343189964-solution-manual-power-electronics-1st-edition-hart-doc (1)
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343189964-solution-manual-power-electronics-1st-edition-hart-doc (1)


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Full file at http://testbank360.eu/solution-manual-power-electronics-1st-edition-hart
CHAPTER 2 SOLUTIONS
2/21/10
2-1) Square waves and triangular waves for voltage and current are two examples.
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2-2) a)
       
2 2
2
[170 sin 377 ] 2890 sin 377 .
10
v t t
p t v t i t t W
R
 
b) peak power = 2890 W.
c) P = 2890/2 = 1445 W.
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2-3)
v(t) = 5sin2πt V.
a) 4sin2πt A.; p(t) = v(t)i(t) = 20 sin22πt W.; P = 10 W.
b) 3sin4πt A.; p(t) = 15sin(2πt)sin(4πt) W.; P = 0
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2-4) a)
     
0 0 50
40 50 70
0 70 100
t ms
p t v t i t ms t ms
ms t ms
 
 
 
b)
   
70
0 50
1 1 40 8.0 .
100
ms
T
ms
P v t i t dt dt W
T ms
 
 
c)
 
70
0 50
40 800 .; 8 100 800 .
ms
T
ms
W p t dt dt mJ or W PT W ms mJ  
 
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2-5) a)
     
70 . 0 6
50 . 6 10
40 . 10 14
0 14 20
W t ms
W ms t ms
p t v t i t W ms t ms
ms t ms
 
 
 
 
b)
 
6 10 14
0 0 6 10
1 1 70 50 40 19 .
20
ms ms ms
T
ms ms
P p t dt dt dt dt W
T ms
 
 
 
 
 
 
c)
Full file at http://testbank360.eu/solution-manual-power-electronics-1st-edition-hart
 
 
6 10 14
0 0 6 10
70 50 40 0.38 .;
19 20 380 .
ms ms ms
T
ms ms
W p t dt dt dt dt J
or W PT ms mJ
 
 
 
 
 
 
 
_____________________________________________________________________________________
2-6)
 
 
) 2 ., 12 2 24 .
) 3.1 ., 12 3.1 37.2 .
dc avg
avg
avg
P V I
a I A P W
b I A P W
 
 
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2-7)
a)
b)
     
       
 
3
0
10 10 377 1 .0 cos 377 3.77 cos 377 .
3.77 1.0
3.77 cos 377 1.0 sin 377 sin 754 1.89 sin 754 .
2
10
L
L
T
L
di t
v t L t t V
dt
p t v t i t t t t t W
P p t dt
T
 
 
 
c)
     
 
0
12 1.0 sin 377 12 sin 377 .
10
T
dc
p t v t i t t t W
P p t dt
T
 
 
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Full file at http://testbank360.eu/solution-manual-power-electronics-1st-edition-hart
2-8) Resistor:
   
     
 
2
1/ 60 1/ 60 1/ 60
2
0 0 0 0
8 24 sin 2 60 .
8 24 sin 2 6 0 2 6 sin 2 60
16 96 sin 2 60 144 sin 2 60 .
1 1 16 96 sin 2 60 144 sin 2 60
1 / 60
16 72 88 .
T
v t i t R t V
p t v t i t t t
t t W
P p t dt dt t dt t
T
W
 
 
 
 
 
 
 
 
 
 
 
 
Inductor:
0.
L
P
dc source:
 
2 6 12 .
dc avg dc
P I V W 
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2-9) a) With the heater on,
 
 
 
 
 
2 2 2
1500 2
1500 . 12.5 2
2120 2
sin 120 2 12.5 2 sin 3000 sin
max 3000 .
m m
m
m m
V I
P W I
p t V I t t t
p t W
 
 
 
b) P = 1500(5/12) = 625 W.
c) W = PT = (625 W)(12 s) = 7500 J. (or 1500(5) = 7500 W.)
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2-10)
   
   
0
3
1 1 90 900 0 4 .
0.1
4 900 4 10 3.6 .
t
L L
L
i t v t dt d t t ms
L
i ms A
 
 
 
a)
 
2
2
1 1 0. 1 3.6 0.648 .
2 2
W Li J 
b) All stored energy is absorbed by R: WR = 0.648 J.
c)
0.648 16.2 .
40
16.2 .
R
R
S R
W
P W
T ms
P P W
 
 
d) No change in power supplied by the source: 16.2 W.
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