<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg1.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls2 ws6">01)No <span class="blank _0"> </span>circuito <span class="blank _0"> </span>abaixo, <span class="blank _0"> </span>tod<span class="blank _1"> </span>as <span class="blank _0"> </span>as <span class="blank _2"> </span>lâmpadas <span class="blank _0"> </span>são <span class="blank _0"> </span>iguais <span class="blank _2"> </span>e <span class="blank _0"> </span>circula <span class="blank _0"> </span>uma <span class="blank _2"> </span>corrente <span class="blank _0"> </span>de <span class="blank _0"> </span>2A <span class="blank _0"> </span>quando <span class="blank _2"> </span>a <span class="blank _0"> </span>chave <span class="blank _0"> </span>es<span class="blank _1"> </span>tá </div><div class="t m0 x2 h2 y3 ff1 fs0 fc0 sc0 ls2 ws6">aberta. </div><div class="t m0 x2 h2 y4 ff1 fs0 fc0 sc0 ls2 ws6"> <span class="blank _3"> </span> </div><div class="t m0 x2 h2 y5 ff1 fs0 fc0 sc0 ls2 ws6">Com a chave fechada<span class="blank _4"></span>, pode-se afirmar que a potência elétrica dis<span class="blank _1"> </span>sipada em cada lâmpada<span class="blank _4"></span> vale:<span class="blank _1"> </span> </div><div class="t m0 x3 h3 y6 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws1">12W<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y7 ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws1">24W<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y8 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls4 ws1">36W<span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y9 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws1">48W<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 ya ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws1">64W<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x2 h2 yb ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yc ff1 fs0 fc0 sc0 ls2 ws6">02) C<span class="blank _4"></span>om relação ao conteúdo de eletricidade, correlacione os elementos que podem es<span class="blank _1"> </span>tar presentes em </div><div class="t m0 x2 h2 yd ff1 fs0 fc0 sc0 ls2 ws6">um circuito às suas definições, assinalando, a seguir, a opção<span class="blank _4"></span> c<span class="blank _1"> </span>orreta.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 ye ff1 fs0 fc0 sc0 ls2 ws6">ELE<span class="blank _1"> </span>MENT<span class="blank _4"></span>OS </div><div class="t m0 x2 h2 yf ff1 fs0 fc0 sc0 ls2 ws6">I- Voltímet<span class="blank _4"></span>ro </div><div class="t m0 x2 h2 y10 ff1 fs0 fc0 sc0 ls5 ws3">II<span class="ls2 ws6">- Resistor </span></div><div class="t m0 x2 h2 y11 ff1 fs0 fc0 sc0 ls5 ws3">III<span class="ls2 ws6">- Amperímetro </span></div><div class="t m0 x2 h2 y12 ff1 fs0 fc0 sc0 ls5 ws4">IV<span class="ls2 ws6">- Gerador </span></div><div class="t m0 x2 h2 y13 ff1 fs0 fc0 sc0 ls2 ws6">V- Receptor </div><div class="t m0 x2 h2 y14 ff1 fs0 fc0 sc0 ls6 ws5">VI<span class="ls2 ws6">- Ca<span class="blank _4"></span>pacitor </span></div><div class="t m0 x2 h2 y15 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y16 ff1 fs0 fc0 sc0 ls2 ws6">DEFINIÇÕE<span class="blank _1"> </span>S<span class="blank _4"></span> </div><div class="t m0 x2 h2 y17 ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo que tra<span class="blank _4"></span>nsforma outras formas de energias em energ<span class="blank _1"> </span>ia elétrica.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y18 ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo que tra<span class="blank _4"></span>nsforma energia elétrica em outras formas de energ<span class="blank _1"> </span>ia. </div><div class="t m0 x2 h2 y19 ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo que tra<span class="blank _4"></span>nsforma energia elétrica em energia excl<span class="blank _1"> </span>usivamente térmica. </div><div class="t m0 x2 h2 y1a ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo usado para a<span class="blank _4"></span>rmazenar carga elétrica.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y1b ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo usado para medir a<span class="blank _4"></span> corrente elétrica em um circuito.