<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg1.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls1 ws1">R<span class="_0 blank"></span>esolução de questões \u2013 </div><div class="t m0 x1 h2 y2 ff1 fs0 fc0 sc0 ls1 ws1">Noções de inf<span class="_0 blank"></span>or<span class="_1 blank"> </span>mática</div><div class="t m0 x2 h3 y3 ff2 fs1 fc0 sc0 ls1 ws1">Ítalo Demarchi<span class="fs2 v1">1</span></div><div class="t m0 x3 h4 y4 ff2 fs3 fc0 sc0 ls1 ws1">1. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>espe) <span class="_3 blank"> </span>Assinale <span class="_4 blank"> </span>a <span class="_4 blank"> </span>opção <span class="_4 blank"> </span>correspondente <span class="_4 blank"> </span>a <span class="_4 blank"> </span>características <span class="_4 blank"> </span>do <span class="_4 blank"> </span>sistema </span></div><div class="t m0 x4 h5 y5 ff3 fs3 fc1 sc0 ls1 ws1">operacional Linux.</div><div class="t m0 x4 h4 y6 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">Monotarefa, monousuário<span class="_0 blank"></span>, gratuito<span class="_0 blank"></span>.</span></div><div class="t m0 x4 h4 y7 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">Multitarefa, multiusuário<span class="_0 blank"></span>, <span class="ff4">open source</span>.</span></div><div class="t m0 x4 h4 y8 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">Monotarefa, multiusuário<span class="_0 blank"></span>, <span class="ff4">open source</span>.</span></div><div class="t m0 x4 h4 y9 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">Multitarefa, monousuário<span class="_0 blank"></span>, gratuito<span class="_0 blank"></span>.</span></div><div class="t m0 x5 h5 ya ff3 fs3 fc1 sc0 ls1 ws1">Resposta: B</div><div class="t m0 x5 h5 yb ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h5 yc ff3 fs3 fc1 sc0 ls1 ws1">P<span class="_0 blank"></span>ar<span class="_4 blank"> </span>timos <span class="_3 blank"> </span>do <span class="_4 blank"> </span>pr<span class="_4 blank"> </span>incípio <span class="_4 blank"> </span>de <span class="_3 blank"> </span>que, <span class="_4 blank"> </span>atualmente, <span class="_4 blank"> </span>os <span class="_4 blank"> </span>sistemas <span class="_3 blank"> </span>operacionais <span class="_4 blank"> </span>não </div><div class="t m0 x6 h5 yd ff3 fs3 fc1 sc0 ls1 ws1">mais <span class="_1 blank"> </span>existem <span class="_3 blank"> </span>na <span class="_1 blank"> </span>condição <span class="_3 blank"> </span>de <span class="_1 blank"> </span>monotarefa <span class="_1 blank"> </span>(ex<span class="_0 blank"></span>ecução <span class="_1 blank"> </span>de <span class="_1 blank"> </span>uma <span class="_3 blank"> </span>atividade <span class="_1 blank"> </span>por </div><div class="t m0 x6 h4 ye ff3 fs3 fc1 sc0 ls1 ws1">vez), <span class="_4 blank"> </span>assim <span class="_4 blank"> </span>eliminamos <span class="_3 blank"> </span>as <span class="_3 blank"> </span>opções <span class="_4 blank"> </span><span class="ff2">a</span><span class="ls0"> e<span class="_0 blank"></span> <span class="ff2 ls1">c<span class="ff3">. <span class="_4 blank"> </span>Da <span class="_3 blank"> </span>mesma <span class="_3 blank"> </span>forma, <span class="_4 blank"> </span>por <span class="_3 blank"> </span>razões <span class="_4 blank"> </span>de <span class="_4 blank"> </span>in-</span></span></span></div><div class="t m0 x6 h4 yf ff3 fs3 fc1 sc0 ls1 ws1">tegração <span class="_8 blank"> </span>cada <span class="_8 blank"> </span>vez <span class="_9 blank"> </span>maior <span class="_8 blank"> </span>entre <span class="_8 blank"> </span>usuár<span class="_4 blank"> </span>ios, <span class="_8 blank"> </span>o <span class="_8 blank"> </span>termo <span class="_9 blank"> </span>monousuário <span class="_9 blank"> </span>(opção <span class="_8 blank"> </span><span class="ff2">d</span>) </div><div class="t m0 x6 h4 y10 ff3 fs3 fc1 sc0 ls1 ws1">também não é mais correto; assim a opção <span class="ff2">b</span> é a c<span class="_0 blank"></span>orreta.</div><div class="t m0 x3 h4 y11 ff2 fs3 fc0 sc0 ls1 ws1">2. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>esgranrio <span class="_1 blank"> </span>\u2013 <span class="_3 blank"> </span>adap.) <span class="_3 blank"> </span>A <span class="_1 blank"> </span>\ue01fgura <span class="_3 blank"> </span>mostra <span class="_1 blank"> </span>o <span class="_4 blank"> </span>Window<span class="_0 blank"></span>s <span class="_1 blank"> </span>Explorer <span class="_3 blank"> </span>sendo <span class="_1 blank"> </span>ex<span class="_0 blank"></span>e<span class="_4 blank"> </span>-</span></div><div class="t m0 x4 h5 y12 ff3 fs3 fc1 sc0 ls1 ws1">cutado <span class="_4 blank"> </span>no Window<span class="_0 blank"></span>s <span class="_3 blank"> </span>XP<span class="_a blank"></span>, <span class="_4 blank"> </span>em <span class="_4 blank"> </span>sua <span class="_4 blank"> </span>con\ue01fguração <span class="_4 blank"> </span>padrão, com <span class="_4 blank"> </span>o <span class="_4 blank"> </span>diretório <span class="_b blank"></span> </div><div class="t m0 x4 h5 y13 ff3 fs3 fc1 sc0 ls1 ws1">\u201cC: \P<span class="_0 blank"></span>rojetos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> selecionado<span class="_0 blank"></span>. </div><div class="t m1 x7 h6 y14 ff3 fs4 fc1 sc0 ls1 ws1">Ítalo Demarchi.</div><div class="t m0 x8 h7 y15 ff2 fs5 fc0 sc0 ls1 ws1">1 <span class="_8 blank"> </span><span class="ff3 fs6 fc1 v2">Educador T<span class="_0 blank"></span>écnico <span class="_9 blank"> </span>em </span></div><div class="t m0 x8 h8 y16 ff3 fs6 fc1 sc0 ls1 ws1">Processament<span class="_0 blank"></span>o de <span class="_0 blank"></span>Dados </div><div class="t m0 x8 h8 y17 ff3 fs6 fc1 sc0 ls1 ws1">pela Secretaria de Estado </div><div class="t m0 x8 h8 y18 ff3 fs6 fc1 sc0 ls1 ws1">da <span class="_d blank"> </span>Educação <span class="_d blank"> </span>de <span class="_d blank"> </span>Santa </div><div class="t m0 x8 h8 y19 ff3 fs6 fc1 sc0 ls1 ws1">Catarina (SED <span class="_0 blank"></span>- SC). Expe- </div><div class="t m0 x8 h8 y1a ff3 fs6 fc1 sc0 ls1 ws1">riência na <span class="_3 blank"> </span>de\ue01fnição, im-</div><div class="t m0 x8 h8 y1b ff3 fs6 fc1 sc0 ls1 ws1">plantação <span class="_4 blank"> </span>e <span class="_1 blank"> </span>auditoria <span class="_4 blank"> </span>de <span class="_e blank"></span> </div><div class="t m0 x8 h8 y1c ff3 fs6 fc1 sc0 ls1 ws1">processos e <span class="_1 blank"> </span>projetos <span class="_1 blank"> </span>di- </div><div class="t m0 x8 h8 y1d ff3 fs6 fc1 sc0 ls1 ws1">dáticos com foco da <span class="_4 blank"> </span>área </div><div class="t m0 x8 h8 y1e ff3 fs6 fc1 sc0 ls1 ws1">de <span class="_1 blank"> </span>TI <span class="_1 blank"> </span>(Tecnolog<span class="_0 blank"></span>ia da In-</div><div class="t m0 x8 h8 y1f ff3 fs6 fc1 sc0 ls1 ws1">formação), <span class="_f blank"> </span>bem <span class="_f blank"> </span>como </div><div class="t m0 x8 h8 y20 ff3 fs6 fc1 sc0 ls1 ws1">na elaboração <span class="_1 blank"> </span>de <span class="_1 blank"> </span>mate-</div><div class="t m0 x8 h8 y21 ff3 fs6 fc1 sc0 ls1 ws1">rial <span class="_8 blank"> </span>didático <span class="_8 blank"> </span>impresso <span class="_8 blank"> </span>e </div><div class="t m0 x8 h8 y22 ff4 fs6 fc1 sc0 ls1">on-line<span class="ff3 ws1"> <span class="_d blank"> </span>de <span class="_10 blank"> </span>Educação <span class="_d blank"> </span>a </span></div><div class="t m0 x8 h8 y23 ff3 fs6 fc1 sc0 ls1 ws1">Distância (EaD<span class="_0 blank"></span>). Coorde-</div><div class="t m0 x8 h8 y24 ff3 fs6 fc1 sc0 ls1 ws1">nador <span class="_3 blank"> </span>do <span class="_3 blank"> </span>Núcleo <span class="_3 blank"> </span>de <span class="_3 blank"> </span>Do-</div><div class="t m0 x8 h8 y25 ff3 fs6 fc1 sc0 ls1 ws1">cumentação <span class="_3 blank"> </span>e Educação </div><div class="t m0 x8 h8 y26 ff3 fs6 fc1 sc0 ls1 ws1">Corporativa <span class="_10 blank"> </span>da <span class="_10 blank"> </span>Benner </div><div class="t m0 x8 h8 y27 ff3 fs6 fc1 sc0 ls1 ws1">Solution. Professor horis-</div><div class="t m0 x8 h8 y28 ff3 fs6 fc1 sc0 ls1 ws1">ta <span class="_1 blank"> </span>na <span class="_3 blank"> </span>Faculdade <span class="_1 blank"> </span>SENA<span class="_0 blank"></span>C/</div><div class="t m0 x8 h8 y29 ff3 fs6 fc1 sc0 ls1">SC.