@import url(https://fonts.googleapis.com/css?family=Source+Sans+Pro:300,400,600,700); Questão 62- Os quatro primeiros termos da sequência definida por \ufeffan=(\u22121)n\u22c5n+1a_n=(-1)^n\cdot n +1an\u200b=(\u22121)n\u22c5n+1\ufeff , \ufeffn\u2208N\u2217n \in \mathbb{N}^*n\u2208N\u2217\ufeff são tais que a) formam uma PA de razão 4 b) formam uma PG de razão 2 c) \ufeffa1+a3a_1 + a_3 a1\u200b+a3\u200b\ufeff = \ufeffa2+a4a_2 + a_4 a2\u200b+a4\u200b\ufeff d) \ufeffa1+a2a_1 + a_2 a1\u200b+a2\u200b\ufeff = \ufeffa3+a4a_3 + a_4a3\u200b+a4\u200b\ufeff RESOLUÇÃOFala galera, para resolvermos essa questão precisamos identificar os quatro primeiros termos dessa sequencia \ufeffa1=(\u22121)1\u22c51+1=0a_1=(-1)^1\cdot 1 +1=0a1\u200b=(\u22121)1\u22c51+1=0\ufeff \ufeffa2=(\u22121)2\u22c52+1=3a_2=(-1)^2\cdot 2+1=3a2\u200b=(\u22121)2\u22c52+1=3\ufeff \ufeffa3=(\u22121)3\u22c53+1=\u22122a_3=(-1)^3\cdot 3+1=-2a3\u200b=(\u22121)3\u22c53+1=\u22122\ufeff \ufeffa4=(\u22121)4\u22c54+1=5a_4=(-1)^4\cdot 4 +1= 5a4\u200b=(\u22121)4\u22c54+1=5\ufeff GABARITO LETRA: (D) Qualquer duvida, meu instagram @carol.1111
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