<span class="blank _0"> </span> </div><div class="t m0 x2 h2 y1c ff1 fs0 fc0 sc0 ls2 ws6">( ) Dispositivo usado para medir a<span class="blank _4"></span> tensão elétrica em um circuito. <span class="blank _1"> </span> </div><div class="t m0 x3 h3 y1d ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">(V<span class="blank _1"> </span>I) (V) (IV) (III) (II)<span class="blank _4"></span> (I) <span class="blank _1"> </span> </span></span></div><div class="t m0 x3 h3 y1e ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">(V<span class="blank _1"> </span>) (IV) (II) (I) (VI) (II<span class="blank _4"></span>I) <span class="blank _1"> </span> </span></span></div><div class="t m0 x3 h3 y1f ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls2">(IV) (V) (II) (VI) (<span class="blank _4"></span>III) (I) </span></span></div><div class="t m0 x3 h3 y20 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">(V<span class="blank _1"> </span>) (VI) (II) (III) <span class="blank _4"></span>(I) (IV) </span></span></div><div class="t m0 x3 h3 y21 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">(IV) (III) (V) (II) (VI) (I) <span class="blank _1"> </span> </span></span></div><div class="t m0 x2 h2 y22 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y23 ff1 fs0 fc0 sc0 ls2 ws6">03) Um aparelho <span class="blank _4"></span>de ar condicionado de uma residência tem potência nominal de 1100W e está li<span class="blank _4"></span>gado a </div><div class="t m0 x2 h2 y24 ff1 fs0 fc0 sc0 ls2 ws6">uma rede elétrica de 2<span class="blank _4"></span>20V. Sabendo que, no verão, ess<span class="blank _1"> </span>e aparelho funciona<span class="blank _4"></span> durante 6 horas por dia, </div><div class="t m0 x2 h2 y25 ff1 fs0 fc0 sc0 ls2 ws6">pode-se dizer que a corrente elétrica que ci<span class="blank _4"></span>rcula pelo aparelho e o s<span class="blank _1"> </span>eu consumo mensal (30 dias) de </div><div class="t m0 x2 h2 y26 ff1 fs0 fc0 sc0 ls2 ws6">energia valem, respectivament<span class="blank _4"></span>e: </div><div class="t m0 x2 h2 y27 ff1 fs0 fc0 sc0 ls2 ws6">a) 5A e 1<span class="blank _4"></span>98 kWh </div><div class="t m0 x2 h2 y28 ff1 fs0 fc0 sc0 ls2 ws6">b) 5A e 18<span class="blank _4"></span>6kWh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y29 ff1 fs0 fc0 sc0 ls2 ws6">c) 5A e 17<span class="blank _4"></span>8kWh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y2a ff1 fs0 fc0 sc0 ls2 ws6">d) 6A e 19<span class="blank _4"></span>8kWh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y2b ff1 fs0 fc0 sc0 ls2 ws6">e) 6A e 186<span class="blank _4"></span> kWh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y2c ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y2d ff1 fs0 fc0 sc0 ls2 ws6">04) Observe a figura abai<span class="blank _4"></span>xo. </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y2e w1 h4" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg2.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2f ff1 fs0 fc0 sc0 ls2 ws6"> <span class="blank _5"> </span> </div><div class="t m0 x2 h2 y30 ff1 fs0 fc0 sc0 ls2 ws6">O esquema acima representa, de modo simplificado, a l<span class="blank _4"></span>igação de um chuveiro elétrico em uma rede de </div><div class="t m0 x2 h2 y31 ff1 fs0 fc0 sc0 ls2 ws6">alimenta<span class="blank _4"></span>ção elétrica doméstica. Supondo que a chave reguladora de temperatura esteja na posição 2 e </div><div class="t m0 x2 h2 y32 ff1 fs0 fc0 sc0 ls2 ws6">usando as informações mostradas, pode-se afirmar que a corrente elétrica que passa pelo disjuntor </div><div class="t m0 x2 h2 y33 ff1 fs0 fc0 sc0 ls2 ws6">vale: </div><div class="t m0 x3 h3 y34 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws7">20A<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y35 ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws7">25A<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y36 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls4 ws7">30A<span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y37 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws7">35A<span class="blank"> </span><span class="ls2 ws6"> </span></span></span></div><div class="t m0 x3 h3 y38 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls4 ws8">40<span class="ls2 ws6">A<span class="blank _1"> </span> </span></span></span></div><div class="t m0 x2 h2 y39 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y3a ff1 fs0 fc0 sc0 ls2 ws6">05) Os geradores de eletricidade são dispositivos capazes de gerar diferença de pot<span class="blank _4"></span>encial elétrico, </div><div class="t m0 x2 h2 y3b ff1 fs0 fc0 sc0 ls2 ws6">convertendo outra<span class="blank _4"></span>s formas de energia em energ<span class="blank _1"> </span>ia elétrica.<span class="blank _4"></span> Ele<span class="blank _1"> </span>s podem ser class<span class="blank _1"> </span>ificados em mecânicos </div><div class="t m0 x2 h2 y3c ff1 fs0 fc0 sc0 ls2 ws6">ou químicos. Sobre os geradores de eletricidade, assinale a <span class="blank _4"></span>opção correta.<span class="blank _0"> </span> </div><div class="t m0 x2 h2 y3d ff1 fs0 fc0 sc0 ls2 ws6">a) O dínamo é um tipo <span class="blank _4"></span>de gerador químico.