</div><div class="t m0 x9 h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi xb y0 w2 ha" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg2.png"><div class="c xc y2c w3 h0"><div class="t m0 xd h9 y2d ff3 fs7 fc0 sc0 ls1">2</div><div class="t m0 xb h9 y2e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 xe h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xf h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x10 y2c w4 h0"><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x11 h5 y31 ff3 fs3 fc1 sc0 ls2 ws1">Sabe<span class="_4 blank"> </span>-se <span class="_1 blank"> </span>que <span class="_8 blank"> </span>o <span class="_8 blank"> </span>arquiv<span class="_0 blank"></span>o <span class="_8 blank"> </span>Atas <span class="_1 blank"> </span>está <span class="_8 blank"> </span>sendo <span class="_1 blank"> </span>editado <span class="_8 blank"> </span>neste <span class="_1 blank"> </span>momento <span class="_8 blank"> </span>pelo<span class="_0 blank"></span> </div><div class="t m0 x4 h5 y32 ff3 fs3 fc1 sc0 ls2 ws1">usuário <span class="_1 blank"> </span>através <span class="_1 blank"> </span>do <span class="_4 blank"> </span>Word <span class="_1 blank"> </span>2007, <span class="_1 blank"> </span>em <span class="_1 blank"> </span>sua <span class="_1 blank"> </span>con\ue01fguração <span class="_1 blank"> </span>padrão<span class="_0 blank"></span>. <span class="_1 blank"> </span>Sabendo<span class="_4 blank"> </span>-se </div><div class="t m0 x4 h5 y33 ff3 fs3 fc1 sc0 ls2 ws1">que <span class="_1 blank"> </span>não <span class="_1 blank"> </span>existe <span class="_1 blank"> </span>nenhum <span class="_1 blank"> </span>problema <span class="_1 blank"> </span>com <span class="_1 blank"> </span>o <span class="_1 blank"> </span>computador <span class="_1 blank"> </span>do <span class="_1 blank"> </span>usuário, <span class="_1 blank"> </span>o <span class="_1 blank"> </span>que </div><div class="t m0 x4 h5 y34 ff3 fs3 fc1 sc0 ls2 ws1">ocorrerá <span class="_3 blank"> </span>se <span class="_1 blank"> </span>ele <span class="_1 blank"> </span>tentar <span class="_3 blank"> </span>renomear <span class="_1 blank"> </span>o <span class="_3 blank"> </span>diretório \u201cC:\P<span class="_0 blank"></span>rojetos\u201d<span class="_e blank"></span> <span class="_1 blank"> </span>para \u201c<span class="_0 blank"></span>C:\Projetos<span class="_0 blank"></span> </div><div class="t m0 x4 h5 y35 ff3 fs3 fc1 sc0 ls2 ws2">Prioritários\u201d?</div><div class="t m0 x9 h4 y36 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">O <span class="_8 blank"> </span>computador <span class="_8 blank"> </span>irá <span class="_1 blank"> </span>reinicializar <span class="_8 blank"> </span>porque <span class="_8 blank"> </span>o <span class="_1 blank"> </span>W<span class="_0 blank"></span>indows <span class="_8 blank"> </span>XP <span class="_8 blank"> </span>não <span class="_8 blank"> </span>aceita </span></div><div class="t m0 x12 h5 y37 ff3 fs3 fc1 sc0 ls1 ws1">acentos no nome de dir<span class="_0 blank"></span>etórios.</div><div class="t m0 x9 h4 y38 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">O Windows <span class="_4 blank"> </span>Explorer <span class="_4 blank"> </span>será <span class="_4 blank"> </span>fechado <span class="_3 blank"> </span>automaticamente<span class="_0 blank"></span>, <span class="_3 blank"> </span>pois <span class="_4 blank"> </span>ele <span class="_3 blank"> </span>não </span></div><div class="t m0 x12 h5 y39 ff3 fs3 fc1 sc0 ls1 ws1">permite renomear o nome de diret<span class="_0 blank"></span>órios que já possuem arquivos.</div><div class="t m0 x9 h4 y3a ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">O <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório <span class="_1 blank"> </span>será <span class="_3 blank"> </span>renomeado <span class="_1 blank"> </span>e <span class="_3 blank"> </span>o <span class="_1 blank"> </span>arquiv<span class="_0 blank"></span>o <span class="_1 blank"> </span>Atas <span class="_3 blank"> </span>será <span class="_1 blank"> </span>mo<span class="_0 blank"></span>vido <span class="_1 blank"> </span>para <span class="_3 blank"> </span>a </span></div><div class="t m0 x12 h5 y3b ff3 fs3 fc1 sc0 ls1 ws0">lixeira.</div><div class="t m0 x9 h4 y3c ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">O dir<span class="_0 blank"></span>etório será <span class="_0 blank"></span>renomeado <span class="_0 blank"></span>e <span class="_0 blank"></span>um <span class="ff4">link</span> <span class="_0 blank"></span>para o <span class="_0 blank"></span>arquiv<span class="_0 blank"></span>o Atas <span class="_0 blank"></span>será <span class="_0 blank"></span>cria-</span></div><div class="t m0 x12 h5 y3d ff3 fs3 fc1 sc0 ls1 ws1">do na área de trabalho do <span class="_c blank"></span>Windows XP<span class="_a blank"></span>.</div><div class="t m0 x9 h4 y3e ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">O diret<span class="_0 blank"></span>ório não será renomeado <span class="_0 blank"></span>porque o ar<span class="_0 blank"></span>quivo Atas <span class="_0 blank"></span>está sendo </span></div><div class="t m0 x12 h5 y3f ff3 fs3 fc1 sc0 ls1 ws1">editado e uma mensagem de erro será apresen<span class="_0 blank"></span>tada.</div><div class="t m0 x11 h5 y40 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: E</div><div class="t m0 x11 h5 y41 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h4 y42 ff3 fs3 fc1 sc0 ls1 ws1">P<span class="_0 blank"></span>ar<span class="_4 blank"> </span>tindo <span class="_4 blank"> </span>da <span class="_4 blank"> </span>opção <span class="_4 blank"> </span><span class="ff2">e</span>, <span class="_3 blank"> </span>que <span class="_4 blank"> </span>está <span class="_4 blank"> </span>correta, <span class="_4 blank"> </span>além <span class="_4 blank"> </span>de <span class="_4 blank"> </span>não <span class="_4 blank"> </span>reiniciar <span class="_4 blank"> </span>(opção <span class="_4 blank"> </span><span class="ff2">a</span>), <span class="_4 blank"> </span>o </div><div class="t m0 x4 h4 y43 ff3 fs3 fc1 sc0 ls1 ws1">Windo<span class="_0 blank"></span>ws aceita acentuação em nomes <span class="_0 blank"></span>de diretórios. Na opção <span class="ff2">b</span> <span class="_0 blank"></span>é incorreta </div><div class="t m0 x4 h5 y44 ff3 fs3 fc1 sc0 ls1 ws1">a a\ue01frmação <span class="_4 blank"> </span>quanto a não <span class="_4 blank"> </span>renomear diretórios com arquivos<span class="_0 blank"></span>. <span class="_4 blank"> </span>Nenhum siste<span class="_4 blank"> </span>-</div><div class="t m0 x4 h4 y45 ff3 fs3 fc1 sc0 ls1 ws1">ma <span class="_4 blank"> </span>envia arquivos para a <span class="_4 blank"> </span>lixeira sem <span class="_4 blank"> </span>a <span class="_4 blank"> </span>interação do <span class="_4 blank"> </span>usuário (opção <span class="_4 blank"> </span><span class="ff2">c</span>), <span class="_4 blank"> </span>assim </div><div class="t m0 x4 h4 y46 ff3 fs3 fc1 sc0 ls1 ws1">como não é criado <span class="ff4">link</span> automático ao r<span class="_0 blank"></span>enomear itens (opção <span class="ff2">d</span>).</div><div class="t m0 x13 h4 y47 ff2 fs3 fc0 sc0 ls3 ws1">3. <span class="_7 blank"> </span><span class="ff3 fc1">(<span class="_0 blank"></span>Cesgranrio) Qual dos itens abaix<span class="_0 blank"></span>o apresenta uma memória dinâmica?</span></div><div class="t m0 x9 h4 y48 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1 ws0">CD<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y49 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1 ws0">Eeprom.</span></div><div class="t m0 x9 h4 y4a ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1 ws0">Flash.</span></div><div class="t m0 x9 h4 y4b ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1 ws0">RAM.</span></div><div class="t m0 x9 h4 y4c ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1 ws0">ROM.