pair on N isolated C=O π* orbital new, stabilized lower-energy lone pair orbitals overlap empty π* orbital lone pair in p orbital new higher-energy π* orbital allow orbitals to interact Só ocorre com aquecimento prolongado e catálise com ácidos ou bases fortes Éster Amida 34 Prof. Dr. José Eduardo Damas Martins 1 – X deve ser melhor grupo de saída que Nu 2 – Nu deve ser um nucleófilo forte o suficiente para realizar a adição à carbonila 3 - deve ser um eletrófilo suficientemente forte para reagir com Nu Condições para que a reação ocorra R X O Nu R Nu O + X R X O 01/10/14 18 35 Prof. Dr. José Eduardo Damas Martins Esterificação de Fisher 36 Prof. Dr. José Eduardo Damas Martins Esterificação de Fischer 01/10/14 19 37 Prof. Dr. José Eduardo Damas Martins Mecanismo 38 Prof. Dr. José Eduardo Damas Martins Mecanismo ? 01/10/14 20 39 Prof. Dr. José Eduardo Damas Martins Mecanismo ? 40 Prof. Dr. José Eduardo Damas Martins Devido à formação de água durante a reação, a mesma d e v e s e r r e m o v i d a utilizando-se um Dean-stark ou qualquer outro agente secante para que o equilíbrio seja deslocado no sentido de formação do éster. Dean-Stark 01/10/14 21 41 Prof. Dr. José Eduardo Damas Martins
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