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y3e ff1 fs0 fc0 sc0 ls2 ws6">b) A bateri<span class="blank _4"></span>a de um automóvel é um tipo de gerador mecânico.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y3f ff1 fs0 fc0 sc0 ls2 ws6">c) As pilhas secas são geradores<span class="blank _1"> </span> químicos. </div><div class="t m0 x2 h2 y40 ff1 fs0 fc0 sc0 ls2 ws6">d) Os geradores químicos funcionam com base no princípio da indução elet<span class="blank _4"></span>romagnética.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y41 ff1 fs0 fc0 sc0 ls2 ws6">e) As lâmpadas fluorescentes são geradores químicos. </div><div class="t m0 x2 h2 y42 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y43 ff1 fs0 fc0 sc0 ls2 ws6">06) Tanto em residências quant<span class="blank _4"></span>o em indústrias e imóveis comerciais existem instrumentos conectados à </div><div class="t m0 x2 h2 y44 ff1 fs0 fc0 sc0 ls2 ws6">rede elétrica responsáveis por efetuar uma medida<span class="blank _4"></span> cujo valor é express<span class="blank _1"> </span>o em quilowatt-hora (Kw.h). A </div><div class="t m0 x2 h2 y45 ff1 fs0 fc0 sc0 ls2 ws6">unidade de medida quil<span class="blank _4"></span>owatt-hora (Kw.h), apesar de não ser o<span class="blank _1"> </span> padrão definido pelo Sistema </div><div class="t m0 x2 h2 y46 ff1 fs0 fc0 sc0 ls2 ws6">Internacional<span class="blank _4"></span> de unidades, pode ser utilizada para medir a:<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y47 ff1 fs0 fc0 sc0 ls2 ws6">a) intensidade l<span class="blank _4"></span>uminosa.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y48 ff1 fs0 fc0 sc0 ls2 ws6">b) quantida<span class="blank _4"></span>de de energia elétrica.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y49 ff1 fs0 fc0 sc0 ls2 ws6">c) potência elét<span class="blank _4"></span>rica. </div><div class="t m0 x2 h2 y4a ff1 fs0 fc0 sc0 ls2 ws6">d) tensão elétri<span class="blank _4"></span>ca.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y4b ff1 fs0 fc0 sc0 ls2 ws6">e) quantida<span class="blank _4"></span>de de carga elétrica.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y4c ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y4d ff1 fs0 fc0 sc0 ls2 ws6">07) C<span class="blank _4"></span>onsidere um dispositivo elétrico cujo valor da resistência elétrica é constante. Estando el<span class="blank _4"></span>e </div><div class="t m0 x2 h2 y4e ff1 fs0 fc0 sc0 ls2 ws6">devidamente conecta<span class="blank _4"></span>do aos terminais de uma bateria de 12 volts, a intensidade da corrente el<span class="blank _4"></span>é<span class="blank _1"> </span>trica </div><div class="t m0 x2 h2 y4f ff1 fs0 fc0 sc0 ls2 ws6">que o percorre é de 4A. Com base nessas informações, pode-se afirmar que o valor da resistência </div><div class="t m0 x2 h2 y50 ff1 fs0 fc0 sc0 ls2 ws6">elétrica deste dispositi<span class="blank _4"></span>vo, em ohms, é: </div><div class="t m0 x2 h2 y51 ff1 fs0 fc0 sc0 ls2 ws6">a) 1/<span class="blank _4"></span>3 </div><div class="t m0 x2 h2 y52 ff1 fs0 fc0 sc0 ls2 ws6">b) 3 </div><div class="t m0 x2 h2 y53 ff1 fs0 fc0 sc0 ls2 ws6">c) 8 </div><div class="t m0 x2 h2 y54 ff1 fs0 fc0 sc0 ls2 ws6">d) 16 </div><div class="t m0 x2 h2 y55 ff1 fs0 fc0 sc0 ls2 ws6">e) 48 </div><div class="t m0 x2 h2 y56 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y57 ff1 fs0 fc0 sc0 ls2 ws6">08) Em regiões mais frias do Brasil e fundament<span class="blank _4"></span>al a utilização de chuveiros elétricos para aquecimento </div><div class="t m0 x2 h2 y58 ff1 fs0 fc0 sc0 ls2 ws6">da água do banho di<span class="blank _4"></span>ário. Cada banho poss<span class="blank _1"> </span>ui um certo consumo de energia. Quanto <span class="blank _4"></span>de energia se gasta </div><div class="t m0 x2 h2 y59 ff1 fs0 fc0 sc0 ls2 ws6">em um banho de 10 min (<span class="blank _4"></span>1/6 de hora) em um chu<span class="blank _1"> </span>veiro elétrico cuja potência e 3,0 kW, em kWh? </div><div class="t m0 x2 h2 y5a ff1 fs0 fc0 sc0 ls2 ws6">a) 0,5 k<span class="blank _4"></span>Wh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y5b ff1 fs0 fc0 sc0 ls2 ws6">b) 3,0 kW'h </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y2e w1 h5" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg3.