</span></div><div class="t m0 x11 h5 y4d ff3 fs3 fc1 sc0 ls1 ws1">Resposta: D</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x14 y0 w5 hb" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg3.png"><div class="c xc y2c w4 h0"><div class="t m0 x15 h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 x16 h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x17 y2c w3 h0"><div class="t m0 x18 h9 y4e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 x19 h9 y4f ff3 fs7 fc0 sc0 ls1">3</div><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x5 h5 y31 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h5 y50 ff3 fs3 fc1 sc0 ls1 ws1">A memória dinâmica é a mais bara<span class="_0 blank"></span>ta entre elas e, portanto<span class="_0 blank"></span>, a mais utiliza-</div><div class="t m0 x6 h5 y51 ff3 fs3 fc1 sc0 ls1 ws1">da nos <span class="_4 blank"> </span>computadores. São <span class="_4 blank"> </span>popularmente conhecidas <span class="_4 blank"> </span>como memórias <span class="_4 blank"> </span>RAM </div><div class="t m0 x6 h4 y52 ff3 fs3 fc1 sc0 ls1 ws1">(opção <span class="_1 blank"> </span><span class="ff2">d</span>). <span class="_1 blank"> </span>O <span class="_1 blank"> </span>CD <span class="_1 blank"> </span>(opção <span class="_1 blank"> </span><span class="ff2">a</span>) <span class="_1 blank"> </span>é <span class="_3 blank"> </span>uma <span class="_1 blank"> </span>memória <span class="_1 blank"> </span>de <span class="_1 blank"> </span>armazenamento <span class="_1 blank"> </span>em <span class="_1 blank"> </span>massa, </div><div class="t m0 x6 h5 y53 ff3 fs3 fc1 sc0 ls1 ws1">pode <span class="_4 blank"> </span>ser <span class="_3 blank"> </span>gravado <span class="_4 blank"> </span>pelo <span class="_3 blank"> </span>usuário <span class="_3 blank"> </span>sempre <span class="_4 blank"> </span>que <span class="_3 blank"> </span>necessário<span class="_0 blank"></span>. <span class="_3 blank"> </span>Já <span class="_3 blank"> </span>a <span class="_4 blank"> </span>Eeprom <span class="_3 blank"> </span>(opção </div><div class="t m0 x6 h4 y36 ff2 fs3 fc1 sc0 ls1">b<span class="ff3 ws1">) <span class="_4 blank"> </span>é <span class="_3 blank"> </span>interna <span class="_4 blank"> </span>no <span class="_3 blank"> </span>computador<span class="_0 blank"></span>, <span class="_4 blank"> </span>pode <span class="_3 blank"> </span>ser <span class="_3 blank"> </span>grav<span class="_0 blank"></span>ada, <span class="_3 blank"> </span>apagada <span class="_3 blank"> </span>ou <span class="_4 blank"> </span>regravada <span class="_4 blank"> </span>utili-</span></div><div class="t m0 x6 h5 y37 ff3 fs3 fc1 sc0 ls1 ws1">zando um <span class="_4 blank"> </span>equipamento que fornece <span class="_4 blank"> </span>as voltagens adequadas <span class="_4 blank"> </span>em cada <span class="_4 blank"> </span>pino </div><div class="t m0 x6 h4 y54 ff3 fs3 fc1 sc0 ls1 ws1">(conector). <span class="_3 blank"> </span>Na <span class="_1 blank"> </span>opção <span class="_3 blank"> </span><span class="ff2">c</span> <span class="_1 blank"> </span>temos <span class="_3 blank"> </span>a <span class="_1 blank"> </span>memória <span class="_3 blank"> </span>Flash, <span class="_3 blank"> </span>ou <span class="_1 blank"> </span>não <span class="_3 blank"> </span>volátil, <span class="_3 blank"> </span>pois <span class="_1 blank"> </span>guar<span class="_0 blank"></span>da </div><div class="t m0 x6 h5 y55 ff3 fs3 fc1 sc0 ls1 ws1">todas <span class="_1 blank"> </span>as <span class="_3 blank"> </span>informações <span class="_1 blank"> </span>mesmo <span class="_3 blank"> </span>quando <span class="_1 blank"> </span>não <span class="_1 blank"> </span>estiver <span class="_3 blank"> </span>recebendo <span class="_1 blank"> </span>energ<span class="_0 blank"></span>ia; <span class="_1 blank"> </span>e <span class="_1 blank"> </span>na </div><div class="t m0 x6 h4 y56 ff3 fs3 fc1 sc0 ls1 ws1">opção <span class="_1 blank"> </span><span class="ff2">e</span>, <span class="_8 blank"> </span>a <span class="_1 blank"> </span>memória <span class="_1 blank"> </span>ROM <span class="_8 blank"> </span>é <span class="_1 blank"> </span>do <span class="_1 blank"> </span>tipo <span class="_8 blank"> </span>soment<span class="_0 blank"></span>e <span class="_8 blank"> </span>para <span class="_1 blank"> </span>leitura, <span class="_1 blank"> </span>seu <span class="_1 blank"> </span>conteúdo <span class="_1 blank"> </span>é </div><div class="t m0 x6 h5 y57 ff3 fs3 fc1 sc0 ls1 ws1">grav<span class="_0 blank"></span>ado uma única vez, direto de fábrica.</div><div class="t m0 x3 h4 y58 ff2 fs3 fc0 sc0 ls1 ws1">4. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>esgranrio) <span class="_4 blank"> </span>Em <span class="_4 blank"> </span>um <span class="_4 blank"> </span>microcomputador com Windo<span class="_0 blank"></span>ws <span class="_4 blank"> </span>XP <span class="_4 blank"> </span>em <span class="_4 blank"> </span>sua <span class="_4 blank"> </span>con-</span></div><div class="t m0 x4 h5 y59 ff3 fs3 fc1 sc0 ls1 ws1">\ue01fguração padrão<span class="_0 blank"></span>, se um usuário aumentar a resolução da tela</div><div class="t m0 x4 h4 y5a ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">mais itens caberão na tela, mas esses it<span class="_0 blank"></span>ens reduzirão de tamanho.</span></div><div class="t m0 x4 h4 y5b ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">mais itens caberão na tela e esses it<span class="_0 blank"></span>ens aumentarão de tamanho.</span></div><div class="t m0 x4 h4 y5c ff2 fs3 fc0 sc0 ls4 ws1">c) <span class="_11 blank"> </span><span class="ff3 fc1">menos itens caberão na tela, mas esses it<span class="_0 blank"></span>ens aumentarão de tamanho.</span></div><div class="t m0 x4 h4 y5d ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">menos itens caberão na tela e esses itens r<span class="_0 blank"></span>eduzirão de tamanho.</span></div><div class="t m0 x4 h4 y5e ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">o <span class="_0 blank"></span>número <span class="_0 blank"></span>de it<span class="_0 blank"></span>ens pr<span class="_0 blank"></span>esentes <span class="_0 blank"></span>na t<span class="_0 blank"></span>ela permanecerá <span class="_c blank"></span>o mesmo<span class="_0 blank"></span>, <span class="_0 blank"></span>e ape-</span></div><div class="t m0 x0 h5 y5f ff3 fs3 fc1 sc0 ls1 ws1">nas a qualidade das imagens será afetada.</div><div class="t m0 x5 h5 y44 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: A</div><div class="t m0 x5 h5 y60 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h5 y61 ff3 fs3 fc1 sc0 ls1 ws1">Aumentar <span class="_4 blank"> </span>a <span class="_3 blank"> </span>resolução <span class="_4 blank"> </span>quer <span class="_3 blank"> </span>dizer <span class="_4 blank"> </span>diminuir <span class="_3 blank"> </span>o <span class="_3 blank"> </span>tamanho <span class="_3 blank"> </span>dos <span class="_3 blank"> </span><span class="ff4 ws3">pixels</span> <span class="_4 blank"> </span>(pontos </div><div class="t m0 x6 h5 y62 ff3 fs3 fc1 sc0 ls1 ws1">da <span class="_4 blank"> </span>tela <span class="_4 blank"> </span>que <span class="_4 blank"> </span>formam <span class="_4 blank"> </span>a <span class="_4 blank"> </span>imagem), <span class="_4 blank"> </span>logo, <span class="_4 blank"> </span>os <span class="_4 blank"> </span>itens <span class="_4 blank"> </span>diminuirão <span class="_4 blank"> </span>também, <span class="_4 blank"> </span>pois <span class="_4 blank"> </span>são </div><div class="t m0 x6 h5 y48 ff3 fs3 fc1 sc0 ls1 ws1">originalmente <span class="_3 blank"> </span>elaborados <span class="_1 blank"> </span>com <span class="_3 blank"> </span>cer<span class="_4 blank"> </span>to <span class="_1 blank"> </span>número <span class="_3 blank"> </span>de <span class="_1 blank"> </span>pontos<span class="_0 blank"></span>. <span class="_1 blank"> </span>Como <span class="_1 blank"> </span>a <span class="_3 blank"> </span>tela <span class="_1 blank"> </span>é <span class="_3 blank"> </span>do </div><div class="t m0 x6 h5 y63 ff3 fs3 fc1 sc0 ls1 ws1">mesmo <span class="_1 blank"> </span>tamanho <span class="_1 blank"> </span>físico, <span class="_1 blank"> </span>com <span class="_1 blank"> </span>menos <span class="_1 blank"> </span>pontos <span class="_1 blank"> </span>caberão <span class="_1 blank"> </span>mais, <span class="_1 blank"> </span>e <span class="_1 blank"> </span>assim <span class="_1 blank"> </span>sobrará </div><div class="t m0 x6 h4 y64 ff3 fs3 fc1 sc0 ls1 ws1">espaço para mais itens<span class="_0 blank"></span>. A alternativa correta é a opção <span class="ff2">a</span>.</div><div class="t m0 x3 h4 y65 ff2 fs3 fc0 sc0 ls1 ws1">5. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>esgranrio \u2013 <span class="_9 blank"> </span>adap<span class="_0 blank"></span>.) Sobre <span class="_9 blank"> </span>os <span class="_12 blank"> </span>aspectos <span class="_12 blank"> </span>de <span class="_12 blank"> </span>segurança <span class="_9 blank"> </span>dos sistemas </span></div><div class="t m0 x4 h5 y66 ff3 fs3 fc1 sc0 ls1 ws1">computacionais, são f<span class="_0 blank"></span>eitas as a\ue01frmativas abaixo<span class="_0 blank"></span>.</div><div class="t m0 x5 h5 y67 ff3 fs3 fc1 sc0 ls1 ws1">I. A palavra <span class="ff4 ws3">windows</span> é um e<span class="_0 blank"></span>xemplo de senha forte.</div><div class="t m0 x5 h5 y68 ff3 fs3 fc1 sc0 ls1 ws1">II. <span class="ff4 ws3">Ransomw<span class="_0 blank"></span>are<span class="ff3 ws1"> é um tipo de </span>malware<span class="ff3">.</span></span></div><div class="t m0 x5 h5 y69 ff3 fs3 fc1 sc0 ls3 ws1">III. Os <span class="ff4 ws4">trojans</span> são antivírus que pr<span class="_0 blank"></span>otegem as macros do Excel c<span class="_0 blank"></span>ontra vírus.