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Gabarito da 6a ¯ Lista de Ca´lculo Diferencial e Integral I IBM / 2010 Exerc´ıcio 1. a)f ′(x) = 6x b)f ′(x) = 3x2 + 2x c)f ′(x) = 2x d)f ′(x) = 3 + 1 2 √ x e)f ′(x) = −6 x3 f)f ′(x) = 2 3 3 √ x2 g)f ′(x) = 3− 1 x2 h)f ′(x) = − 4 x2 − 10 x3 i)f ′(x) = 2x2 + x 2 j)f ′(x) = 1 3 3 √ x2 + 1 2 √ x k)f ′(x) = 2− 1 x2 − 2 x3 l)f ′(x) = 18x2 + 1 3 3 √ x2 Exerc´ıcio 2. a) f ′(x) > 0 se x ∈ (−∞,−2)∪ (0,∞), f ′(x) < 0 se x ∈ (−2, 0). b) lim x→+∞ f(x) =∞ e lim x→−∞ f(x) = −∞. Exerc´ıcio 3. a)f ′(x) = −x2 + 1 (x2 + 1)2 b)f ′(x) = 1 c)f ′(x) = 15x2 − 18x− 15 (5x− 3)2 d)f ′(x) = −x+ 1 2 √ x(x+ 1)2 e)f ′(x) = 5− 1 (x− 1)2 f)f ′(x) = 1 2 √ x − 9x 2 (x3 + 2)2 Exerc´ıcio 4. a) ±1. b) g′(x) < 0, se |x| > 1 e g′(x) > 0, se |x| < 1. c) lim x→+∞ g(x) = 0 e lim x→−∞ g(x) = 0. Exerc´ıcio 5. a)f ′(x) = 6x− 5senx b)f ′(x) = −senx(x 2 + 1)− 2xcosx (x2 + 1)2 c)f ′(x) = senx+ xcosx d)f ′(x) = 2xtgx+ x2sec2x e)f ′(x) = tgx+ sec2x(x+ 1) tg2x f)f ′(x) = 3(senx− cosx) (senx+ cosx)2 g)f ′(x) = secxtgx(3x+ 2)− 3secx (3x+ 2)2 h)f ′(x) = −senx+ 2xsenx+ (x2 + 1)cosx i)f ′(x) == secx+ 2xsecxtgx 2 √ x j)f ′(x) == −senx− cosx(x2 + x) x2sen2x k)f ′(x) = 2x+ 3tgx+ 3xsec2x l)f ′(x) = −1 + cosx(x− 1)− senx(x+ 1) (x− cosx)2 1 Exerc´ıcio 6. Calcule f ′(x): a)f ′(x) = 4cos4x b)f ′(x) = −5sen5x c)f ′(x) = 3x2cosx3 d)f ′(x) = 3(senx+ cosx)2(cosx− senx) e)f ′(x) = 3 2 √ 3x+ 1 f)f ′(x) = 1 3 3 √ ( x+ 1 x− 1) 2 2 (x+ 1)2 g)f ′(x) = −cos(cosx)senx h)f ′(x) = 8x(x2 + 3)3 i)f ′(x) = −2xsen(x2 + 3) j)f ′(x) = 3sec2(3x) k)f ′(x) = 3sec(3x)tg(3x) l)f ′(x) = 2xsen2xcos2x− sen(2x)sen(x2) sen4x Exerc´ıcio 7. 1)f ′(x) = −2 (x− 1)2 2)f ′(x) = 4x3 + 12x2 − 1 (x+ 2)2 3)f ′(x) = −x6 − 16x3 + 8 (x3 + 2)2 4)f ′(x) = sen( √ x5 − x2) + x(5 2 √ x3 − 2x)cos( √ x5 − x2) 5)f ′(x) = (x4 + tg2x+ 1)(2/3cos x− xsen x)− 4xcos x(2x3 + tg xsec2x) 3 √ x(x4 + tg2x+ 1)3 6)f ′(x) = tg2x+ 2xtgxsec2x 2 √ xtg2x 7)f ′(x) = (1− 2√xcossec xcotg x)(x3 + 3x2)− (2x+ 2√xcossec x)(3x2 + 6x) 2 √ x(x3 + 3x2)2 8)f ′(x) = xsec √ x2 + 1tg √ x2 + 1√ x2 + 1 9)f ′(x) = 2xtg x+ x2sec2x− x2tg2x sec x 10)f ′(x) = sen(2x) 2 + xcos(2x) 11)f ′(x) = (x+ 2)3(64− 8x3) (x4 + 16)2 12)f ′(x) = (cosx− 1)cos(x− senx) (sen(x− sen x))2 13)f ′(x) = 4 3 3 √ x+ √ x ( 3 √ x+ √ x)2 14)f ′(x) = −6xcosse2(3x2 + 5) 15)f ′(x) = xsen(2x)− x2cos(2x) (sen xcos x)2 16)f ′(x) = (x4 + 3x2)tg x+ (2x5 + 2x3)tg2x+ (x5 + x3)sec2x (x2 + 1)2cos2x 2 17)f ′(x) = −3cotg2(x)− 3cotg4(x) 18)f ′(x) = −2sen x(x2 + x+ 1)− 2cos x(2x+ 1) (x2 + x+ 1)2 19)f ′(x) = 2x√ 1− x4 20)f ′(x) = 2arcsen x√ 1− x2 21)f ′(x) = −2xarctg x+ 1− x 2 1 + x2 22)f ′(x) = arccos x 23)f ′(x) = −sen(ln(x) x 24)f ′(x) = 1 2x 25)f ′(x) = −x 1 + x 26)f ′(x) = 1− x+ xln x x(1− x)2 27)f ′(x) = e √ x 2 √ x 28)f ′(x) = excos(ex) 29)f ′(x) = ex√ 1− e2x 30)f ′(x) = 1 (1 + x2)arctg x 31)f ′(x) = −2 x3 (e1/x 2 + 1) 32)f ′(x) = ex ex + 1 33)f ′(x) = −3x2sen(x3)ecos(x3) 3
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