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9 Molecular Geometry Solutions to Exercises (d) trigonal bipyramidal electron-domain geometry F F F S F or S F F F F (e) Because F is more electronegative than O, S-F bonding domains are smaller than the S=O domain. The structure that minimizes S=O repulsions is more likely (see Solution 9.90). That is, the structure with fewer 90° F- S=O angles and more 120° F- S=O angles is favored. The structure on the right, with in the equatorial position is more likely. Note that a double bond involving an atom with an expanded octet of electrons, such as the S=O in this molecule, does not have the same geometric implications as a double bond to a first row element. 9.111 (a) PX₃, 26 valence 13- pairs 4 electron domains around P, tetrahedral domain geometry, If all bonding and nonbonding electron domains are the same size, perfect tetrahedral angles are 109.5°. If all bonding electron domains are the same size but the nonbonding domain is larger, bond angles are somewhat less than 109°. (b) As electronegativity increases (I