</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi xb y0 w2 ha" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg4.png"><div class="c xc y2c w3 h0"><div class="t m0 xd h9 y2d ff3 fs7 fc0 sc0 ls1">4</div><div class="t m0 xb h9 y2e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 xe h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xf h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x10 y2c w4 h0"><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x11 h5 y31 ff3 fs3 fc1 sc0 ls1 ws1">Está(ão) correta(s) a(s) a\ue01frmativa(s)</div><div class="t m0 x9 h4 y50 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">I, apenas. </span></div><div class="t m0 x9 h4 y6a ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">II, apenas.</span></div><div class="t m0 x9 h4 y6b ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">III, apenas. </span></div><div class="t m0 x9 h4 y6c ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">I e II, apenas.</span></div><div class="t m0 x9 h4 y6d ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">I, II e III.</span></div><div class="t m0 x11 h5 y6e ff3 fs3 fc1 sc0 ls1 ws1">Resposta: B</div><div class="t m0 x11 h5 y6f ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h5 y70 ff3 fs3 fc1 sc0 ls3 ws1">A a\ue01frmativa I é incorreta, pois não leva em conta a sugestão da própria Mi<span class="ls1">-</span></div><div class="t m0 x4 h5 y71 ff3 fs3 fc1 sc0 ls3 ws1">crosoft, <span class="_4 blank"> </span>como <span class="_3 blank"> </span>possuir <span class="_4 blank"> </span>pelo <span class="_3 blank"> </span>menos <span class="_3 blank"> </span>oito <span class="_4 blank"> </span>caracteres, <span class="_4 blank"> </span>obrigatoriamente <span class="_4 blank"> </span>misturar </div><div class="t m0 x4 h5 y72 ff3 fs3 fc1 sc0 ls3 ws1">letras <span class="_0 blank"></span>e númer<span class="_0 blank"></span>os e <span class="_0 blank"></span>não <span class="_0 blank"></span>conter <span class="_0 blank"></span>palavras <span class="_0 blank"></span>completas. <span class="_0 blank"></span>A a\ue01frmativa <span class="_c blank"></span>II é <span class="_0 blank"></span>correta, <span class="_0 blank"></span><span class="ff4 ls5 ws5">ra n <span class="ls1">-</span></span></div><div class="t m0 x4 h5 y73 ff4 fs3 fc1 sc0 ls3 ws4">somw<span class="_0 blank"></span>are<span class="ff3 ws1"> <span class="_4 blank"> </span>é um tipo <span class="_4 blank"> </span>de </span>malware<span class="ff3 ws1"> que se refere aos cavalos de troia que cobram </span></div><div class="t m0 x4 h5 y74 ff3 fs3 fc1 sc0 ls3 ws1">resgate <span class="_3 blank"> </span>pelos <span class="_1 blank"> </span>dados; <span class="_1 blank"> </span>já <span class="_1 blank"> </span>a <span class="_1 blank"> </span>a\ue01frmativa <span class="_3 blank"> </span>III <span class="_1 blank"> </span>é <span class="_1 blank"> </span>falsa, <span class="_1 blank"> </span>pois <span class="_4 blank"> </span>T<span class="_0 blank"></span>rojan <span class="_1 blank"> </span>é <span class="_3 blank"> </span>um <span class="_1 blank"> </span>tipo <span class="_1 blank"> </span>de <span class="_1 blank"> </span>vírus </div><div class="t m0 x4 h5 y75 ff3 fs3 fc1 sc0 ls1 ws1">usa<span class="_0 blank"></span>do <span class="_c blank"></span>ger<span class="_0 blank"></span>alme<span class="_0 blank"></span>nte <span class="_c blank"></span>par<span class="_0 blank"></span>a <span class="_c blank"></span>inv<span class="_0 blank"></span>asão<span class="_0 blank"></span> <span class="_0 blank"></span>de <span class="_c blank"></span>out<span class="_0 blank"></span>ro <span class="_c blank"></span>co<span class="_0 blank"></span>mput<span class="_0 blank"></span>ador <span class="_c blank"></span>co<span class="_0 blank"></span>m <span class="_0 blank"></span>o <span class="_c blank"></span>obj<span class="_0 blank"></span>etiv<span class="_0 blank"></span>o <span class="_c blank"></span>de <span class="_c blank"></span>pegar </div><div class="t m0 x4 h4 y76 ff3 fs3 fc1 sc0 ls3 ws1">senhas ou outras informações<span class="_0 blank"></span>. Assim, a opção <span class="ff2 ls1 ws6">b</span> é a resposta corr<span class="_0 blank"></span>eta.</div><div class="t m0 x13 h4 y77 ff2 fs3 fc0 sc0 ls1 ws1">6. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>esgranrio<span class="_4 blank"> </span> \u2013 adap.) C<span class="_0 blank"></span>onsidere o texto a seguir sobre chaves em siste-</span></div><div class="t m0 x9 h5 y78 ff3 fs3 fc1 sc0 ls1 ws1">mas de segurança.</div><div class="t m0 x11 h5 y79 ff3 fs3 fc1 sc0 ls1 ws1">A criptogra\ue01fa ____________ <span class="_4 blank"> </span>é <span class="_4 blank"> </span>um método que <span class="_4 blank"> </span>utiliza um <span class="_4 blank"> </span>par <span class="_4 blank"> </span>de chaves: </div><div class="t m0 x4 h5 y7a ff3 fs3 fc1 sc0 ls1 ws1">uma pública e <span class="_0 blank"></span>uma privada. P<span class="_0 blank"></span>ara ___________, a <span class="_0 blank"></span>chave pública <span class="_0 blank"></span>é usada para </div><div class="t m0 x4 h5 y7b ff3 fs3 fc1 sc0 ls1 ws1">cifrar mensagens e, com isso<span class="_0 blank"></span>, apenas o dono da chave privada pode decifrá-</div><div class="t m0 x4 h5 y7c ff3 fs3 fc1 sc0 ls1 ws1">la. <span class="_0 blank"></span>Para <span class="_0 blank"></span>____________, <span class="_0 blank"></span>a cha<span class="_0 blank"></span>ve <span class="_0 blank"></span>privada é <span class="_0 blank"></span>usada <span class="_0 blank"></span>para cifr<span class="_0 blank"></span>ar mensagens <span class="_0 blank"></span>e, <span class="_0 blank"></span>com </div><div class="t m0 x4 h5 y61 ff3 fs3 fc1 sc0 ls1 ws1">isso<span class="_0 blank"></span>, <span class="_1 blank"> </span>garante-se <span class="_1 blank"> </span>que <span class="_3 blank"> </span>apenas <span class="_1 blank"> </span>o <span class="_3 blank"> </span>dono <span class="_1 blank"> </span>da <span class="_3 blank"> </span>chave <span class="_3 blank"> </span>privada <span class="_1 blank"> </span>poderia <span class="_1 blank"> </span>t<span class="_0 blank"></span>er <span class="_1 blank"> </span>cifrado <span class="_3 blank"> </span>a </div><div class="t m0 x4 h5 y62 ff3 fs3 fc1 sc0 ls1 ws1">mensagem que foi decifrada c<span class="_0 blank"></span>om a chave pública.</div><div class="t m0 x11 h5 y7d ff3 fs3 fc1 sc0 ls1 ws1">As palavras que c<span class="_0 blank"></span>ompletam corretamente a frase acima são:</div><div class="t m0 x9 h4 y7e ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">assimétrica, autenticidade e con\ue01fdencialidade<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y7f ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">assimétrica, con\ue01fdencialidade e autenticidade<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y80 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">simétrica, autenticidade e con\ue01fdencialidade<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y81 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">simétrica, autenticidade e não repúdio<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y82 ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">simétrica, con\ue01fdencialidade e não repúdio<span class="_0 blank"></span>.</span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf5" class="pf w0 h0" data-page-no="5"><div class="pc pc5 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x14 y0 w5 hb" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg5.png"><div class="c xc y2c w4 h0"><div class="t m0 x15 h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 x16 h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x17 y2c w3 h0"><div class="t m0 x18 h9 y4e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 x19 h9 y4f ff3 fs7 fc0 sc0 ls1">5</div><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x5 h5 y31 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: A</div><div class="t m0 x5 h5 y50 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h5 y6a ff3 fs3 fc1 sc0 ls6 ws1">O <span class="_4 blank"> </span>melhor <span class="_3 blank"> </span>modo <span class="_3 blank"> </span>para <span class="_3 blank"> </span>compreender <span class="_4 blank"> </span>a <span class="_3 blank"> </span>criptogra\ue01fa <span class="_4 blank"> </span>assimétrica <span class="_3 blank"> </span>é <span class="_3 blank"> </span>imagi<span class="ls1">-</span></div><div class="t m0 x6 h5 y83 ff3 fs3 fc1 sc0 ls6 ws1">nar <span class="_0 blank"></span>uma caixa <span class="_0 blank"></span>com <span class="_0 blank"></span>uma <span class="_0 blank"></span>fechadura <span class="_0 blank"></span>que aceita <span class="_c blank"></span>duas chav<span class="_0 blank"></span>es dif<span class="_0 blank"></span>erentes: <span class="_0 blank"></span>uma </div><div class="t m0 x6 h5 y84 ff3 fs3 fc1 sc0 ls6 ws1">chave <span class="_4 