Calcule a integral dupla: ∫ 4 2 ∫ 2 1 ( x 2 + y 2 ) dydx

kkk

\int _2^4\int _1^2x^2+y^2dydx

\int _1^2x^2+y^2dy=x^2+\frac{7}{3}

=\int _2^4\left(x^2+\frac{7}{3}\right)dx

\int _2^4\left(x^2+\frac{7}{3}\right)dx=\frac{70}{3}