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CHAPTER 8 261 diastereomers because they are stereoisomers that are not mirror images of each other. 8.54. This conversion requires the Markovnikov addition of water without carbocation rearrangement. This can be achieved via oxymercuration-demercuration: 8.55. In the presence of acid, the epoxide is first protonated, which requires two curved arrows, as shown below. The resulting intermediate is then attacked by a molecule of methanol, which functions as a nucleophile. This step requires two curved arrows. Then, in the final step of the mechanism, a molecule of methanol functions as a base and removes a proton, thereby generating the product. This final step is a proton transfer step, and therefore requires two curved arrows: 8.56. In the first step of the mechanism, a proton is transferred from H3O+ to the alkene, which requires two curved arrows, as shown. The resulting secondary carbocation then rearranges via a methyl shift, giving a more stable, tertiary carbocation. That step is shown with one curved arrow. The tertiary carbocation is then captured by a water molecule, which is shown with one curved arrow, going from the nucleophile (water) to the electrophile (the carbocation). Then, in the final step of the mechanism, a molecule of water functions as a base and removes a proton, thereby generating the product. This final step is a proton transfer step, and therefore requires two curved arrows, as shown: OH Methyl shift H O H H H O H H O H O HH 8.57. (a) The reagents indicate a hydrogenation reaction, so the net result will be the addition of H and H across the alkene. The regiochemical outcome is not relevant because the two groups added (H and H) are identical. We expect the reaction to proceed via a syn addition, giving the following meso compound: (b) The reagents indicate an acid-catalyzed hydration, so the net result will be the addition of H and OH across the alkene. We expect a Markovnikov addition, so the OH group will be installed at the more-substituted position. No chiral centers are formed in the process, so stereochemistry is not a relevant consideration: (c) The reagents indicate a hydroboration-oxidation, so the net result will be the addition of H and OH across the alkene. For the regiochemical outcome, we expect an anti-Markovnikov addition, so the OH group is installed at the less-substituted position. The stereochemical outcome (syn addition) is not relevant in this case, because the product has no chiral centers: (d) The reagents indicate a dihydroxylation process (via an epoxide), so the net result will be the addition of OH and OH across the alkene. The regiochemical outcome www.MyEbookNiche.eCrater.com