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- Método de Colby (1957) 
 
Qsm = 0,0864*Q*C’s 
Qsm = 0,0864.139,35.30,83 
Qsm = 37,179 ton/dia 
 
log qnm= 3,432*logU + 1,6004 
logqnm=3,432*log(0,94)+1,6004 
logqnm =1,50 
qnm = 32,22 ton/dia/m 
 
logCr  A.logU  B 
logCr .log(0,94)  2,7782 
logCr = 2,71 Cr  522,42 mg/L 
 
e 
𝑐′𝑠
𝑐𝑟
=
3083
522,42
= 𝟓, 𝟗𝟎 
 
 
logK log c’s/cr + 0,0753 
logKlog (5,90) + 0,0753 = 0,440 
K = 2,755 
 
 
Qnm = qnm.B.K = 487,08 ton/dia 
Qnm = 32,22. 70,10. 2,755 
Qnm = 6,220 ton/dia 
 
 
 
Qst = Qsm + Qnm 
Qs t= 37,179+6,220 
Qst = 43,399 ton/dia 
 
 
 
 
 
 
 
 - Método de Engelund e Hansen (1967) 

o= . Rh.S ² 
o= = 𝟏, 𝟐𝟒 𝒙 𝟏𝟎−𝟑 
 
gs  0,05.s.𝑈2 = ⦋ 
𝐷
g(
γs
γ−1
)
 ⦌
1
2 ⦋ 
τo
(γs−γ)𝐷
 ⦌3/2 
gs 0,05.2,65. (0,94)2 = ⦋ 
1,081𝑥 10−𝟎𝟒
9,8(
2,65
1−1
)
 ⦌
1
2 ⦋ 
1,24 𝑥 10−𝟑
(2,65−1)1,081𝑥 10−𝟎𝟒
 ⦌3/2 
gs 𝟓, 𝟓𝟒𝟖𝒙𝟏𝟎−𝟑

Qt= gs.B.86400/1000 
Qt= 5,548 𝑥 10−𝟑.70,10.86400/1000 
Qt = 33,602 ton/dia 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
- Método de Yang (1973) 
 
U* = (9,81* Rh* S)0,5= 0,11 m/s 
 
 
Eq. (2.37) 
 
 
 W = 
1 
(s - 1).g.D
2 
 18  
 
 W = 
1 
(2,65 - 1).9,8.(7,55x10 -05)2 
 18 8,23121x10
-07 
 
 
 W = 6,22 x 10-17 m/s 
 
 
 
Eq. (2.36) 
 
W =⦋ 2/3.g.(s.D3+36.() 2⦌1/2 -6.  
 
W =⦋ 2/3.9,8.(2,65/1-1).(1,065x10-04)3+36(8,23121x10-07)2⦌1/2- 6(8,23121x10 -07) 
 1,065x10-04 
W = 1,10 x 10-10 
 
W =⦋ 2/3.9,8.(2,65/1-1).(1,5x10-04)3+36(8,23121x10 -07)2⦌1/2- 6(8,23121x10 -07) 
 1,5x10-04 
W = 1,90 x 10-10 
D. inferior D.superior D. médio W UC/W CT % CT. % 
6,3x10-05 8,8x10-05 7,55x10-05 6,22 x 10-17 9,7 2,307 0,17 0,39219 
8,8x10-04 1,25x10-04 1,065x10-04 1,10 x 10-10 13,64 1,247 0,58 0,72326 
1,25x10-04 1,75x10-04 1,5x10-04 1,90 x 10-10 19,22 7,67 0,20 1,534 
1,75x10-04 2,5x10-04 2,125x10-04 2,99 x 10-10 27,23 5,62 0,05 0,281 
 
 
W =⦋ 2/3.9,8.(2,65/1-1).(2,125x10-04)3+36(8,23121x10-07)2⦌1/2- 6(8,23121x10 -07) 
 2,125x10-04 
W =2,99 x 10-10 
 
Cálculo da velocidade crítica Uc que depende do fator U*. D/ ν 
Quando: 1,2 < U* .D/ ν < 70 
 
Então: Uc/W= 2,5/[log (U*.D/ν) -0,06] +0,66 
 
 Uc= W. {2,5/[log (U*.D/ν) -0,06] +0,66} 
Caculos: 
U*. D = 0,11. 7,55x10-05= 1,00x10-13 
 ν 8,23121x10-07 
 Uc = 6,22 x 10-03. {2,5/[log (1,00x10 -13) -0,06] +0,66} 
Uc = 9,7 
 
