Buscar

SIGNALS BASICS (PART 2)

Prévia do material em texto

UNIVERSIDAD YACHAY TECH
SCHOOL OF BIOLOGICAL SCIENCES AND ENGINEERING
BIOMEDICAL ENGINEERING
SIGNAL THEORY AND MEDICAL BIOCOMPUTATION
HIGHER MATHEMATICS FOR ENGINEERING
Ing. Diego Almeida Ph.D
June
2022
01
CLASS 08: SIGNALS BASICS (PART 2)
03
Basic signals in discrete 
time
Energy signals and power 
signals
Solving Task II
03
BASIC SIGNALS IN DISCRETE TIME
The unit impulse function, δ[n], also known as the Kronecker delta function, is
defined as:
01 02 03 04 05
Unit impulse function in discrete time :
𝜹 𝒏 = ቊ
1 𝑛 = 0
0 𝑛 ≠ 0
04
01
Remember: Delta de Dirac in continuous time:
Other cases
Area
• Parameterized function:
න
−∞
∞
𝜹(𝒕) = ቊ
1 𝑡 = 0
0 𝑡 ≠ 0
05
01
Unit impulse function in discrete time:
Meets the following properties:
06
01
Unit step function in discrete time:
The unit step function, u[n], is defined as:
𝓾 𝒏 = ቊ
1 𝑛 ≥ 0
0 𝑛 < 0
07
01
Decomposition of a discrete signal:
Suppose the signal x [n] given in the figure. We can decompose it as:
x 𝒏 = σ𝒌=−∞
∞ 𝒙 𝒌 𝜹 𝒏 − 𝒌
08
ENERGY SIGNALS AND POWER SIGNALS:
01 02 03 04 05
Energy Signal:
The energy (E) of a signal x (t) is defined as:
The signal x(t) is a finite energy signal (or simply energy signal) if and only if: 
0 < 𝐸𝑋(𝑡) < ∞ → 𝑃 = 0
09
Power signal:
02
The power (P) of a signal x (t) is defined as:
The signal x(t) is a finite energy signal (or simply energy signal) if and only if: 
0 < 𝑃𝑋(𝑡) < ∞ → 𝐸 = ∞
For periodic signals the power can be calculated by integrating the signal into a period:
010
Important notes:
• The signal x(t) that does not satisfy either of the two relationships is neither of finite
energy nor of finite power. Therefore, it is not a power or energy signal.
0 < 𝐸𝑋(𝑡) < ∞
0 < 𝑃𝑋(𝑡) < ∞
• Periodic signals are power signals.
• The unit step is a power signal (its energy is infinite).
• The unit impulse is an energy signal (its average power is 0).
• The increasing exponential signal is a signal with infinite power and energy.
• Finite signals are energy signals
02
011
Summary:
02
Continuous time Discrete time
Energy in a time interval: 
Energy in a time interval: 
Power in a time interval: 
Total energy of a signal: 
Total power of a signal: 
Power in a time interval: 
Total energy of a signal: 
Total power of a signal: 𝑁
012
Example 1:
Determine whether or not each the following signals is power or energy signals:
02
T
• Periodic signal. Period T=4
𝟎 < 𝑷𝑿(𝒕) < ∞ → Power signal
𝑷 =
𝟏
𝑻
׬
𝟎
𝑻
𝒙(𝒕) 𝟐𝒅𝒕
𝑃 =
1
𝑇
න
0
1
(−2) 2𝑑𝑡 +
1
𝑇
න
2
3
(2) 2𝑑𝑡
𝑃 =
1
4
0׬
1
4𝑑𝑡 +
1
4
2׬
3
4𝑑𝑡
𝑃 = 1 + 1 = 2
1)
013
Example 2:
02
2)
• Total Energy:
𝟎 < 𝑬𝑿(𝒕) < ∞ → Energy signal
𝑬 = ∞−׬
∞
𝒙(𝒕) 𝟐𝒅𝒕
𝐸 = ׬
0
∞
(2𝑒−𝑡) 2𝑑𝑡
𝐸 = ׬
0
∞
4𝑒−2𝑡𝑑𝑡
𝐸 = 4
4𝑒−2𝑡
−2
∞
0
