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Semiconductor Physics and Devices: Basic Principles, 4 th edition Chapter 6 By D. A. Neamen Problem Solutions ______________________________________________________________________________________ 6.9 p-type material; minority carriers are electrons (a) n From Figure 5.3, 1300n cm 2 /V-s (b) 13000259.0 nn e kT DD 67.33 cm 2 /s (c) 7 0 10 nnt s 15107 ao Np cm 3 15 2102 107 105.1 a i o N n n 41021.3 cm 3 pt o nt o pn pt 15 7 4 107 10 10214.3 so 41018.2 pt s _______________________________________ 6.10 For Ge: 13104.2 in cm 3 2 2 22 i dd o n NN n 213 2 1313 104.2 2 104 2 104 1310124.5 cm 3 13 13 2132 10124.1 10124.5 104.2 o i o n n p cm 3 (a) We have: 3900n cm 2 /V-s, 101nD cm 2 /s 1900p cm 2 /V-s, 2.49pD cm 2 /s For very, very low injection, pDnD pnDD D pn pn 1313 1313 10124.12.4910124.5101 10124.110124.52.49101 2.54 cm 2 /s and pn np pn pn 1313 1313 10124.1190010124.53900 10124.510124.119003900 1340 cm 2 /V-s (b) For holes, 6 0 102 ppt s For electrons, 0pnt pn 6 1313 102 10124.110124.5 nt 61012.9 nt s _______________________________________ 6.11 pene pn With excess carriers nnn o and ppp o For an n-type semiconductor, we can write ppn Then ppepne opon or pepene pnopon so pe pn In steady-state, pOgp So that pOpn ge _______________________________________ 6.12 (a) 1610 ao Np cm 3 4 16 2102 1025.2 10 105.1 o i o p n n cm 3 ppenne opon nepe pnop Now 0/ 0 1 nt n egpn 0/720 1105108 nt e 0/14 1104 nt e cm 3