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Step of 6 8.017P Refer to Figure 8.12(a) from the text book. Consider the expression for transconductance 8ml in terms of the over drive voltage and the bias current. Substitute 100 for 8ml 200 8ml Therefore, the expression for the over drive voltage is 8ml Step of 6 Consider the expression for the transconductance Substitute 200 for 10 µm for 0.5 µm for 4 and 500 for 8ml Therefore, the value of 8ml is 1.414 mS Step of 6 Calculate the value of the input resistance - 8ml Substitute 1.414 mS for 8ml Therefore, the value of the input resistance is Step of 6 Calculate the value of the current gain Substitute 10 µm for 50 µm for and 0.5 µm for 4 and L₂ 5 Therefore, the value of the current gain is 5 Step of 6 Calculate the value of the output current I₀ Substitute 5 for and 100 for Therefore, the value of the output current is 500 Step of 6 Calculate the value of the output resistance Substitute 10 V/µm for 0.5 µm for L₂ and 500 for 500 = 10 kΩ Therefore, the value of the output resistance is