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls2 ws6">c) 5,0 kWh </div><div class="t m0 x2 h2 y3 ff1 fs0 fc0 sc0 ls2 ws6">d) 300<span class="blank _4"></span>0 kWh<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y5c ff1 fs0 fc0 sc0 ls2 ws6">e) 3000<span class="blank _4"></span>0 kWh </div><div class="t m0 x2 h2 y5d ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y5e ff1 fs0 fc0 sc0 ls2 ws6">09) Ana<span class="blank _4"></span>lise a tabela a seguir. <span class="ls8"> <span class="blank _1"> </span></span><span class="ff4">Corrente elétrica <span class="blank _1"> </span> <span class="ls8"> </span>Dano biológico</span> </div><div class="t m0 x2 h2 y5f ff1 fs0 fc0 sc0 ls2 ws6"> <span class="blank _4"></span>De 0,01 A ate 0,02 A D<span class="blank _1"> </span>or e contração muscular </div><div class="t m0 x2 h2 y60 ff1 fs0 fc0 sc0 ls2 ws6"> <span class="blank _4"></span>De 0,02 A ate 0,1 A P<span class="blank _1"> </span>arada respiratória<span class="blank _4"></span> <span class="blank _1"> </span> De 0,1 A ate 3<span class="blank _4"></span> </div><div class="t m0 x2 h2 y61 ff1 fs0 fc0 sc0 ls9 ws6">A <span class="ls2"> <span class="ls8"> </span>Fibrilação ventricular que pode ser fata<span class="blank _4"></span>l <span class="blank _1"> </span> <span class="blank _1"> </span> Acima de 3 A Parada </span></div><div class="t m0 x2 h2 y62 ff1 fs0 fc0 sc0 ls2 ws6">cardíaca e queimaduras graves www.mundoeducacao.com/fisica/os-efeitos-corrente-e...<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y63 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y64 ff1 fs0 fc0 sc0 ls2 ws6">A tabela<span class="blank _4"></span> acima apresenta valores de corrente elétrica e as consequências para a saúde dos ser<span class="blank _1"> </span>es </div><div class="t m0 x2 h2 y65 ff1 fs0 fc0 sc0 ls2 ws6">humanos. Para medir a corrente elétri<span class="blank _4"></span>ca a que uma pessoa fica submetida deve-s<span class="blank _1"> </span>e dividir a dif<span class="blank _4"></span>erença de </div><div class="t m0 x2 h2 y66 ff1 fs0 fc0 sc0 ls2 ws6">potencial (<span class="blank _4"></span>ddp) em volts (V) pela resistência elétrica em Ohms (Q). Desta forma, assinale a opção que </div><div class="t m0 x2 h2 y67 ff1 fs0 fc0 sc0 ls2 ws6">indica a consequência para uma<span class="blank _4"></span> pessoa que tenha uma resistênc<span class="blank _1"> </span>ia elétrica de 2000 Q e fica submetida a </div><div class="t m0 x2 h2 y68 ff1 fs0 fc0 sc0 ls2 ws6">uma ddp de 100 V de uma rede elét<span class="blank _4"></span>rica. </div><div class="t m0 x2 h2 y69 ff1 fs0 fc0 sc0 ls2 ws6">a) Cont<span class="blank _4"></span>ração muscular. </div><div class="t m0 x2 h2 y6a ff1 fs0 fc0 sc0 ls2 ws6">b) Parada respiratória<span class="blank _4"></span>.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y6b ff1 fs0 fc0 sc0 ls2 ws6">c) Parada cardíaca. </div><div class="t m0 x2 h2 y6c ff1 fs0 fc0 sc0 ls2 ws6">d) Fibril<span class="blank _4"></span>ação ventricular.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y6d ff1 fs0 fc0 sc0 ls2 ws6">e) Queimaduras graves. </div><div class="t m0 x2 h2 y6e ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y6f ff1 fs0 fc0 sc0 ls2 ws6">10) Três resistores foram submetidos a várias tensões e as<span class="blank _1"> </span> corrent<span class="blank _4"></span>es elétricas que os atravessavam </div><div class="t m0 x2 h2 y70 ff1 fs0 fc0 sc0 ls2 ws6">foram anot<span class="blank _4"></span>adas. Com os dados coletados foi montado a gráfic<span class="blank _1"> </span>o abaixo:<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y71 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x4 h2 y72 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y73 ff1 fs0 fc0 sc0 ls2 ws6">Observando o gráfico, é correto afirmar que o <span class="blank _4"></span>resistor:<span class="blank _1"> </span> </div><div class="t m0 x3 h3 y74 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls7">R<span class="fs1 lsa v1">1 <span class="blank _1"> </span></span><span class="ff5 ls2">é ôhmico e possui resistência igual a 33<span class="blank _4"></span>\u03a9<span class="blank _1"> </span><span class="ff1"> </span></span></span></span></div><div class="t m0 x3 h3 y75 ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls7">R<span class="fs1 ls2 ws9 v1">2</span><span class="ls2"> é ôhmico e poss<span class="blank _1"> </span>ui <span class="ff5">resistência igual a 2<span class="blank _4"></span>2\u03a9<span class="ff1"> </span></span></span></span></span></div><div class="t m0 x3 h3 y76 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls7">R<span class="fs1 ls2 ws9 v1">3</span><span class="ls2"> <span class="ff5">não é ôhmi<span class="blank _4"></span>co e possui resistência igual a 11\u03a9<span class="blank _1"> </span><span class="ff1"> </span></span></span></span></span></div><div class="t m0 x3 h3 y77 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls7">R<span class="fs1 ls2 ws9 v1">2</span><span