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Trabalho de Calculo III Nome: Rafael Mesquita de Sousa Matricula:201602130817 y’’-2y’+y=t^2-1 m^2-2m+1=0 =1 yh=c1e^x+c2ce^x yp=(ax^2+bx+c)-d y’p=2ax+b y’’p=2a 2a-2(2ax+b)+(ax^2+bx+c-d)=t^2-1 2a-4ax-2b+ax^2+bx+c-d=t^2-1 (-4a+b)x+92a-2b+c)+ax^2-d=t^2-1 a=1 d=-1 -4a+b=0 2a-2b=0 -4+b=0 2-2b+c=0 B=4 2-2b+c=0 2-2*4+c=0 2-8+c=0 -6+c= C=6 Yp=(ax^2+bx+c)-d Yp=1x^2+4x+6-(-1) Yp=1x^2+4x+7 Yg=c1e^x+c2xe^x+x^2+4x+7 2)y’’-2y’+y=3e^2t m^2-2m+1=0 =1 yh=c1e^x+c2xe^x yp=ae^2t y’p=2ae^2t y’’p=4ae^2t 4ae^2t-2(2ae^2t)+ae^2t=3e^2t 4ae^2t-4ae^2t+ae^2t=3e^2t A=3 Yg=c1e^x+c2xe^x+3e^2t 3)y’’-2y’+y=4cost m^2-2m+1=0 =1 yh=c1e^x+c2xe^x yp=accost+bsent y’p=-asent+bcost y’’p=-acost-bsent -acost-bsent-2(-asent+bcost)+(acost+bsent) =4cost 2asent-2bcost=4cost -bcost=-4cost A=0 b=-2 Yp=accost+bsent Yp=0cost-2sent Yp=-2sent Yg=c1e^x+c2xe^x-2sent 4)y’’-2y’+y=3e^t m^2-2m+1=0 =1 yh=c1e^x+c2xe^x yp=at^2e^t y’p=2ate^t+at^2e^t y’’p=(2a*e^t+2at*e^t)+(2at*e^t+at^2*e^t) (2a*e^t+2at*e^t)+(2at*e^t+at^2*e^t)-2(2at*e^t+at^2*e^t)+at^2e^t=3e^t 2ae^t+2ate^t+2ate^t+at^2e^t-4ate^t-2atê^t=3e^t 2ae^t+4ate^t-4ate^t+2at^2e^t-2at^2e^t=3e^t 2ae^t=3e^t 2a=3 A=3/2 Yp=3/2t^2e^t Yg=c1e^t+c2xe^t+3/2t^2e^t 5)y’’-2y’+y=te^t m^2-2m+1=0 =1 yh=c1e^x+c2xe^x yp=at^3e^t+bt^2e^t y’p=3at^2e^t+at^3e^t+2bte^t+bt^2e^t y’’p=6ate^t+6at^2e^t+at^3e^t+2be^t+4bte^t+bt^2e^t 9ate^t+6at^2e^t+at^3e^t+2be^t+4bte^t+bt^2e^t+6at^2e^t-2at^3e^t-4bte^t-2bt^2e^t+at^3e^t+bt^2e^t=te^t 6ate^t+bt^2e^t=te^t (6at+2b)e^t=te^t 6ª=1 A=1/6 2b=0 b=0 yp=1/6t^3e^t yg=c1e^x+c2xe^t+1/6t^3e^t 6)y’-y=sent+cos2t m-1=0 m=1 yh=c1e^x+c2xe^x yp=asent+bcost+csen2t+dcos2t y’p=accost-bsent+ccos2t-dsen2t yp= accost-bsent+ccos2t-dsen2t-asent-bcost-csen2t+dcos2t=sent+cos2t acost+ccos2t-bcost-dcos2t-bsent-dsen2t-asent-csen2t=sent+cost (a-b)cost+(c-d)cos2t+(-b-a)sent+(-d-csen2t) =sent+cos2t -a-b=1 *(-1) A+b=-1 a-b=0 a=b+0 b+b=-1 2b=-1 B=-1/2 a-1/2=-1 a=-1+1/2 a=-1/2 c-d=1 -c-d=0 c=d+0 -d-d=0 D=0/2 D=0 c-d=1 c-0=1 c=1 -1/2sent-1/2cost+sen2t Yg=c1e^t+c2xe^t-1/2sent-1/2cost+sen2t
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