blank"> </span>só <span class="_3 blank"> </span>ser<span class="_4 blank"> </span>ve <span class="_4 blank"> </span>para <span class="_3 blank"> </span>trancar <span class="_3 blank"> </span>a <span class="_3 blank"> </span>caixa <span class="_3 blank"> </span>e <span class="_3 blank"> </span>a <span class="_3 blank"> </span>outra <span class="_3 blank"> </span>somente <span class="_3 blank"> </span>para <span class="_3 blank"> </span>abri-la. <span class="_3 blank"> </span>Qual<span class="ls1">-</span></div><div class="t m0 x6 h5 y85 ff3 fs3 fc1 sc0 ls6 ws1">quer <span class="_0 blank"></span>um <span class="_0 blank"></span>que tiv<span class="_0 blank"></span>er uma <span class="_c blank"></span>cópia da <span class="_c blank"></span>chave <span class="_0 blank"></span>que <span class="_0 blank"></span>tranca <span class="_0 blank"></span>a caixa <span class="_c blank"></span>(a cha<span class="_0 blank"></span>ve <span class="_0 blank"></span>pública) </div><div class="t m0 x6 h5 y86 ff3 fs3 fc1 sc0 ls6 ws1">pode <span class="_1 blank"> </span>c<span class="_0 blank"></span>olocar <span class="_1 blank"> </span>itens <span class="_3 blank"> </span>nessa <span class="_1 blank"> </span>caixa. <span class="_3 blank"> </span>Como <span class="_1 blank"> </span>somente <span class="_3 blank"> </span>você <span class="_3 blank"> </span>possui <span class="_1 blank"> </span>a <span class="_3 blank"> </span>chave <span class="_1 blank"> </span>que<span class="_0 blank"></span> </div><div class="t m0 x6 h5 y38 ff3 fs3 fc1 sc0 ls6 ws1">abre <span class="_1 blank"> </span>a <span class="_3 blank"> </span>caixa <span class="_1 blank"> </span>(chave <span class="_1 blank"> </span>privada), <span class="_1 blank"> </span>ninguém <span class="_3 blank"> </span>mais <span class="_1 blank"> </span>pode <span class="_1 blank"> </span>bisbilhotar <span class="_1 blank"> </span>o <span class="_1 blank"> </span>seu <span class="_1 blank"> </span>con<span class="ls1">-</span></div><div class="t m0 x6 h5 y39 ff3 fs3 fc1 sc0 ls6 ws1">teúdo<span class="_0 blank"></span>. Isso <span class="_4 blank"> </span>é difer<span class="_0 blank"></span>ente da criptogra\ue01fa simétrica, na <span class="_4 blank"> </span>qual a mesma chave é </div><div class="t m0 x6 h5 y87 ff3 fs3 fc1 sc0 ls6 ws1">usada tanto para <span class="_0 blank"></span>trancar quanto para abrir a caixa. A<span class="_0 blank"></span>ssim, a opção correta </div><div class="t m0 x6 h4 y88 ff3 fs3 fc1 sc0 ls6 ws1">é a <span class="ff2">a</span><span class="ls1">.</span></div><div class="t m0 x3 h4 y89 ff2 fs3 fc0 sc0 ls1 ws1">7. <span class="_2 blank"> </span><span class="ff3 fc1">(C<span class="_0 blank"></span>espe) <span class="_8 blank"> </span>Considere <span class="_8 blank"> </span>a <span class="_8 blank"> </span>con\ue01fguração <span class="_8 blank"> </span>de <span class="_8 blank"> </span>um <span class="_8 blank"> </span>microcomputador <span class="_8 blank"> </span>do <span class="_8 blank"> </span>tipo </span></div><div class="t m0 x4 h5 y8a ff4 fs3 fc1 sc0 ls1 ws1">notebook <span class="ff3">apresentada a seguir<span class="_c blank"></span>.</span></div><div class="t m0 x5 h5 y8b ff3 fs3 fc1 sc0 ls1 ws1">Intel Core Duo \u2013 1,6GHz e 533MHz FSB;</div><div class="t m0 x5 h5 y3f ff3 fs3 fc1 sc0 ls1 ws1">2MB L2 cache;</div><div class="t m0 x5 h5 y40 ff3 fs3 fc1 sc0 ls1 ws1">15,4 <span class="_0 blank"></span>WX<span class="_0 blank"></span>GA LCD;</div><div class="t m0 x5 h5 y41 ff3 fs3 fc1 sc0 ls1 ws1">120GB HDD;</div><div class="t m0 x5 h5 y42 ff3 fs3 fc1 sc0 ls1 ws1">DVD-R<span class="_4 blank"> </span>W <span class="ff4">double layer</span>;</div><div class="t m0 x5 h5 y8c ff3 fs3 fc1 sc0 ls1 ws1">1GB DDR2, 802.11 a/b/g <span class="ff4 ws3">wireless</span> LAN.</div><div class="t m0 x5 h5 y7b ff3 fs3 fc1 sc0 ls1 ws1">Com base na con\ue01fguração apr<span class="_0 blank"></span>esentada, assinale a opção correta.</div><div class="t m0 x4 h4 y8d ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">Intel <span class="_1 blank"> </span>C<span class="_0 blank"></span>ore <span class="_1 blank"> </span>Duo <span class="_3 blank"> </span>indica <span class="_1 blank"> </span>que <span class="_1 blank"> </span>há <span class="_3 blank"> </span>dois <span class="_1 blank"> </span>processador<span class="_0 blank"></span>es <span class="_1 blank"> </span>no <span class="_3 blank"> </span>mesmo <span class="_1 blank"> </span><span class="ff4">chip</span> </span></div><div class="t m0 x0 h5 y8e ff3 fs3 fc1 sc0 ls1 ws1">de silício<span class="_0 blank"></span>.</div><div class="t m0 x4 h4 y8f ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">1,6GHz indica que o pr<span class="_0 blank"></span>ocessador possui capacidade de armaz<span class="_0 blank"></span>ena-</span></div><div class="t m0 x0 h5 y90 ff3 fs3 fc1 sc0 ls1 ws1">mento de dados de 1 600MB<span class="_0 blank"></span>.</div><div class="t m0 x4 h4 y91 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">Intel C<span class="_0 blank"></span>ore Duo indica <span class="_0 blank"></span>a existência <span class="_0 blank"></span>de memória dupla, <span class="_0 blank"></span>o que amplia </span></div><div class="t m0 x0 h5 y7f ff3 fs3 fc1 sc0 ls1 ws1">a velocidade de proc<span class="_0 blank"></span>essamento das informações.</div><div class="t m0 x4 h4 y80 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">533MHz FSB indica a capacidade da memória RAM.</span></div><div class="t m0 x5 h5 y81 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: A</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf6" class="pf w0 h0" data-page-no="6"><div class="pc pc6 w0 h0"><img fetchpriority="low" loading="lazy" class="bi xb y0 w2 ha" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg6.png"><div class="c xc y2c w3 h0"><div class="t m0 xd h9 y2d ff3 fs7 fc0 sc0 ls1">6</div><div class="t m0 xb h9 y2e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 xe h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xf h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x10 y2c w4 h0"><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x11 h5 y31 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h4 y50 ff3 fs3 fc1 sc0 ls1 ws1">A <span class="_8 blank"> </span>opção <span class="_9 blank"> </span>correta <span class="_8 blank"> </span>é <span class="_8 blank"> </span>a <span class="_9 blank"> </span>alternativa <span class="_8 blank"> </span><span class="ff2">a</span>, <span class="_8 blank"> </span>dois <span class="_9 blank"> </span>processadores <span class="_8 blank"> </span>no <span class="_8 blank"> </span>mesmo <span class="_9 blank"> </span><span class="ff4">chip</span>. </div><div class="t m0 x4 h5 y51 ff3 fs3 fc1 sc0 ls1 ws1">1,6GHz <span class="_3 blank"> </span>indica <span class="_1 blank"> </span>a <span class="_4 blank"> </span>velocidade <span class="_3 blank"> </span>de <span class="_3 blank"> </span>processamento<span class="_0 blank"></span>, <span class="_3 blank"> </span>não <span class="_3 blank"> </span>tem <span class="_3 blank"> </span>relação <span class="_3 blank"> </span>com <span class="_3 blank"> </span>arma-</div><div class="t m0 x4 h4 y52 ff3 fs3 fc1 sc0 ls1 ws1">zenamento <span class="_1 blank"> </span>(opção <span class="_1 blank"> </span><span class="ff2">b</span>). <span class="_8 blank"> </span>Refer<span class="_0 blank"></span>ente <span class="_1 blank"> </span>à <span class="_8 blank"> </span>opção <span class="_1 blank"> </span><span class="ff2">c</span>, <span class="_8 blank"> </span>a <span class="_1 blank"> </span>memória <span class="_8 blank"> </span>pode <span class="_1 blank"> </span>ser <span class="_1 blank"> </span><span class="ff4 ws3">cache</span> <span class="_1 blank"> </span>ou </div><div class="t m0 x4 h4 y53 ff3 fs3 fc1 sc0 ls1 ws1">RAM; e, <span class="_0 blank"></span>novamente, <span class="_0 blank"></span>a opção <span class="ff2">d</span> se <span class="_0 blank"></span>refere <span class="_0 blank"></span>à memória RAM, nessa c<span class="_0 blank"></span>on\ue01fguração </div><div class="t m0 x4 h5 y36 ff3 fs3 fc1 sc0 ls1 ws1">possui 1GB de capacidade de memória.</div><div class="t m0 x13 h4 y86 ff2 fs3 fc0 sc0 ls1 ws1">8. <span class="_2 blank"> </span><span class="ff3 fc1">Com <span class="_1 blank"> </span>referência <span class="_1 blank"> </span>ao <span class="_8 blank"> </span>microcomputador <span class="_8 blank"> </span>apr<span class="_0 blank"></span>esentado, <span class="_1 blank"> </span>assinale <span class="_8 blank"> </span>a <span class="_8 blank"> </span>opção </span></div><div class="t m0 x9 h5 y38 ff3 fs3 fc1 sc0 ls1 ws0">correta.</div><div class="t m0 x9 h4 y92 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">A capacidade do disco rígido<span class="_0 blank"></span>, na referida con\ue01fguração<span class="_0 blank"></span>, é de 1GB.