Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_573

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Step of 5 5.006E The Device parameter is, = = 40 Therefore, the value of is, Step 2 of 5 The Device parameter 2 is, = 40 =0.025 Therefore, the value of 2 is, Step of 5 The overdrive voltage of the device is, The Drain to source voltage is, Hence, > So, the device is operating in saturation region. In saturation region, the drain current is, Substitute for , for for L. 0.5V for 1V for and 0.025V⁻¹ for 2. =(100x10*)(20)(0.25)(1.02 Therefore, the drain current is, Step 4 of 5 The Output resistance is, iD 40 = 0.5125x10⁻³ = Therefore, the output resistance is, Step 5 of 5 The voltage is increased of by So, the new drain to source voltage is, 3V Since, > the device is operating in saturation region. In saturation region drain current is, Substitute for 16 µm for for L. 0.5V for 3V for and =0.5375x10⁻³ The increase in drain current is, =0.025x10⁻³ Therefore, the drain current increment is, D(increment) =