class="ls2"> <span class="ff5">não é ôhmico e possui resis<span class="blank _1"> </span>tência igual<span class="blank _4"></span> a 22\u03a9<span class="blank _1"> </span><span class="ff1"> </span></span></span></span></span></div><div class="t m0 x3 h3 y78 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls7">R<span class="fs1 ls2 ws9 v1">1</span><span class="ls2"> <span class="ff5">não é ôhmico e possui resis<span class="blank _1"> </span>tência igual<span class="blank _4"></span> a 44\u03a9<span class="blank _1"> </span><span class="ff1"> </span></span></span></span></span></div><div class="t m0 x2 h2 y79 ff1 fs0 fc0 sc0 ls2 ws6">11) C<span class="blank _4"></span>om o objetivo de mostrar as diferentes maneiras de se associar os res<span class="blank _1"> </span>istores e, <span class="blank _1"> </span>assim, estudar as </div><div class="t m0 x2 h2 y7a ff1 fs0 fc0 sc0 ls2 ws6">suas principais características, foi<span class="blank _4"></span> proposto o circuito abaixo:<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y7b ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x5 h2 y7c ff1 fs0 fc0 sc0 ls2 ws6"> </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y7d w1 h6" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg4.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls2 ws6">Analisando essa montagem, concluiu-se que a corrente elét<span class="blank _4"></span>rica que es<span class="blank _1"> </span>tá passando pelo circuit<span class="blank _4"></span>o vale:<span class="blank _1"> </span> </div><div class="t m0 x3 h3 y3 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">0, 96A </span></span></div><div class="t m0 x3 h3 y5c ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">0,48A </span></span></div><div class="t m0 x3 h3 y5d ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls2">0,36<span class="blank _4"></span>A </span></span></div><div class="t m0 x3 h3 y5e ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">0,24A </span></span></div><div class="t m0 x3 h3 y5f ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">0,12A </span></span></div><div class="t m0 x2 h2 y61 ff1 fs0 fc0 sc0 ls2 ws6">12) Para uma a<span class="blank _4"></span>tividade prática de eletricidade, foi montado o <span class="blank _1"> </span>circuito abaixo e, com um amperímet<span class="blank _4"></span>ro, </div><div class="t m0 x2 h2 y7e ff1 fs0 fc0 sc0 ls2 ws6">verificou-se que a corrente elét<span class="blank _4"></span>rica que o circulava, num dado momento, era de 2A.<span class="blank _1"> </span> </div><div class="t m0 x6 h2 y7f ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y80 ff1 fs0 fc0 sc0 ls2 ws6">Nesse instante, é correto afirmar que a<span class="blank _4"></span> potência da lâmpada, em watts, valia.<span class="blank _1"> </span> </div><div class="t m0 x3 h3 y81 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">9 </span></span></div><div class="t m0 x3 h3 y82 ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">8 </span></span></div><div class="t m0 x3 h3 y83 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls2">6 </span></span></div><div class="t m0 x3 h3 y84 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">5 </span></span></div><div class="t m0 x3 h3 y85 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">3 </span></span></div><div class="t m0 x2 h2 y86 ff1 fs0 fc0 sc0 ls2 ws6">13) Ana<span class="blank _4"></span>lise a figura a seguir. </div><div class="t m0 x2 h2 y87 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x7 h2 y88 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y89 ff1 fs0 fc0 sc0 ls2 ws6">A lei de Ohm afirma que, para um condut<span class="blank _4"></span>or que for mantido a <span class="blank _1"> </span>uma temperatura consta<span class="blank _4"></span>nte, a razão </div><div class="t m0 x2 h2 y8a ff1 fs0 fc0 sc0 ls2 ws6">entre a tensão e a corrent<span class="blank _4"></span>e elétrica é uma constante. Essa constante é chamada de resistência el<span class="blank _4"></span>étrica. </div><div class="t m0 x2 h2 y8b ff1 fs0 fc0 sc0 ls2 ws6">A figura acima<span class="blank _4"></span> representa uma lanterna, cujo circuito elétrico <span class="blank _1"> </span>é composto de uma pilha, uma chave S e </div><div class="t m0 x2 h2 y8c ff1 fs0 fc0 sc0 ls2 ws6">uma lâmpada L. A pi<span class="blank _4"></span>lha fornece uma tensão V = 6,0 V ao circui<span class="blank _1"> </span>to, e a resistência da lâ<span class="blank _4"></span>mpada é R = 3 </div><div class="t m0 x2 h2 y8d ff1 fs0 fc0 sc0 ls2 ws6">Ohms. Quando a chave S é fechada (li<span class="blank _4"></span>gada) , qual o valor da co<span class="blank _1"> </span>rrente elétrica no ci<span class="blank _4"></span>rcuito?