𝐸 = 4 0 − −
1
2
= 2
𝑃 = lim
𝑇→∞
1
𝑇
𝐸 = 0
014
TASK II – SIGNALS AND NOISE:
01 02 03 04 05
Determine is the signal are analog, digital, continuous and discrete 
in time? :
015
Solving task II:
03
Determine is the signal are analog, digital, continuous and discrete 
in time? :
Continuous signal in time - Analog signal. Discrete signal in time - Digital signal.
016
Solving task II: 
03
Determine whether or not each the following signals is periodic 
through using fundamental period:
a) 𝑥(𝑡) = cos(𝑤𝑜𝑡)
017
Solving task II: 
03
Determine whether or not each the following signals is periodic 
through using fundamental period:
a) 𝑥(𝑡) = cos(𝑤𝑜𝑡)
−
018
Solving task II: 
03
Determine whether or not each the following signals is periodic 
through using fundamental period:
b) 𝑥(𝑡) = 𝒆𝑗𝒘𝒐𝑡, use hint: 𝒆𝑗𝒘𝒐𝑡 = cos(𝑤𝑜𝑡) + 𝑗 sin(𝑤𝑜𝑡))
019
Solving task II: 
03
Determine whether or not each the following signals is periodic 
through using fundamental period:
b) 𝑥(𝑡) = 𝒆𝑗𝒘𝒐𝑡, use hint: 𝒆𝑗𝒘𝒐𝑡 = cos(𝑤𝑜𝑡) + 𝑗 sin(𝑤𝑜𝑡))
020
03
Solving task II: 
Determine whether or not each the following signals is periodic 
through using fundamental period:
c) (𝑡) = cos (𝑡 + π/4)
021
03
Solving task II: 
Determine whether or not each the following signals is periodic 
through using fundamental period:
c) (𝑡) = cos (𝑡 + π/4)
−
022
03
Solving task II: 
Determine whether the signal is periodic or aperiodic signal?
a. 𝑥(𝑡) = 𝑠𝑖𝑛 ( 
𝟐𝝅
𝟑
𝑡) 
023
03
𝑻𝟏
𝑻𝟐
=
𝒎
𝒏
→ 𝑻 = 𝑻𝟏 ∗ 𝒏 = 𝑻𝟐 ∗ 𝒎 𝒎,𝒏 ∈ 𝒁
Solving task II: 
Determine whether the signal is periodic or aperiodic signal?
b. 𝑥(𝑡) = cos ( 
𝝅
𝟑
𝑡) + sin ( 
𝝅
𝟒
𝑡) 
024
03
𝑻𝟏
𝑻𝟐
=
𝒎
𝒏
→ 𝑻 = 𝑻𝟏 ∗ 𝒏 = 𝑻𝟐 ∗ 𝒎 𝒎,𝒏 ∈ 𝒁
𝑿𝟏 𝒕 = sin
𝝅
𝟑
𝑡 → 𝑻𝟏 =
𝟐𝝅
𝝎𝒐
= 𝟔
𝑿𝟐 𝒕 = sin
𝝅
𝟒
𝑡 → 𝑻𝟐 =
𝟐𝝅
𝝎𝒐
= 𝟖
𝑿 𝒕 = 𝑿𝟏 𝒕 + 𝑿𝟐 𝒕 →
𝑻𝟏
𝑻𝟐
=
𝟔
𝟖
=
𝟑
𝟒
𝑋 𝑡 is periodic → 𝑇 = 𝑇1 ∗ 4 = 𝑇2 ∗ 3 = 24
Solving task II: 
Determine whether the signal is periodic or aperiodic signal?
b. 𝑥(𝑡) = cos ( 
𝝅
𝟑
𝑡) + sin ( 
𝝅
𝟒
𝑡) 
025
03
Solving task II: 
Given the signal x(t) shown in Figure, obtain: a) x(t + 1); 
b) x(-t + 1); and c) x(3/2 t).
026
03
Solving task II: 
Given the signal x(t) shown in Figure, obtain: a) x(t + 1); 
b) x(-t + 1); and c) x(3/2 t).
a. x(t + 1): 
b. x(-t + 1):
c. x(3/2 t):
027
Solving task II (power and energy signals):
01 02 03 04 05
Determine whether or not each the following signals is power, 
energy or neither:
a) 𝑥(𝑡) = 𝑒−𝑎𝑡 𝑢(𝑡) 
028
04
Solving task II (power and energy signals):
Determine whether or not each the following signals is power, 
energy or neither:
a) 𝑥(𝑡) = 𝑒−𝑎𝑡 𝑢(𝑡) • Total Energy:
𝟎 < 𝑬𝑿(𝒕) < ∞ → Energy signal
𝑬 = ∞−׬
∞
𝒙(𝒕) 𝟐𝒅𝒕
𝐸 = 0׬
∞
(𝑒−𝑎𝑡) 2𝑑𝑡
𝐸 = 0׬
∞
𝑒−2𝑎𝑡𝑑𝑡
𝐸 =
𝑒−2𝑎𝑡
−2𝑎
∞
0
𝐸 = 0 − −
1
2𝑎
=
1
2𝑎
𝑃 = lim
𝑇→∞
1
𝑇
𝐸 = 0
Muchas gracias
Diego Almeida

Continue navegando