</span></div><div class="t m0 x9 h4 y93 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">2MB L2 <span class="ff4 ws3">cache</span> <span class="_0 blank"></span>indica a capacidade da memória <span class="ff4 ws3">cache</span>, uma memó-</span></div><div class="t m0 x12 h5 y94 ff3 fs3 fc1 sc0 ls1 ws1">ria <span class="_8 blank"> </span>estática <span class="_1 blank"> </span>que <span class="_1 blank"> </span>tem <span class="_8 blank"> </span>por <span class="_1 blank"> </span>\ue01fnalidade <span class="_8 blank"> </span>aumentar <span class="_1 blank"> </span>o <span class="_8 blank"> </span>desempenho <span class="_1 blank"> </span>do </div><div class="t m0 x12 h5 y3c ff3 fs3 fc1 sc0 ls1 ws1">processador ao r<span class="_0 blank"></span>ealizar busca antecipada na memória RAM.</div><div class="t m0 x9 h4 y95 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">A opção DVD-R<span class="_4 blank"> </span>W signi\ue01fca que é possível gra<span class="_0 blank"></span>var e ler de ambos <span class="_4 blank"> </span>os </span></div><div class="t m0 x12 h5 y3e ff3 fs3 fc1 sc0 ls1 ws1">lados do disco<span class="_0 blank"></span>.</div><div class="t m0 x9 h4 y96 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">A <span class="_0 blank"></span>utilização <span class="_0 blank"></span>de <span class="_0 blank"></span>dispositivos <span class="_c blank"></span>do <span class="_0 blank"></span>tipo <span class="_0 blank"></span><span class="ff4 ws3">pendrive<span class="ff3 ws1"> <span class="_0 blank"></span>permite <span class="_0 blank"></span>ampliar<span class="_c blank"></span>, ainda </span></span></span></div><div class="t m0 x12 h5 y40 ff3 fs3 fc1 sc0 ls1 ws1">que temporariamente<span class="_0 blank"></span>, a capacidade da memória ROM do compu-</div><div class="t m0 x12 h5 y5d ff3 fs3 fc1 sc0 ls1 ws0">tador<span class="_c blank"></span>.</div><div class="t m0 x11 h5 y5e ff3 fs3 fc1 sc0 ls1 ws1">Resposta: B</div><div class="t m0 x11 h5 y43 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h5 y97 ff3 fs3 fc1 sc0 ls1 ws1">Quando se fala em <span class="_4 blank"> </span>disco<span class="_0 blank"></span>, é comum a <span class="_4 blank"> </span>utilização de HD ou HDD (<span class="ff4 ws3">Hard</span><span class="ls7"> </span><span class="ff4 ws3">Disk</span> </div><div class="t m0 x4 h4 y60 ff3 fs3 fc1 sc0 ls1 ws1">ou <span class="_1 blank"> </span><span class="ff4">Hard <span class="_1 blank"> </span>D<span class="_4 blank"> </span>isk <span class="_1 blank"> </span>Drive</span>) <span class="_1 blank"> </span>aqui <span class="_8 blank"> </span>de <span class="_1 blank"> </span>120GB. <span class="_8 blank"> </span>A <span class="_1 blank"> </span>opção <span class="_8 blank"> </span><span class="ff2">b</span> <span class="_1 blank"> </span>está <span class="_8 blank"> </span>correta <span class="_1 blank"> </span>quando <span class="_1 blank"> </span>indica </div><div class="t m0 x4 h4 y98 ff3 fs3 fc1 sc0 ls1 ws1">memória <span class="ff4 ws3">cache.</span> DVD-R<span class="_4 blank"> </span>W (opção <span class="_4 blank"> </span><span class="ff2">c</span>) indica que <span class="_4 blank"> </span>é regrav<span class="_0 blank"></span>ável (<span class="ff4 ws3">ReWriter</span>). A me<span class="_4 blank"> </span>-</div><div class="t m0 x4 h4 y47 ff3 fs3 fc1 sc0 ls1 ws1">mória <span class="_8 blank"> </span>ROM <span class="_8 blank"> </span>(opção <span class="_8 blank"> </span><span class="ff2">d</span>) <span class="_1 blank"> </span>é <span class="_8 blank"> </span>interna, <span class="_8 blank"> </span>não <span class="_8 blank"> </span>sendo <span class="_1 blank"> </span>possível <span class="_8 blank"> </span>ampliação <span class="_8 blank"> </span>por <span class="_8 blank"> </span>meios </div><div class="t m0 x4 h5 y99 ff3 fs3 fc1 sc0 ls1 ws0">removív<span class="_0 blank"></span>eis.</div><div class="t m0 x13 h4 y63 ff2 fs3 fc0 sc0 ls1 ws1">9. <span class="_2 blank"> </span><span class="ff3 fc1">Ainda com base na con\ue01fguração apresen<span class="_0 blank"></span>tada, assinale a <span class="_4 blank"> </span>opção corre-</span></div><div class="t m0 x9 h5 y64 ff3 fs3 fc1 sc0 ls1">ta.</div><div class="t m0 x9 h4 y65 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">15,4WX<span class="_0 blank"></span>GA <span class="_9 blank"> </span>L<span class="_0 blank"></span>CD <span class="_9 blank"> </span>indica <span class="_8 blank"> </span>o <span class="_9 blank"> </span>modelo <span class="_9 blank"> </span>e <span class="_9 blank"> </span>o <span class="_8 blank"> </span>tamanho <span class="_9 blank"> </span>da <span class="_9 blank"> </span>placa-mãe <span class="_9 blank"> </span>da </span></div><div class="t m0 x12 h5 y66 ff3 fs3 fc1 sc0 ls1 ws1">con\ue01fguração apresen<span class="_0 blank"></span>tada.</div><div class="t m0 x9 h4 y67 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">DVD-R<span class="_4 blank"> </span>W <span class="ff4">double layer</span> indica que o <span class="ff4 ws3">notebook</span> <span class="_4 blank"> </span>possui leitora de DVD </span></div><div class="t m0 x12 h5 y9a ff3 fs3 fc1 sc0 ls1 ws1">dupla face, mas não permite g<span class="_0 blank"></span>ravação<span class="_0 blank"></span>.</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf7" class="pf w0 h0" data-page-no="7"><div class="pc pc7 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x14 y0 w5 hb" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg7.png"><div class="c xc y2c w4 h0"><div class="t m0 x15 h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 x16 h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x17 y2c w3 h0"><div class="t m0 x18 h9 y4e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 x19 h9 y4f ff3 fs7 fc0 sc0 ls1">7</div><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x4 h4 y31 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">Com <span class="_0 blank"></span>a con\ue01fguração <span class="_0 blank"></span>de <span class="ff4 ws3">hardw<span class="_0 blank"></span>are<span class="ff3 ws1"> apr<span class="_0 blank"></span>esentada, não <span class="_0 blank"></span>seria possível <span class="_0 blank"></span>a </span></span></span></div><div class="t m0 x0 h5 y32 ff3 fs3 fc1 sc0 ls1 ws1">instalação do <span class="ff4 ws7">sof t ware</span> Linux. Par<span class="_0 blank"></span>a <span class="_4 blank"> </span>essa instalação, seria necessário </div><div class="t m0 x0 h5 y33 ff3 fs3 fc1 sc0 ls1 ws1">ampliar a capacidade de memória.</div><div class="t m0 x4 h4 y52 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">O <span class="_4 blank"> </span><span class="ff4 ws3">notebook</span> <span class="_4 blank"> </span>com a <span class="_4 blank"> </span>con\ue01fguração apresentada <span class="_4 blank"> </span>permite <span class="_4 blank"> </span>acesso a <span class="_4 blank"> </span>re-</span></div><div class="t m0 x0 h5 y53 ff3 fs3 fc1 sc0 ls1 ws1">des sem \ue01fo das tecnologias 802.11 a/b/g <span class="ff4 ws3">wireless</span> LAN.</div><div class="t m0 x5 h5 y85 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: D</div><div class="t m0 x5 h5 y9b ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h4 y9c ff3 fs3 fc1 sc0 ls3 ws1">Na opção <span class="ff2 ls1 ws6">a</span><span class="ls1"> <span class="_0 blank"></span>é a<span class="_0 blank"></span>pre<span class="_0 blank"></span>sent<span class="_0 blank"></span>ado <span class="_0 blank"></span>o m<span class="_0 blank"></span>odelo<span class="_0 blank"></span> e <span class="_0 blank"></span>tama<span class="_0 blank"></span>nho <span class="_0 blank"></span>do <span class="_0 blank"></span>moni<span class="_0 blank"></span>tor <span class="_0 blank"></span>e n<span class="_0 blank"></span>ão d<span class="_0 blank"></span>a pl<span class="_0 blank"></span>aca </span></div><div class="t m0 x6 h4 y9d ff3 fs3 fc1 sc0 ls3 ws1">mãe. <span class="_0 blank"></span>DVD-R<span class="_4 blank"> </span>W <span class="ff4">double <span class="_0 blank"></span>layer<span class="ff3"> <span class="_0 blank"></span>(opção <span class="ff2 ls1 ws6">b</span>) <span class="_0 blank"></span>grava <span class="_0 blank"></span>e lê <span class="_0 blank"></span>de <span class="_0 blank"></span>ambos os <span class="_0 blank"></span>lados do <span class="_0 blank"></span>disco. <span class="_0 blank"></span>Ao </span></span></div><div class="t m0 x6 h4 y93 ff3 fs3 fc1 sc0 ls3 ws1">contrário do <span class="_4 blank"> </span>sugerido <span class="_4 blank"> </span>na opção <span class="_4 blank"> </span><span class="ff2 ls1 ws6">c</span>, <span class="_4 blank"> </span>o Linux <span class="_4 blank"> </span>requer menos <span class="_4 blank"> </span>recursos <span class="_4 blank"> </span>que o <span class="_4 blank"> </span>siste<span class="_4 blank"> </span><span class="ls1">-</span></div><div class="t m0 x6 h4 y94 ff3 fs3 fc1 sc0 ls3 ws1">ma <span class="_0 blank"></span>Window<span class="_0 blank"></span>s. A opção <span class="ff2 ls1 ws6">d</span> é correta quando a\ue01frma o acesso a r<span class="_0 blank"></span>edes sem \ue01fo.