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Step of 5 2.090P The differentiation of triangular waveform results a square waveform. This is because differentiation of ramp signal results in a square wave. (t) A IV 0 0.25 0.5 0.75 1.25 1.5 (Sms) -IV B T Figure 1 Step of 5 The input voltage equation between 0 to A points (0, 0) and (0.00025, 1) is, 1-0 The input voltage equation between A and B points (0 00025, 1) and (0.00075,-1) is, -1-1 10⁻³ = 0.00075-0.00025 4 The input voltage equation between points and C (0.00075,-1) and (0.001,0) is, 0.00025 0+1 4 4 Step of 5 Calculate the total input equation for full cycle T = ms 2 Calculate the output voltage for = 0 to = ms Substitute 20 kΩ for R and 10⁻⁷ F for =-8V Step of 5 Sketch the output waveform. 4V 0 0.25 0.5 T Figure 2 Step of 5 Consider the following for a square wave: = Here, = 4 V Hence, =4V Find the value of R for = 12 V R -12 = Hence, the required resistance R is