<span class="blank _0"> </span> </div><div class="t m0 x3 h3 y8e ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">2,5 A <span class="blank _1"> </span> </span></span></div><div class="t m0 x3 h3 y8f ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">2,0 A<span class="blank _1"> </span> </span></span></div><div class="t m0 x3 h3 y90 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff1 ls2">1, 5 A </span></span></div><div class="t m0 x3 h3 y91 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">1,0 A<span class="blank _1"> </span> </span></span></div><div class="t m0 x3 h3 y92 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff1 ls2">0, 5 A<span class="blank _1"> </span> </span></span></div><div class="t m0 x2 h2 y93 ff1 fs0 fc0 sc0 ls2 ws6">14) Para fa<span class="blank _4"></span>zer um rádio funcionar, ele precisa ser alimentado com uma tensão de 6 Volts. Dispõe<span class="blank _1"> </span>-se de </div><div class="t m0 x2 h2 y94 ff1 fs0 fc0 sc0 ls2 ws6">quatro pil<span class="blank _4"></span>has, sendo que cada uma delas possui tensão V = 1,5 V<span class="blank _1"> </span>. Logo, para que esse rádio funcione, </div><div class="t m0 x2 h2 y95 ff1 fs0 fc0 sc0 ls2 ws6">devem ser associada<span class="lsb wsa">s.</span> </div><div class="t m0 x2 h2 y96 ff1 fs0 fc0 sc0 ls2 ws6">a) três pilhas em série. </div><div class="t m0 x2 h2 y97 ff1 fs0 fc0 sc0 ls2 ws6">b) quatro pi<span class="blank _4"></span>lhas em série.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y98 ff1 fs0 fc0 sc0 ls2 ws6">c) três pilhas em paralelo. </div><div class="t m0 x2 h2 y99 ff1 fs0 fc0 sc0 ls2 ws6">d) quatro pi<span class="blank _4"></span>lhas em paralelo.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y9a ff1 fs0 fc0 sc0 ls2 ws6">e) duas pilhas em série e duas em paralelo. </div><div class="t m0 x2 h2 y9b ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y9c ff1 fs0 fc0 sc0 ls2 ws6">15) Duas lâmpadas incandescentes e idênti<span class="blank _4"></span>cas estão ligadas a uma fonte de 24V, conforme mostra <span class="blank _1"> </span>o </div><div class="t m0 x2 h2 y9d ff1 fs0 fc0 sc0 ls2 ws6">circuito aba<span class="blank _4"></span>ixo.<span class="blank _1"> </span> </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf5" class="pf w0 h0" data-page-no="5"><div class="pc pc5 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y9e w1 h7" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg5.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x8 h2 y5f ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y9f ff1 fs0 fc0 sc0 ls2 ws6">Sabendo que a corrent<span class="blank _4"></span>e elétrica que circula através do circuito tem intensidade igual a 4A, é correto </div><div class="t m0 x2 h2 ya0 ff1 fs0 fc0 sc0 ls2 ws6">afirmar que a resistência de cada<span class="blank _4"></span> lâmpada vale.<span class="blank _1"> </span> </div><div class="t m0 x3 h3 ya1 ff2 fs0 fc0 sc0 ls3 ws0">a)<span class="ff3 ls0 ws6"> <span class="ff5 ls4 wsb">6\u03a9<span class="blank"> </span></span><span class="ff1 ls2"> </span></span></div><div class="t m0 x3 h3 ya2 ff2 fs0 fc0 sc0 ls3 ws0">b)<span class="ff3 ls0 ws6"> <span class="ff5 ls4 wsb">5\u03a9<span class="blank"> </span></span><span class="ff1 ls2"> </span></span></div><div class="t m0 x3 h3 ya3 ff2 fs0 fc0 sc0 ls2 ws2">c)<span class="ff3 ls1 ws6"> <span class="ff5 ls4 wsb">4\u03a9</span><span class="ff1 ls2"> </span></span></div><div class="t m0 x3 h3 ya4 ff2 fs0 fc0 sc0 ls3 ws0">d)<span class="ff3 ls0 ws6"> <span class="ff5 ls4 wsb">3\u03a9<span class="blank"> </span></span><span class="ff1 ls2"> </span></span></div><div class="t m0 x3 h3 ya5 ff2 fs0 fc0 sc0 ls3 ws0">e)<span class="ff3 ls0 ws6"> <span class="ff5 ls4 wsb">2\u03a9<span class="blank"> </span></span><span class="ff1 ls2"> </span></span></div><div class="t m0 x2 h2 ya6 ff1 fs0 fc0 sc0 ls2 ws6"> RESOLU<span class="blank _1"> </span>ÇÃO:<span class="blank _4"></span> </div><div class="t m0 x2 h2 ya7 ff1 fs0 fc0 sc0 ls2 ws6">01)ALTERNATIV<span class="blank _1"> </span>A C </div><div class="t m0 x2 h2 ya8 ff1 fs0 fc0 sc0 ls2 ws6">Com a chave abert<span class="blank _4"></span>a, os três res<span class="blank _1"> </span>istores es<span class="blank _1"> </span>tão em série. </div><div class="t m0 x2 h2 ya9 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws6 v1">eq </span><span class="ls2 ws6">= R<span class="fs1 ws9 v1">1</span> + R<span class="fs1 ws9 v1">2</span> + R<span class="blank _1"> </span><span class="fs1 ws9 v1">3</span><span class="ls8"> </span>-> R</span><span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = 3.R </span></div><div