</div><div class="t m0 x3 h4 y9e ff2 fs3 fc0 sc0 ls1 ws1">10. <span class="_0 blank"></span><span class="ff3 fc1">(Cesgranrio) Uma <span class="_4 blank"> </span>empresa <span class="_4 blank"> </span>faz <span class="_4 blank"> </span><span class="ff4">backup</span> completo <span class="_4 blank"> </span>de <span class="_4 blank"> </span>seus <span class="_4 blank"> </span>arquivos<span class="_0 blank"></span>, <span class="_4 blank"> </span>se<span class="_4 blank"> </span>-</span></div><div class="t m0 x4 h5 y95 ff3 fs3 fc1 sc0 ls1 ws1">manalmente <span class="_1 blank"> </span>aos <span class="_3 blank"> </span>domingos, <span class="_1 blank"> </span>às <span class="_1 blank"> </span>10h, <span class="_3 blank"> </span>com <span class="_1 blank"> </span>duração <span class="_1 blank"> </span>de <span class="_1 blank"> </span>1h. <span class="_3 blank"> </span>Um <span class="_1 blank"> </span><span class="ff4">backup</span> </div><div class="t m0 x4 h5 y3e ff3 fs3 fc1 sc0 ls1 ws1">incremental é <span class="_0 blank"></span>realizado diariamente<span class="_0 blank"></span>, às 22h, também com <span class="_0 blank"></span>duração de </div><div class="t m0 x4 h5 y3f ff3 fs3 fc1 sc0 ls1 ws1">1h. <span class="_8 blank"> </span>Em <span class="_8 blank"> </span>uma <span class="_8 blank"> </span>determinada <span class="_1 blank"> </span>quar<span class="_4 blank"> </span>ta-feira, <span class="_8 blank"> </span>às <span class="_8 blank"> </span>8h, <span class="_1 blank"> </span>ocorreu <span class="_8 blank"> </span>um <span class="_8 blank"> </span>problema </div><div class="t m0 x4 h5 y5c ff3 fs3 fc1 sc0 ls1 ws1">que <span class="_4 blank"> </span>ocasionou <span class="_3 blank"> </span>a <span class="_3 blank"> </span>perda <span class="_4 blank"> </span>total <span class="_3 blank"> </span>dos <span class="_3 blank"> </span>arquivos<span class="_0 blank"></span>. <span class="_3 blank"> </span>Com <span class="_4 blank"> </span>base <span class="_3 blank"> </span>nessas <span class="_3 blank"> </span>informa-</div><div class="t m0 x4 h5 y9f ff3 fs3 fc1 sc0 ls1 ws1">ções, é c<span class="_0 blank"></span>orreto a\ue01frmar que</div><div class="t m0 x4 h4 ya0 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">arquivos <span class="_0 blank"></span>gravados <span class="_0 blank"></span>às 6h de quarta-feira ser<span class="_0 blank"></span>ão recuperados a <span class="_0 blank"></span>par<span class="_4 blank"> </span>tir </span></div><div class="t m0 x0 h5 ya1 ff3 fs3 fc1 sc0 ls1 ws1">do <span class="ff4">backup</span> de terça-f<span class="_0 blank"></span>eira.</div><div class="t m0 x4 h4 ya2 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">todos os arquivos gravados na quar<span class="_4 blank"> </span>ta-feira serão perdidos<span class="_0 blank"></span>, <span class="_4 blank"> </span>exc<span class="_0 blank"></span>eto </span></div><div class="t m0 x0 h5 ya3 ff3 fs3 fc1 sc0 ls1 ws1">os maiores que 1KB<span class="_0 blank"></span>.</div><div class="t m0 x4 h4 y46 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">a <span class="_4 blank"> </span>recuperação <span class="_4 blank"> </span>poderá <span class="_4 blank"> </span>ser <span class="_3 blank"> </span>feita <span class="_4 blank"> </span>a <span class="_4 blank"> </span>par<span class="_4 blank"> </span>tir <span class="_4 blank"> </span>dos <span class="_3 blank"> </span><span class="ff4">backups</span> <span class="_4 blank"> </span>de <span class="_3 blank"> </span>segunda <span class="_4 blank"> </span>e </span></div><div class="t m0 x0 h5 ya4 ff3 fs3 fc1 sc0 ls1 ws1">terça-f<span class="_0 blank"></span>eira, sem a necessidade dos <span class="ff4">backups</span> de domingo<span class="_0 blank"></span>.</div><div class="t m0 x4 h4 y99 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">para r<span class="_0 blank"></span>ecuperação dos <span class="_0 blank"></span>arquivos <span class="_0 blank"></span>até a <span class="_0 blank"></span>última posição <span class="_0 blank"></span>possível, <span class="_0 blank"></span>serão </span></div><div class="t m0 x0 h5 ya5 ff3 fs3 fc1 sc0 ls1 ws1">necessários somente <span class="_0 blank"></span>os <span class="ff4">backups</span> completos <span class="_0 blank"></span>de domingo e o incr<span class="_0 blank"></span>e<span class="_4 blank"> </span>-</div><div class="t m0 x0 h5 ya6 ff3 fs3 fc1 sc0 ls1 ws1">mental de terça-f<span class="_0 blank"></span>eira.</div><div class="t m0 x4 h4 ya7 ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">para <span class="_0 blank"></span>recuperação dos <span class="_0 blank"></span>arquivos <span class="_0 blank"></span>até a <span class="_0 blank"></span>última posição <span class="_0 blank"></span>possível, <span class="_0 blank"></span>serão </span></div><div class="t m0 x0 h5 ya8 ff3 fs3 fc1 sc0 ls1 ws1">necessários <span class="_4 blank"> </span>os <span class="_3 blank"> </span><span class="ff4">backups</span> <span class="_3 blank"> </span>completo <span class="_4 blank"> </span>e <span class="_3 blank"> </span>incremental <span class="_3 blank"> </span>de <span class="_3 blank"> </span>domingo <span class="_4 blank"> </span>e <span class="_3 blank"> </span>os </div><div class="t m0 x0 h5 ya9 ff4 fs3 fc1 sc0 ls1">backups<span class="ff3 ws1"> incrementais de segunda e ter<span class="_0 blank"></span>ça-feira.</span></div><div class="t m0 x5 h5 yaa ff3 fs3 fc1 sc0 ls1 ws1">Resposta: E</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf8" class="pf w0 h0" data-page-no="8"><div class="pc pc8 w0 h0"><img fetchpriority="low" loading="lazy" class="bi xb y0 w6 hc" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg8.png"><div class="c xc y2c w3 h0"><div class="t m0 xd h9 yab ff3 fs7 fc0 sc0 ls1">8</div><div class="t m0 xb h9 yac ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 xe h9 yad ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xf h9 yae ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x10 y2c w4 h0"><div class="t m0 x9 h9 yaf ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 yb0 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x11 h5 yb1 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h5 yb2 ff3 fs3 fc1 sc0 ls1 ws1">Nessa questão <span class="_0 blank"></span>basta saber <span class="_0 blank"></span>que <span class="_0 blank"></span>o <span class="ff4">backup</span> <span class="_0 blank"></span>incremental faz <span class="_0 blank"></span>cópia <span class="_0 blank"></span>apenas do </div><div class="t m0 x4 h4 yb3 ff3 fs3 fc1 sc0 ls1 ws1">conteúdo <span class="_4 blank"> </span>desde <span class="_3 blank"> </span>o <span class="_3 blank"> </span>último <span class="_3 blank"> </span>incremental, <span class="_4 blank"> </span>assim <span class="_3 blank"> </span>apenas <span class="_3 blank"> </span>a <span class="_1 blank"> </span>opção <span class="_4 blank"> </span><span class="ff2">e</span> <span class="_3 blank"> </span>faz <span class="_3 blank"> </span>sentido, </div><div class="t m0 x4 h5 yb4 ff3 fs3 fc1 sc0 ls1 ws1">pois <span class="_4 blank"> </span>junta <span class="_4 blank"> </span>o <span class="_3 blank"> </span>último <span class="_3 blank"> </span>completo <span class="_4 blank"> </span>mais <span class="_4 blank"> </span>os <span class="_3 blank"> </span>incrementais <span class="_4 blank"> </span>de <span class="_4 blank"> </span>cada <span class="_3 blank"> </span>dia <span class="_4 blank"> </span>que <span class="_3 blank"> </span>passou </div><div class="t m0 x4 h5 yb5 ff3 fs3 fc1 sc0 ls1 ws1">no período.</div><div class="t m0 x1a hd yb6 ff2 fs0 fc0 sc0 ls1 ws1">Questões extras </div><div class="t m0 x13 h4 yb7 ff2 fs3 fc0 sc0 ls1 ws1">11. <span class="_0 blank"></span><span class="ff3 fc1 ws0">(Cesgranrio)<span class="ff2 ls2 ws1"> </span><span class="ws1">A \ue01fgura mostra o W<span class="_0 blank"></span>indows Explorer sendo executado no </span></span></div><div class="t m0 x9 h5 yb8 ff3 fs3 fc1 sc0 ls1 ws1">Windo<span class="_0 blank"></span>ws XP<span class="_a blank"></span>, em por<span class="_4 blank"> </span>tuguês e com sua con\ue01fguração padrão<span class="_0 blank"></span>. </div><div class="t m1 x1b h6 yb9 ff3 fs4 fc1 sc0 ls1 ws1">Ítalo Demarchi.