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Chapter 1 Measurement and Vectors Conceptual Problems [SSM] Determine the Concept 2 • Picture the Problem 3 • Determine the Concept 4 • Determine the Concept 5 • [SSM] Picture the Problem Remarks: Because there are exactly 2.54 cm in 1 in and exactly 12 inches in 1 ft, we are justified in reporting four significant figures in these results. 6 • Determine the Concept 7 • Determine the Concept 8 Determine the Concept 9 • 10 • Determine the Concept 11 • [SSM] Determine the Concept 12 • Determine the Concept 13 • [SSM] Determine the Concept Estimation and Approximation 14 • Picture the Problem 15 • [SSM] Picture the Problem 16 •• Picture the Problem 17 •• Picture the Problem 18 •• Picture the Problem 19 •• [SSM] Picture the Problem Units 20 • Picture the Problem 21 • Picture the Problem 22 • Picture the Problem 23 •• [SSM] Picture the Problem 24 •• Picture the Problem Conversion of Units 25 • Picture the Problem 26 • Picture the Problem 27 • Picture the Problem 28 • Picture the Problem 29 • Picture the Problem 30 • Picture the Problem 31 • Picture the Problem 32 • Picture the Problem 33 •• [SSM] Picture the Problem 34 •• Picture the Problem 35 •• [SSM] Picture the Problem Dimensions of Physical Quantities 36 • Picture the Problem 37 • Picture the Problem 38 •• Picture the Problem 39 •• Picture the Problem 40 •• Picture the Problem 41 •• [SSM] Picture the Problem 42 •• Picture the Problem Remarks: While it is true that , dimensional analysis does not reveal the presence of dimensionless constants. For example, if the analysis shown above would fail to establish the factor of 43 •• [SSM] Picture the Problem 44 •• Picture the Problem Scientific Notation and Significant Figures 45 • [SSM] Picture the Problem 46 • Picture the Problem 47 • [SSM] Picture the Problem 48 • Picture the Problem 49 • [SSM] Picture the Problem 50 •• Picture the Problem 51 •• [SSM] Picture the Problem Vectors and Their Properties 52 • Picture the Problem Remarks: You could also solve Part ( ) of this problem by using the law of cosines. 53 • [SSM] Picture the Problem 54 • Picture the Problem Remarks: In Part ( ) we could have used the Pythagorean Theorem to find the magnitude of 55 • Picture the Problem 56 • Picture the Problem Remarks: If you use the Pythagorean Theorem and right-triangle trigonometry, you’ll find that the length of the second leg of your journey is 265 m and that = 19 S of E. 57 •• Picture the Problem 58 •• Picture the Problem Remarks: The analytical results for and are in excellent agreement with the values determined graphically. 59 •• [SSM] Picture the Problem 60 •• Picture the Problem Remarks: One can confirm that a given vector is, in fact, a unit vector by checking its magnitude. General Problems 61 • [SSM] Picture the Problem Remarks: An alternative to multiplying by 103 m/km in the last step is to replace the metric prefix k in km by 103. 62 • Picture the Problem 63 • Picture the Problem 64 • Picture the Problem 65 • Picture the Problem 66 •• Picture the Problem 67 •• Picture the Problem 68 •• Picture the Problem 69 •• Picture the Problem 70 •• Picture the Problem 71 ••• Picture the Problem 0.80 0.90 1.00 1.10 1.20 1.30 1.40 1.50 1.60 1.70 1.80 0.50 0.60 0.70 0.80 0.90 1.00 Remarks: One could use a graphing calculator to obtain the results in Parts ( ) and ( ). 72 ••• Picture the Problem 0.00 0.20 0.40 0.60 0.80 1.00 1.20 1.40 0.00 0.20 0.40 0.60 0.80 1.00 1.20 1.40 Remarks: One could use a graphing calculator to obtain these results. 73 ••• [SSM] Picture the Problem 74 ••• Picture the Problem Remarks: One can also solve this problem using the law of sines. 75 ••• Picture the Problem -0.4 -0.2 0.0 0.2 0.4 0.6 0.8 1.0 -1.1 -1.0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 , , 76 ••• Picture the Problem 77 ••• Picture the Problem 78 ••• Picture the Problem
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