U*. D = 0,11. 1,065x10 -05= 1,42x10-13 
 ν 8,23121x10-07 
Uc = 1,10 x 10-10. {2,5/[log (1,42x10-13) -0,06] +0,66} 
Uc = 13,64 
 
U*. D = 0,11. 1,5x10 -04= 2,00x10 -13 
 ν 8,23121x10-07 
 Uc =1,90 x 10-10. {2,5/[log (2,00x10-13) -0,06] +0,66} 
Uc = 19,22 
U*. D = 0,11. 2,125x10-04 = 2,83x10-13 
 ν 8,23121x10-07 
 Uc =2,99 x 10-10. {2,5/[log (2,83x10-13) -0,06] +0,66} 
Uc = 27,23 
Cálculo da concentração total em ppm: 
 
log CT= 5,435 – 0,286. log (W.D/ν) – 0,457. log (U*/W) + [(1,799-0,409.log 
(W.D/ν) – 0,314.log (U*/W)]. log (U. S/ W – Uc.S/W) 
log CT= 5,435- 0,286. log (6,22 x 10-17. 7,55x10-05 / 8,23121x10-07) - 0,457. log (0,11/6,22x 
10-17) + [(1,799-0,409.log(6,22 x 10-17. 7,55x10-05 / 8,23121x10-07) – 0,314.log (0,11/6,22x 
10-17) ]. log (0,94. 0,0005998/6,22 x 10-17 – 9,7.0,0005998/6,22 x 10-17) 
CT= 2,307 
log CT= 5,435- 0,286. log (1,10 x 10-10. 1,065x10-04 / 8,23121x10-07) - 0,457. log (0,11/1,10 x 
10-10) + [(1,799-0,409.log(1,10 x 10-10. 1,065x10-04 / 8,23121x10-07) – 0,314.log (0,11/1,10 x 
10-10) ]. log (0,94. 0,0005998/1,10 x 10-10 – 13,64.0,0005998/1,10 x 10-10) 
CT= 1,247 
log CT= 5,435- 0,286. log (1,90 x 10-10. 1,5x10-04 / 8,23121x10 -07) - 0,457. log (0,11/1,90 x 
10-10) + [(1,799-0,409.log(1,90 x 10-10. 1,5x10-04 / 8,23121x10 -07) – 0,314.log (0,11/1,90 x 10-
10) ]. log (0,94. 0,0005998/ 1,90 x 10-10 – 19,22.0,0005998/1,90 x 10-10) 
CT= 7,67 
log CT= 5,435- 0,286. log (2,99 x 10-10. 2,125x10-04 / 8,23121x10-07) - 0,457. log (0,11/2,99 x 
10-10) + [(1,799-0,409.log(2,99 x 10-10. 2,125x10-04 / 8,23121x10-07) – 0,314.log (0,11/2,99 x 
10-10) ]. log (0,94. 0,0005998/2,99 x 10-10 – 27,23.0,0005998/2,99 x 10-10) 
CT= 5,62 
 
Qt= 0,0864. Q. CT 
Qt= 0,0864. 139,35.1,010 
Qt= 12,160 
 
g..D50  
 - Método de Karim (1998) 
 
 

W  


 

 


W  9,8.1,65.1,081x10-04 


 
W = 0,011 m/s 
 
 2,97 1,47 
qs /√𝒈.. 𝑫
3 = 0,00139 (V/√𝒈. . 𝑫) . ( U* / W) 
 
 
 0,94 2,97 1,47 
qs /√9,8.1,65. (1,081x1004)3 = 0,00139 (√9,8.1,65.1,081x1004) . ( 0,11 / 0,011) 
 
qs = 0,0018 
 
 
 
 
Qt= qs * 2,65 * 86400 * B 
 
Qt= 0,0018 * 2,65 * 86400 * 7,10 
 
Qt = 2.926,10 ton/dia 
 
 
 
 
 
 
 
 
 
 
 2  
362 
3 g. .D 3 
50 
 
g..D 3 
50 

 
 9,8.1,65.(1,081x 

 
 3 9,8.1,65.(1,081x 
1,081x 1,1,65.9,8.(1,081x 
 

D
50 .g.D50 
 
 
 - Método de Cheng (2002) 
 
 
 
 
 
 
 
 u 
 = 
.g.D50
 
 
g.d.s)1/2 
1,65.9,8.1,081x10-04 
 
 

 
 


  
qb 
 
 
  
 
 
 
 
238,1
 
 
 
 
qb =0,001m³/s 
 
 
 
 
 


exp 0,05 
 

 


exp 0,05 
 
 
 
Qt= qb*B*86400*2,65 
Qt = 0,001.70,10.86400.2,65 
Qt = 16.050,09 ton/dia