Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_759

Prévia do material em texto

Step 1 of 9 7.006E Refer Figure the textbook (a) Determine the dc current and dc voltage DS To find the dc parameters put =0 Dc drain current is, (1) Here, V, threshold voltage, gate source voltage, transconductance (W/L) width Substitute V for threshold 2V for 20 for and 20 for (W/L) the equation (1) Thus, Drain current ID Step Apply Kirchhoff's voltage law the drain loop. Substitute 10 for drain resistance RD for power voltage and 200 for drain current in the above equation. =5-2 =3V Thus, Drain source voltage is Step (b) The trans-conductance is, Substitute V for V, for Vas and for the above equation 8m mA/V Thus, trans -conductance at the bias point 0.4 mA/\ Step (c) The voltage gain is, Substitute 10 for RD 0.4 mA/V for in the above equation Therefore, the voltage gain V/V Step 5 of 9 (d) Small signal approximation holds good. relation between and Consider gate-Source signal is V Substitute -4V for and V for in the equation -4 V/V Hence, small signal voltage is Step Minimum and maximum values obtain by combining ac and dc values at the same time. Minimum value the is, =3-0.8(1) =3-0.8 =2.2V Step of 9 Maximum value the is, =3+0.8(1) =3+0.8 =3.8V Therefore, the minimum and maximum values of drain to source voltage are 2.2V and 3.8V Step of 9 (e) Consider the situation with the input signal applied. The total instantaneous gate source voltage will be Instantaneous drain current from equation (7 28) in the textbook is, 2 Substitute for k, 2V for IV for and V for in equation (2) 200 +0.04 200+ Therefore, various component drain current is 204 Step 9 of 9 Consider the drain current equation In the above equation amplitude of second harmonic is of fundament Second harmonics amplitude percentage with respect to the fundamental component