Olá
Faça assim: (3 ⋅ a + 6) ÷ (a² ⋅ x - 4 ⋅ x)
(3 · a + 6) = 3 ⋅ (a + 2)
(a² · x - 4 · x) = x ⋅ (a² - 4) = x ⋅ (a² - 2²) = x ⋅ (a - 2) ⋅ (a + 2)
Então:
(3 ⋅ a + 6) ÷ (a² ⋅ x - 4 ⋅ x)
[3 ⋅ (a + 2)] ÷ [x ⋅ (a - 2) ⋅ (a + 2)]
3 ÷ [x ⋅ (a - 2)]
3 ÷ (a ⋅ x - 2 ⋅ x]
Espero que esteja correto! Bons estudos!
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