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558 16MOLECULES INMOTION 16B Motion in liquids Answers to discussion questions D16B.2 �e Grotthuss mechanism for conduction by protons in water is described in Section 16B.2(a) on page 701 and illustrated in Fig. 16B.2 on page 703. It seems plausible that such a mechanism could also occur in the relatively open hydrogen bonded structure of ice. Solutions to exercises E16B.1(b) �e temperature dependence of the viscosity η is given by [16B.1–699], η = η0eEa/RT , where η0 is viscosity in the limit of high temperature and Ea is the associated activation energy. Taking the natural logarithm gives ln η = ln η0 + Ea/RT . Hence ln η1 − ln η2 = (ln η0 + Ea/RT1) − (ln η0 + Ea/RT2) = Ea R ( 1 T1 − 1 T2 ) Rearranging gives an expression for the activation energy Ea = R ln (η1/η2) (T−11 − T−12 ) = (8.3145 JK−1mol−1) ln [(1.554 cP)/(1.450 cP)] [(293.15 K)−1 − (313.15 K)−1] = 2.64 kJmol−1 E16B.2(b) According to the law of independent migration of ions, the limiting molar conductivity Λ○m of an electrolyte is given by the sum of the limiting molar conductivities λ i of the ions present, [16B.6–701], Λ○m = ν+λ+ + ν−λ−; in this expression ν+ and ν− are the numbers of cations and anions provided by each formula unit of electrolyte. For each of the given electrolytes it follows that Λ○KF = λK+ + λF− Λ○KCH3CO2 = λK+ + λCH3CO2− Λ○Mg(CH3CO2)2 = λMg2+ + 2λCH3CO2− �ese expressions are manipulated to give Λ○MgF2 Λ○MgF2 = λMg2+ + 2λF− = (Λ○Mg(CH3CO2)2 − 2λCH3CO2−) + 2(Λ ○ KF − λK+) = Λ○Mg(CH3CO2)2 + 2Λ ○ KF − 2(λCH3CO2− + λK+) = Λ○Mg(CH3CO2)2 + 2Λ ○ KF − 2Λ○KCH3CO2 = [18.78 + 2(12.89) − 2(11.44)]mSm2mol−1 = 21.68 mSm2mol−1