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-M(As 0 E =E+0 log *e !" E=EP +0.059 log, E ↳04=m TE Iz R Ag(AgCI =0.22V 1é +Aglar ->Agt(Taq ErsAs=0.8V 1log dei R -e * =Gi 1.- Noe role eranparteenI↓ It2dW- As/Age/Be AglAgI/I AglAges/ He/HeeOn/O Hg/HCle/CI- Ig/HgO/NaOH0.1mol - 0.928V Ig/IgrOnkesOncel 0.64 Gonton de Pateriale - 0.SV - 0.SV-0.2360U= Hglgele/kIo-0.337V (EC) 0. SVvs ENH=0.264V ->As Ag(Hecelk(HoN-0.20012 vs ECs Hultgecle/zelester - 0.2412V ->-t I 0.264V Hg/Agete/Nalkard- 0.2360e. AglAgClekorit - 0.197V #in ENH - O 1.34V - +az - 0.5V nent-- ECsWall 064V - ha/hsO/hes 0.197N- Ag/AgCl/kCIrat 0.1 vEs a ENH - (Ecs) - O ENH v - 2.07 ENH-0 MaMg24 E=Ag/AgI/kCl -E =-237 Stechodo.- Aplicantes Astulacionesdoterconities # e Wes fot + lé-fort En(1.4V E =E +0059logfea == Efef=0.77V ↳-C1f-fet lest fe-fot Purante ce* +f fe+ Q =Acost Aft Afort - **= aftRit 1.59U - ** *-fes+ E I* =ActArest Acont 0.77 E = E +0.059 logat Vot Después depuntode equivalencia fort co*-fe+* = 1.595+0.059 log den Vo AceArt Salade el de caday encuentela reaccióndecada una de las siguentesoldas. a) AgclAg(1=0.01112(a ==0.01/zas ↳)pulfo(a= 1), fe(41 =0.111CI(a= =0.0011/Ag(or/Agea 4 zm(y/znO:"(a==0.1). 0H(a==1)(Hg0cr(Hgse a) Agcr(Ag(1 =0.01112(a ==0.01 /zns E=E+ oslog Ei=Ep -EE =Er-kir EU.SV 2Ag -2Agt +1e- (2) Ei= -0.76V-0.5V) E=10.76 Z +2é-Zi Ei= -1.56V 2Ag +Z-2Agt Zi E= -1.56V+59 log E= - 147.1V oe 16 = - nfE 36 = - e (96,500) (- 1.471) Er *=283,999 En ↳)pulfo(a= 1), fe(41 =0.111CI(a= =0.0011/Ag(or/Agea E=E +059 log I -Q R =As Afet UntArc E=0.77 fet-f + 1e Q=fest Aet =ot E =0.22V AgCl+ 1 -Ag +CI -> e? Fe+ AgC) -- Agtfe3 E=_0.55V70.059 log E=ER-=E-kir=Ei-Ei ~ E=-0.491V E =0.220-0.77V=-0.SSU 4 zm(y/znO:"(a==0.1). 0H(a==1)(Hg0cr(Hgse E=1.216V Ze+ 40H-ZP +2120 + 200E= 0.098 HgO +2+ H20--D+20H- Ent HgPt2OH- ZeDeHgtHzO -Q =AznarYno >AsorAze I -Hote EIE -Eiz=0.048U-(-1.2160 E=1.314V E =1514V+59 log E=1.344V Pandionty (umes .1Nor,Miérco 2 UI Propiedades Coligativos. St = jkam ↓(i =2 es Nall-Nat+C 1.7 Para la siguientealda HesOn- 244On P6CAg//P65Oy(HeOn (as0.00m) Helg, later IPt E=0.09589 2 VI =? I = Eaz I=1 [10.002(2 +10,001(2 I=0.003 log UI-- Iz. IzB logUt=-(2/C(0.509 log UI = - 0.558 U= =1- 0.855 UI =0.88 E=0.095892 UI =? ~On + 16-P65Oncer+2é EE-0.356V 3E=OV-(0.956V2H+2-He(g -E16 +2H10-165Onceit Hacg, Ei =0.356V Es =Ed-Er &HeronR=Art Q =(1) 1 =4Gro A Aro Q a =V=C Art=U=(1+ ==10.002/ Aron= U-_Cro-- VI (0.001 -.A Aro E=20 +039 log E =[V10.002][W=10.001) * =V/4X0-* 0.09589V=0.356V+09 logWI (No 210.09989-0.3960) =log (VI1940-] 0.059U - 8.82 = log(VI(nx10- 10-8=VI/4x10- U= VI =0.72 Loof. dact media f - Ibonos detamina UIde mara ebchofrica, Para la celda . - t(uKuClesmerlAgCIlAg I IL * en C+ 2C1- ->C E = 0.191 arando m= 1N0wol Eg E= - 0.74V im=0.2 a ↳-(é 6 Petumins E Ag*Cl+2-2Agt21 4) Peterse UI Cut2AgCIr-(+ 2Ci +2As a Culle I R =Ang'AcoAci 8 = I disc AcuCa a =Ac, 21=1 Baja concentración a = C XP = l La E =E +59 log 0.191= Et 0.059 log 1 2 11x10-4(2x10-4 0.191 =E+0.2362V E=0.191-0.3362V E = - 0.1452V acr=U=10.4 Q = 0).Aci 1 = Acret =UI( ~ a a Ha= WI (0.2 1Ga I = VE 10.2(8x-0.41 I 1 = 1 e Q VI 10.032/ E = -0.14S2V E = - 0.74V E =E1log t - 1.074 v=-0.14522+054 log coser I1-0.07410.1ns2V=109 2110.0920.0592 -2.3 =- log UI(0.032 10 =(10.032/ UI =0.49 Gonetraciónde Piagramas de Pourbaix P ↑ SX T Hierro:fet,fet, felots, feeds, feUn", fe fortlé-f Q= *Zona de estabilidad E =E + 0.059 log fest Xt Linear horizontales. = FoOn2- * Linear Verticales Ello, afest Afeo a E est o.neo acido/base Elf 08 et s: [volubilidad fez03 - 0.4 - - 0.3 - F folOl/z pl Pisolventeeselagua - Las solusiones se consideran ideales y los gases perfectos · =1 c=ap=a - Losiagemusas son realizadosaeso y una paciono 1 bar En una frontan que repars expeciesdisaltar a considera que las concentracios de las especiesson iguales Los potenciales estanreferidos al electrodo nounalde hidroigace -Losespain disuellasestanen concentraciosde 1 a 100 118, indice m Frontera a ItM- ~- -~ - 37 +15 - fo*, Q =t- ↑ E = E +s log I E=0.77V+ logstestdro Fe Foo, E=E+0.0S lo I E "It fets.nwo 9 9aa 0.8 e fot E= -0.44V+089 log UX0= -0.0SO fez03 - 0.4 -0.3 folOl/z F pl Fo(OH) (f FolOHs + 3H +1e- -- fe+3Het Q =Afet Hirzo E =Be-Aro con Dar E=E +134 log E=E0+054 log-Et0.0sloganl-0.054 log dee E =E -0.059/0gre +19) 10.099/ lag Am pH = -log Ant -teE =E-0.059109 Afe-0.18pH E = 1.13 - 0.18,H
