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ESCUELA SUPERIOR POLITÉCNICA DE CHIMBORAZO PRIMER SEMESTRE PARALELO ¨B¨ ANÁLISIS MATEMÁTICO ASQUI VACA, BORIS JOSUE → 𝐬𝐢𝐧 𝒙 = √1 − cos2 𝑥 sin2 𝑥 + cos2 𝑥 = 1 → 𝑦′ = −2 cos 𝑥 ∗ (− sin 𝑥) 2√1 − cos2 𝑥 → 𝑦′ = 2 cos 𝑥 ∗ sin 𝑥 2√1 − cos2 𝑥 → 𝑦′ = cos 𝑥 ∗ sin 𝑥 √sin2 𝑥 → 𝑦′ = cos 𝑥 ∗ sin 𝑥 sin 𝑥 → 𝑦′ = cos 𝑥 → cos 𝑥 = √1 − sin2 𝑥 sin2 𝑥 + cos2 𝑥 = 1 → 𝑦′ = −2 sin 𝑥 ∗ cos 𝑥 2√1 − sin2 𝑥 → 𝑦′ = −2 sin 𝑥 ∗ cos 𝑥 2√cos2 𝑥 →→ 𝑦′ = − sin 𝑥 ∗ cos 𝑥 cos 𝑥 −→ 𝑦′ = − sin 𝑥 → tan 𝑥 = sin 𝑥 cos 𝑥 → 𝑦′ = cos 𝑥 ∗ cos 𝑥 − (− sin 𝑥 ∗ sin 𝑥) cos2 𝑥 → 𝑦′ = cos2 𝑥 + sin2 𝑥 cos2 𝑥 → 𝑦′ = 1 cos2 𝑥 → 𝑦′ = sec2 𝑥 → cot 𝑥 = cos 𝑥 sin 𝑥 → 𝑦′ = − sin 𝑥 ∗ sin 𝑥 − cos 𝑥 ∗ cos 𝑥 sin2 𝑥 → 𝑦′ = −(sin2 𝑥 + cos2 𝑥) sin2 𝑥 → 𝑦′ = −1 sin2 𝑥 → 𝑦′ = − csc2 𝑥 → sec 𝑥 = 1 cos 𝑥 = (cos 𝑥)−1 𝑦′ → −1(cos 𝑥)−2(− sin 𝑥) → 𝑦′ = sin 𝑥 cos 𝑥 ∗ 1 cos 𝑥 → 𝑦′ = tan 𝑥 ∗ sec 𝑥 → csc 𝑥 = 1 sin 𝑥 = (sin 𝑥)−1 → 𝑦′ = −1(sin 𝑥)−2(cos 𝑥) → 𝑦′ = − cos 𝑥 sin 𝑥 ∗ 1 sin 𝑥 → 𝑦′ = − cot 𝑥 ∗ csc 𝑥 FUNCIONES TRIGONOMÉTRICAS INVERSAS 𝑦 = sin 𝑥 𝑥 = sin 𝑦 → 1 = cos 𝑦 ∗ 𝑦′ → 𝑦′ = 1 cos 𝑦 → cos2 𝑦 + sin2 𝑦 = 1 → cos 𝑦 = √1 − sin2 𝑦 → 𝑦′ = 1 √1 − sin2 𝑦 → 𝑦′ = 1 √1 − 𝑥2 𝑦 = cos 𝑥 → 𝑥 = cos 𝑦 → 1 = − sin 𝑦 ∗ 𝑦′ → 𝑦′ = −1 sin 𝑦 → cos2 𝑦 + sin2 𝑦 = 1 → sin 𝑦 = √1 − cos2 𝑦 → 𝑦′ = −1 √1 − cos2 𝑦 → 𝑦′ = −1 √1 − 𝑥2 𝑦 = tan 𝑥 𝑥 = tan 𝑦 → 1 = sec2 𝑦 ∗ 𝑦′ → 𝑦′ = 1 sec2 𝑦 → 1 + tan2 𝑦 = sec2 𝑦 → 𝑦′ = 1 1 + tan2 𝑦 → 𝑦′ = 1 1 + 𝑥2 → 𝑦 = cot 𝑥 → 𝑥 = cot 𝑦 → 1 = − csc2 𝑦 ∗ 𝑦′ → 𝑦′ = −1 csc2 𝑦 → 1 + cot2 𝑦 = csc2 𝑦 → 𝑦′ = −1 1 + cot2 𝑦 → 𝑦′ = −1 1 + 𝑥2 → 𝑦 = sec 𝑥 → 𝑥 = sec 𝑦 → 1 + tan2 𝑦 = sec2 𝑦 → tan 𝑦 = √sec2 𝑦 − 1 → 1 = sec 𝑦 ∗ tan 𝑦 ∗ 𝑦′ → 𝑦′ = 1 sec 𝑦 ∗ tan 𝑦 → 𝑦′ = 1 sec 𝑦 ∗ √sec2 𝑦 − 1 → 𝑦′ = 1 𝑥 ∗ √𝑥2 − 1 → 𝑦 = csc 𝑥 → 𝑥 = csc 𝑦 → 1 = − csc 𝑦 ∗ cot 𝑦 ∗ 𝑦′ → 𝑦′ = −1 csc 𝑦 ∗ cot 𝑦 → 1 + cot2 𝑦 = csc2 𝑦 → cot 𝑦 = √csc2 𝑦 − 1 → 𝑦′ = −1 csc 𝑦 ∗ √csc2 𝑦 − 1 → 𝑦′ = −1 𝑥 ∗ √𝑥2 − 1
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