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Exemplo dist probabilidade 2018

Esta é uma pré-visualização de arquivo. Entre para ver o arquivo original

ex 1 e 2
	p =	0.6	p =	0.6
	n =	3	n =	5
	x	p	Prob Acum	x	p	Prob Acum
	0	0.064	0.064	0	0.01024	0.01024
	1	0.288	0.352	1	0.0768	0.08704
	2	0.432	0.784	2	0.2304	0.31744
	3	0.216	1	3	0.3456	0.66304
	4	0.2592	0.92224
	5	0.07776	1
	Distrbinom(x;n;p;falso ou verdadeiro)
	Falso se só probabilidade
	Verdadeiro se probabilidade acumulada
	livro
	p =	0.4
	n =	5
	x	p	Prob Acum
	0	0.0778	0.07776
	1	0.2592	0.33696
	2	0.3456	0.68256
	3	0.2304	0.91296
	4	0.0768	0.98976
	5	0.01024	1
Ex 3
	p	0.1
	n	6
	x	p(x)	p(x) acum
	0	0.53144	0.53144
	1	0.35429	0.88573
	2	0.09842	0.98415
	3	0.01458	0.99873
	4	0.00122	0.99994
	5	0.00005	1.00000
	6	0.00000	1.00000
	ou =	1 - 0,8857
	0.098415	0.1143
	0.01458
	0.001215
	0.000054
	0.000001
	Soma 	0.114265
Ex. 4
	4)	p	0.3	B e C	30%
	n	12
	x	p(x)	p(x) acum
	0	0.0138412872	0.0138412872
	1	0.0711837627	0.0850250499
	2	0.1677902979	0.2528153479
	3	0.2397004256	0.4925157734
	4	0.2311396961	0.7236554695
	5	0.1584957916	0.8821512611
	6	0.0792478958	0.9613991569
	7	0.0291114719	0.9905106289
	8	0.0077977157	0.9983083446
	9	0.0014852792	0.9997936237
	10	0.0001909645	0.9999845882
	11	0.0000148803	0.9999994686
	12	0.0000005314	1
Ex 5
	p	0.01	p	0.01
	n	10	n	20
	x	p(x)	p(x) acum	x	p(x)	p(x) acum
	0	0.904382075	0.904382075	0	0.8179069376	0.8179069376	0.8179069376
	1	0.0913517247	0.9957337998	1	0.1652337248	0.9831406624	0.1652337248
	2	0.0041523511	0.9998861509	2	0.0158557615	0.9989964238	0.9831406624
	3	0.0001118478	0.9999979987	3	0.0009609552	0.9999573791
	4	0.0000019771	0.9999999758	4	0.0000412531	0.9999986322
	5	0.000000024	0.9999999998	5	0.0000013334	0.9999999656
	6	0.0000000002	1	6	0.0000000337	0.9999999993
	7	0	1	7	0.0000000007	1
	8	0	1	8	0	1
	9	0	1	9	0	1
	10	0	1	10	0	1
	P(A)	0.9044	11	0	1
	P(B)	0.9831	12	0	1
	P(AeB)=	0.88911564	13	0	1
	14	0	1
	15	0	1
	16	0	1
	17	0	1
	18	0	1
	19	0	1
	20	0	1
Exercício 9
	livro
	p =	0.4
	n =	5
	x	p	Prob Acum
	0	0.0778	0.07776
	1	0.2592	0.33696
	2	0.3456	0.68256
	3	0.2304	0.91296
	4	0.0768	0.98976
	5	0.01024	1
Exercicío 11
	p =	0.4
	n =	5
	x	p
	0	7.7759999999999996E-2
	1	0.25919999999999999
	2	0.34559999999999996
	3	0.23039999999999999
	4	7.6799999999999993E-2
	5	1.0240000000000008E-2
	P(x)≥2= P(2)+ P(3)+ P(4)+ P(5)=
	P(x)≥2	0.66303999999999996

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