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NPTEL Control Engineering Jan-April 2020 Assignment 1 Solution 1. Consider a system with input x(t) and output y(t) related by y(t) = x2(t) +x(t−3). The system is (a) Causal [Correct] (b) Non causal (c) Time varying (d) None of these Solution: Let us put the value of t in the above equation t = 0, y(0) = x2(0) + x(−3) t = 1, y(1) = x2(1) + x(−2) t = 2, y(2) = x2(2) + x(−1) t = −1, y(−1) = x2(−1) + x(−4) We can observe from the above value of output that the output only depends on the present and past value of input. Hence, the system is causal. It can be easily observed from the above relation that the system is time-invariant. 2. Consider the following statements for a linear system given by y = f(x) with f : Rn → Rn 1. f(x1 + x2) = f(x1) + f(x2) 2. f [x(t+ T )] = f [x(t)] + f [x(T )] 3. f(Kx) = Kf(x) (a) 1, 2 and 3 are correct (b) 1 and 2 are correct (c) 1 and 3 are correct [Correct] (d) Only 2 is correct Solution: Any linear system satisfies the laws of superposition and homogeneity. If an input consists of weighted sum of several signals, then the output is the superposition, that is, the weighted sum of the responses of the system to each of those signals. If y = f(x) and say, y1 = f(x1) and y2 = f(x2), then f [(x1) + (x2)] = f(x1) + f(x2) = y1 + y2 means that the system satisfies the superposition theorem. A system is said to be homogeneous if, any input signal say y = f(x) is multiplied by an arbitrary scalar K i.e., f(Kx), then output f(Kx) = Kf(x), or scaling any input signal scales the output signal by the same factor. 1 3. Consider a system with input x(n) and output y(n) related by y(n) = cosx(n) is the system linear? (a) Yes (b) No [Correct] Solution: A direct consequence of the Superposition property is that, for linear systems, an input which is zero for all time results in an output which is zero for all time. When input x(n) = 0 then the output y(n) = cos 0 = 1. Hence, for zero input, output is 1 which is not equal to zero and hence the given system is nonlinear. 4. Which of the following is/are true about a dynamic system (Note: mutiple correct answer possible) (a) memory elements are present [Correct] (b) no memory elements (c) output depends only on present input (d) output depends on past and present inputs [Correct] Solution: A dynamic system is defined as the system in which the system retains or stores information about input values at times other than the current time. The concept of memory in the system corresponds to the presence of mechanism in the system related to memory. 5. In translational mechanical system, the damping is generally provided by (a) Static friction (b) Coulomb friction (c) Viscous friction [Correct] (d) Spring friction Solution: Viscous friction can be safely used to provide damping in mechanical system. Both static friction as well as coulomb friction is not suitable to be used for the purpose of damping. The reason for static friction is that it is only in existence as long as body is stationary, but as soon as the body starts moving, the static friction vanishes. Coulomb friction has constant magnitude and does not vary with the velocity of the body; therefore, it is not suitable to be used for the purpose or damping. Further, spring friction is not a correct term at all. 6. In order to double the time period of a simple pendulum, the length of the string should be (Hint: The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation) (a) halved (b) doubled (c) quadrupled [Correct] (d) none of the above Solution: Time period of a simple pendulum is given by Tp = √ L g 2 If the length of the string is made four times then the time period will become double, as shown below Tpnew = √ 4L g = 2Tp 7. Consider a simple mass-spring-friction system as shown in the figure, where K1, K2 are spring stiffness‘s, f is friction, M is mass, F is force, and x is displacement. The force acting on the system is given by (a) F = M d 2x dt2 + f dx dt + (K1 +K2)x [Correct] (b) F = M d 2x dt2 + f dx dt + (K1 −K2)x (c) F = M d 2x dt2 + f dx dt + (K1K2)x (d) F = M d 2x dt2 + f dx dt Solution: The mechanical equivalent of the system is shown in the figure below MF 1K 2K x f From the above figure, mechanical equation of given system is F = M d2x dt2 + f dx dt +K1x+K2x F = M d2x dt2 + f dx dt + (K1 +K2)x 8. For the given rotational system consisting of motor coupled to an inertial load through a shaft with spring constant K, the motor torque acting on the load is given by 3 (a) T (t) = J d 2θ(t) dt2 +B dθ(t) dt (b) T (t) = J d 2θ(t) dt2 +B dθ(t) dt +Kθ(t) [Correct] (c) T (t) = J d 2θ(t) dt2 +B dθ(t) dt + θ(t) (d) T (t) = J dθ(t)dt +B dθ(t) dt + θ(t) Solution: The mechanical equivalent of the system is shown in the figure below JT K θ B From the above figure, mechanical equation of given system is T (t) = J d2θ(t) dt2 +B dθ(t) dt +Kθ(t) 9. The input is vi(t) and output is v0(t). Which of the following equation correctly describe the dynamics of the electrical circuit shown below is 4 (a) vi(t) = R di(t) dt + L d2i(t) dt2 + 1 C i(t); vo(t) = 1 C ∫ i(t)dt (b) vi = Ri(t) + 1 C ∫ i(t)dt; vo(t) = 1 C ∫ i(t)dt+ Ldi(t)dt (c) v0(t) = Ri(t) + L di(t) dt + 1 C ∫ i(t)dt; vo(t) = 1 C ∫ i(t)dt (d) vi(t) = Ri(t) + L di(t) dt + 1 C ∫ i(t)dt; vo(t) = 1 C ∫ i(t)dt [Correct] Solution: Applying KVL to loop, we get vi(t) = Ri(t) + L di(t) dt + 1 C ∫ i(t)dt vo(t) = 1 C ∫ i(t)dt 5
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