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Tarefa 8 - Limites in nitos Calcule os seguintes limites a) lim t!�1 t2+3t�10 t+5 b) lim x!�1 p x2+8�3 x+1 c) lim x!+1 p x2+8�3 x+1 d) lim �!+1 �4�1 �3�1 e) lim x!+1 p x2+8�3 x2�1 = limx!+1 ( p x2+8�3)( p x2+8+3) (x2�1)( p x2+8+3) = lim x!+1 (x2+8�9) (x2�1)( p x2+8+3) = lim x!+1 (x2�1) (x2�1)( p x2+8+3) = lim x!+1 1 ( p x2+8+3) = 0 f) lim x!+1 1�12x3 4x2+12 g) lim x!+1 3 p x�x�1 x+1 h) lim x!+1 2x 5 3�x 13 x 8 5+3x = lim x!+1 x 5 3 (2�x 13� 53 ) x 8 5 (1+3x1� 8 5 ) = lim x!+1 x 5 3 � 8 5 (2�x� 43 ) (1+3x� 3 5 ) = lim x!+1 x 1 15 (2�x� 43 ) (1+3x� 3 5 ) = lim x!+1 x 1 15 (2�0) (1+0) = +1 i) lim x!�1 p x2+8�3 x2+1 j) lim x!�1 1�12x3 4x2+12 k) lim x!�1 sen x 4x2+12 = 0 pois �1 � sen(x) � 1 l) lim x!�1 sen x+x2 4x2+12 = limx!�1 sen x 4x2+12 + limx!�1 x2 4x2+12 = 0 + 1 4 = 1 4 m) lim x!+1 sen 3x 2x n) lim x!+1 1�cos 3x 2x o) lim x!+1 � sen 3x 2x �2 p) lim x!+1 1�cos 3x 2x2 sen x q) lim x!�1 1�cos2 �x 2x2 1
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