class="t m0 x2 h2 yaa ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = U/i -> 3.R = 24<span class="blank _4"></span>/2 -> R = 4 ohms </span></div><div class="t m0 x2 h2 yab ff1 fs0 fc0 sc0 ls2 ws6">Com a chave fechada<span class="blank _4"></span>, a associação pass<span class="blank _1"> </span>a a ter dois resistores associados em série. </div><div class="t m0 x2 h2 yac ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = R<span class="fs1 ws9 v1">1</span> + R<span class="fs1 ws9 v1">2</span><span class="ls8"> </span>-> R</span><span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = 8 ohms </span></div><div class="t m0 x2 h2 yad ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws6 v1">eq </span><span class="ls2 ws6">= U/i -> 8 = 24/<span class="blank _4"></span>i -> i = 3 A </span></div><div class="t m0 x2 h8 yae ff1 fs0 fc0 sc0 ls2 ws6">Potência em cada lâ<span class="blank _4"></span>mpada <span class="ff5 lsd">\u2013</span> Pot = R.i<span class="fs1 ws9 v2">2</span><span class="ls8"> </span>-> Pot = 4.32 -> Pot = 36 W. </div><div class="t m0 x2 h2 yaf ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yb0 ff1 fs0 fc0 sc0 ls2 ws6">02) ALTERNATIV<span class="blank _1"> </span>A C </div><div class="t m0 x2 h2 yb1 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yb2 ff1 fs0 fc0 sc0 ls2 ws6">03) ALTERNATIV<span class="blank _1"> </span>A A </div><div class="t m0 x2 h2 yb3 ff1 fs0 fc0 sc0 ls2 ws6">t = 6.3<span class="blank _4"></span>0 = 180 h<span class="blank _1"> </span> </div><div class="t m0 x2 h2 yb4 ff1 fs0 fc0 sc0 ls2 ws6">Pot = U.i -> 1100 = 22<span class="blank _4"></span>0.i -> i = 1100/220 = 5 A<span class="blank _1"> </span> </div><div class="t m0 x2 h2 yb5 ff1 fs0 fc0 sc0 ls2 ws6">E = Pot.t -> E = 1100<span class="blank _4"></span>.180 -> E = 1<span class="blank _1"> </span>98 kwh. </div><div class="t m0 x2 h2 yb6 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yb7 ff1 fs0 fc0 sc0 ls2 ws6">04) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 yb8 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws9 v1">1</span><span class="ls2 ws6"> = 2 + 5 + 3<span class="blank _4"></span> -> R<span class="fs1 ws9 v1">1</span> = 10 ohms </span></div><div class="t m0 x2 h2 yb9 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws9 v1">2</span><span class="ls2 ws6"> = 5 + 5 -<span class="blank _4"></span>> R<span class="fs1 ws9 v1">2</span> = 10 ohms </span></div><div class="t m0 x2 h2 yba ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = R<span class="fs1 ws9 v1">1</span></span><span class="ls5 ws3">.R</span><span class="fs1 ls2 ws9 v1">2</span><span class="ls2 wsd">/(R<span class="fs1 ws9 v1">1</span><span class="ws6"> + R<span class="fs1 ws9 v1">2</span>) -> R</span></span><span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = 10.10/<span class="blank _4"></span>20 -> R<span class="fs1 lse wse v1">eq</span> = 5 ohms </span></div><div class="t m0 x2 h2 ybb ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = U/i -> 5 = 12<span class="blank _4"></span>/i -> i = 2,4 A.<span class="blank _1"> </span> </span></div><div class="t m0 x2 h2 ybc ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 ybd ff1 fs0 fc0 sc0 ls2 ws6">04) ALTERNATIV<span class="blank _1"> </span>A <span class="blank _4"></span>E </div><div class="t m0 x2 h2 ybe ff1 fs0 fc0 sc0 ls2 ws6">Pot = U.i -> 4800 = 12<span class="blank _4"></span>0.i -> i = 40 A.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 ybf ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yc0 ff1 fs0 fc0 sc0 ls2 ws6">05) ALTERNATIV<span class="blank _1"> </span>A C </div><div class="t m0 x2 h2 yc1 ff1 fs0 fc0 sc0 ls2 ws6">Pilhas secas s<span class="blank _1"> </span>ão geradores que transformam energia química e<span class="blank _4"></span>m energia el<span class="blank _4"></span>étrica.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 yc2 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yc3 ff1 fs0 fc0 sc0 ls2 ws6">06) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 yc4 ff1 fs0 fc0 sc0 ls2 ws6">A unidade kw.h é a unida<span class="blank _4"></span>de usada pelas empresas de eletricid<span class="blank _1"> </span>ade. É a unidade usada para medir a </div><div class="t m0 x2 h2 yc5 ff1 fs0 fc0 sc0 ls2 ws6">energia elétrica consumida. </div><div class="t m0 x2 h2 yc6 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yc7 ff1 fs0 fc0 sc0 ls2 ws6">07) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 yc8 ff1 fs0 fc0 sc0 ls2 ws6">R = U/i -> R = 12/<span class="blank _4"></span>4<span class="ls8"> </span>-> R = 3 ohms.<span class="blank _0"> </span> </div><div class="t m0 x2 h2 yc9 ff1 fs0 fc0 sc0 ls2 ws6"> </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf6" class="pf w0 h0" data-page-no="6"><div class="pc pc6 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 yca w1 h9" alt="" src="https://files.passeidireto.com/d4017d65-2a1d-457c-817d-9814600694dc/bg6.png"><div class="c x1 y1 w2 h0"><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls2 ws6">08) ALTERNATIV<span class="blank _1"> </span>A A </div><div class="t m0 x2 h2 y3 ff1 fs0 fc0 sc0 ls2 ws6">E = Pot.t -> E = 3.(1/6) -> E = 0,5 k<span class="blank _4"></span>Wh.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y5c ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y5d ff1 fs0 fc0 sc0 ls2 ws6">09) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 y5e ff1 fs0 fc0 sc0 ls2 ws6">R = U/i -> 200<span class="blank _4"></span>0 = 100/i -> i = 0,05 A.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y5f ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y60 ff1 fs0 fc0 sc0 ls2 ws6">10) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 y61 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws9 v1">1</span><span class="ls2 ws6"> = U/i -> R<span class="fs1 ws9 v1">1</span> = 4<span class="blank _4"></span>40/10 -> R<span class="fs1 ws9 v1">1</span> = 44 ohms.<span class="blank _1"> </span> </span></div><div class="t m0 x2 h2 y62 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lsa ws6 v1">2 </span><span class="ls2 ws6">= U/i -> R<span class="fs1 ws9 v1">2</span> = 550/25<span class="blank _4"></span> -> R<span class="fs1 ws9 v1">2</span> = <span class="blank _1"> </span>22 ohms. </span></div><div class="t m0 x2 h2 y63 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 ls2 ws9 v1">3</span><span class="ls2 ws6"> = U/i -> R<span class="fs1 ws9 v1">3</span> = 2<span class="blank _4"></span>20/20 -> R<span class="fs1 ws9 v1">3</span> = 11 ohms.<span class="blank _1"> </span> </span></div><div class="t m0 x2 h2 y64 ff1 fs0 fc0 sc0 ls2 ws6">Resistor ôhmico é aquele que possui resistência elétrica constant<span class="blank _4"></span>e. </div><div class="t m0 x2 h2 y65 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y66 ff1 fs0 fc0 sc0 ls2 ws6">11) ALTERNATIV<span class="blank _1"> </span>A <span class="blank _4"></span>E </div><div class="t m0 x2 h2 y67 ff1 fs0 fc0 sc0 ls2 ws6">Associação em paralelo: 1/<span class="blank _4"></span>R<span class="fs1 lse wsc v1">eq</span> = 1/100 + 1/100 -> R<span class="fs1 lse wsc v1">eq<span class="blank"> </span></span> = 50 oh<span class="blank _1"> </span>ms </div><div class="t m0 x2 h2 y68 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = 50 + 50 = 1<span class="blank _4"></span>00 ohms </span></div><div class="t m0 x2 h2 y69 ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = U/i -> 100<span class="blank _4"></span> = 12/i -> i = 0,12 A.<span class="blank _1"> </span> </span></div><div class="t m0 x2 h2 y6a ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y6b ff1 fs0 fc0 sc0 ls2 ws6">12) ALTERNATIV<span class="blank _1"> </span>A A </div><div class="t m0 x2 h2 y6c ff1 fs0 fc0 sc0 ls2 ws6">Pot = U.i -> Pot = (1,5<span class="blank _4"></span> + 1,5 + 1,5).2 -> Pot = 9 W<span class="blank _1"> </span>. </div><div class="t m0 x2 h2 y6d ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y6e ff1 fs0 fc0 sc0 ls2 ws6">13) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 y6f ff1 fs0 fc0 sc0 ls2 ws6">R = U/i -> 3 = 6/i -> i = 2<span class="blank _4"></span> A.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 y70 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y71 ff1 fs0 fc0 sc0 ls2 ws6">14) ALTERNATIV<span class="blank _1"> </span>A B </div><div class="t m0 x2 h2 ycb ff1 fs0 fc0 sc0 ls2 ws6">Na associação em série, cada elemento possui sua ddp. </div><div class="t m0 x2 h2 ycc ff1 fs0 fc0 sc0 ls2 ws6">U = 1,5 + 1,5 + 1,5<span class="blank _4"></span> + 1,5 = 6,0 V.<span class="blank _1"> </span> </div><div class="t m0 x2 h2 ycd ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 y89 ff1 fs0 fc0 sc0 ls2 ws6">15) ALTERNATIV<span class="blank _1"> </span>A <span class="blank _4"></span>D </div><div class="t m0 x2 h2 y8a ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = U/i -> R<span class="fs1 v1">eq </span>= 24/4 -> R<span class="fs1 v1">eq </span>= 6 ohms </span></div><div class="t m0 x2 h2 yce ff1 fs0 fc0 sc0 lsc">R<span class="fs1 lse wsc v1">eq</span><span class="ls2 ws6"> = R + R -> 6 = 2.R -> R = 3 ohms. </span></div><div class="t m0 x2 h2 ycf ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yd0 ff1 fs0 fc0 sc0 ls2 ws6"> </div><div class="t m0 x2 h2 yd1 ff1 fs0 fc0 sc0 ls2 ws6"> </div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div>
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