</div><div class="t m0 x11 h5 yba ff3 fs3 fc1 sc0 ls1 ws1">O <span class="_10 blank"> </span>diret<span class="_0 blank"></span>ório \u201cDocumentos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> <span class="_d blank"> </span>está <span class="_10 blank"> </span>selecionado. <span class="_d blank"> </span>O <span class="_10 blank"> </span>que <span class="_10 blank"> </span>o <span class="_d blank"> </span>usuário <span class="_10 blank"> </span>deverá </div><div class="t m0 x4 h5 ybb ff3 fs3 fc1 sc0 ls1 ws1">fazer <span class="_4 blank"> </span>se <span class="_1 blank"> </span>quiser <span class="_4 blank"> </span>mover <span class="_4 blank"> </span>o <span class="_3 blank"> </span>diretório \u201cDocumentos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> <span class="_4 blank"> </span>para <span class="_3 blank"> </span>baixo <span class="_3 blank"> </span>do <span class="_3 blank"> </span>diretório <span class="_0 blank"></span>\u201cC:\</div><div class="t m0 x4 h5 ybc ff3 fs3 fc1 sc0 ls1 ws0">NovosP<span class="_0 blank"></span>rojetos<span class="_0 blank"></span>\u201d?</div><div class="t m0 x9 h4 ybd ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">Pr<span class="_0 blank"></span>essionar <span class="_1 blank"> </span>as <span class="_1 blank"> </span>teclas <span class="_3 blank"> </span>Ctrl+X, <span class="_1 blank"> </span>selecionar <span class="_1 blank"> </span>o <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório \u201cC:\NovosP<span class="_0 blank"></span>roje<span class="_4 blank"> </span>-</span></div><div class="t m0 x12 h5 ybe ff3 fs3 fc1 sc0 ls1 ws1">tos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> e, a seguir<span class="_c blank"></span>, pressionar as teclas Ctrl+M.</div><div class="t m0 x9 h4 ybf ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">Pr<span class="_0 blank"></span>essionar <span class="_1 blank"> </span>as <span class="_1 blank"> </span>teclas <span class="_3 blank"> </span>Ctrl+X, <span class="_1 blank"> </span>selecionar <span class="_1 blank"> </span>o <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório \u201cC:\NovosP<span class="_0 blank"></span>roje<span class="_4 blank"> </span>-</span></div><div class="t m0 x12 h5 yc0 ff3 fs3 fc1 sc0 ls1 ws1">tos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> e, a seguir<span class="_c blank"></span>, pressionar as teclas Ctrl+V<span class="_c blank"></span>.</div><div class="t m0 x9 h4 yc1 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">Pr<span class="_0 blank"></span>essionar <span class="_1 blank"> </span>as <span class="_3 blank"> </span>teclas <span class="_1 blank"> </span>Ctrl+D<span class="_0 blank"></span>, <span class="_1 blank"> </span>selecionar <span class="_3 blank"> </span>o <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório \u201cC:\Nov<span class="_0 blank"></span>osProje-</span></div><div class="t m0 x12 h5 yc2 ff3 fs3 fc1 sc0 ls1 ws1">tos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> e, a seguir<span class="_c blank"></span>, pressionar as teclas Ctrl+M.</div><div class="t m0 x9 h4 yc3 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">Pr<span class="_0 blank"></span>essionar <span class="_1 blank"> </span>as <span class="_3 blank"> </span>teclas <span class="_1 blank"> </span>Ctrl+D<span class="_0 blank"></span>, <span class="_1 blank"> </span>selecionar <span class="_3 blank"> </span>o <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório \u201cC:\Nov<span class="_0 blank"></span>osProje-</span></div><div class="t m0 x12 h5 yc4 ff3 fs3 fc1 sc0 ls1 ws1">tos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> e, a seguir<span class="_c blank"></span>, pressionar as teclas Ctrl+V<span class="_c blank"></span>.</div><div class="t m0 x9 h4 yc5 ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">Pr<span class="_0 blank"></span>essionar <span class="_1 blank"> </span>as <span class="_3 blank"> </span>teclas <span class="_1 blank"> </span>Ctrl+D<span class="_0 blank"></span>, <span class="_1 blank"> </span>selecionar <span class="_3 blank"> </span>o <span class="_1 blank"> </span>dir<span class="_0 blank"></span>etório \u201cC:\Nov<span class="_0 blank"></span>osProje-</span></div><div class="t m0 x12 h5 yc6 ff3 fs3 fc1 sc0 ls1 ws1">tos<span class="_0 blank"></span>\u201d<span class="_c blank"></span> e, a seguir<span class="_c blank"></span>, pressionar as teclas Ctrl+X.</div><div class="t m0 x11 h5 yc7 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: B</div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf9" class="pf w0 h0" data-page-no="9"><div class="pc pc9 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x14 y0 w5 hb" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bg9.png"><div class="c xc y2c w4 h0"><div class="t m0 x15 h9 yad ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 x16 h9 yae ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x17 y2c w3 h0"><div class="t m0 x18 h9 yc8 ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 x19 h9 yc9 ff3 fs7 fc0 sc0 ls1">9</div><div class="t m0 x9 h9 yaf ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 yb0 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x5 h5 yb1 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h5 yb2 ff3 fs3 fc1 sc0 ls1 ws1">Nessa <span class="_3 blank"> </span>questão <span class="_1 blank"> </span>trata-se <span class="_3 blank"> </span>de <span class="_3 blank"> </span>recor<span class="_4 blank"> </span>tar <span class="_3 blank"> </span>e <span class="_1 blank"> </span>colar<span class="_c blank"></span>, <span class="_3 blank"> </span>assim, <span class="_1 blank"> </span>o <span class="_3 blank"> </span>primeiro <span class="_1 blank"> </span>passo <span class="_3 blank"> </span>é <span class="_1 blank"> </span>r<span class="_0 blank"></span>e<span class="_4 blank"> </span>-</div><div class="t m0 x6 h4 yb3 ff3 fs3 fc1 sc0 ls1 ws1">cortar<span class="_0 blank"></span>, <span class="_4 blank"> </span>eliminando as <span class="_4 blank"> </span>opções <span class="ff2">c</span>, <span class="_4 blank"> </span><span class="ff2">d</span><span class="ls8"> e </span><span class="ff2">e</span>; na <span class="_4 blank"> </span>opção <span class="ff2">a</span> <span class="_4 blank"> </span>é <span class="_4 blank"> </span>citado Ctrl+M <span class="_4 blank"> </span>para <span class="_4 blank"> </span>colar<span class="_c blank"></span>, </div><div class="t m0 x6 h4 yb4 ff3 fs3 fc1 sc0 ls1 ws1">quando o correto é a opção <span class="ff2">b</span> que utiliza o Ctrl+V<span class="_c blank"></span>.</div><div class="t m0 x3 h4 yca ff2 fs3 fc0 sc0 ls1 ws1">12. <span class="_0 blank"></span><span class="ff3 fc1">(Cesgranrio) Paulo <span class="_4 blank"> </span>está <span class="_4 blank"> </span>utilizando <span class="_4 blank"> </span>um <span class="_4 blank"> </span>microcomputador com <span class="_4 blank"> </span>a <span class="_4 blank"> </span>con\ue01f-</span></div><div class="t m0 x4 h5 ycb ff3 fs3 fc1 sc0 ls1 ws1">guração a seguir:</div><div class="t m0 x5 h5 ycc ff3 fs3 fc1 sc0 ls1 ws1">Intel Core Duo \u2013 1,73GHz</div><div class="t m0 x5 h5 ycd ff3 fs3 fc1 sc0 ls1 ws1">80GB HD</div><div class="t m0 x5 h5 yce ff3 fs3 fc1 sc0 ls1 ws1">1GB DDR2</div><div class="t m0 x5 h5 ycf ff3 fs3 fc1 sc0 ls1 ws1">Com base na con\ue01fguração apr<span class="_0 blank"></span>esentada, é correto a\ue01frmar que</div><div class="t m0 x4 h4 yd0 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">a memória ROM é do tipo HD<span class="_0 blank"></span>.</span></div><div class="t m0 x4 h4 yd1 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">a capacidade da memória RAM é de 1,73GHz.</span></div><div class="t m0 x4 h4 yd2 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">o disco rígido é de 80GB.</span></div><div class="t m0 x4 h4 yd3 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">o monitor de vídeo é de 1GB.</span></div><div class="t m0 x4 h4 yd4 ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">Intel Core Duo indica que exist<span class="_0 blank"></span>em dois pentes de memória RAM.</span></div><div class="t m0 x5 h5 yd5 ff3 fs3 fc1 sc0 ls1 ws1">Resposta: C</div><div class="t m0 x5 h5 yd6 ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x5 h4 yd7 ff3 fs3 fc1 sc0 ls1 ws1">A <span class="_1 blank"> </span>alternativa <span class="_3 blank"> </span>correta <span class="_1 blank"> </span>é <span class="_3 blank"> </span>a <span class="_1 blank"> </span>opção <span class="_1 blank"> </span><span class="ff2">c</span>, <span class="_1 blank"> </span>disco <span class="_3 blank"> </span>rígido <span class="_1 blank"> </span>de <span class="_1 blank"> </span>80GB. <span class="_3 blank"> </span>Na <span class="_1 blank"> </span>opção <span class="_1 blank"> </span><span class="ff2">a</span> <span class="_3 blank"> </span>é <span class="_1 blank"> </span>o </div><div class="t m0 x6 h5 yd8 ff3 fs3 fc1 sc0 ls1 ws1">disco <span class="_4 blank"> </span>rígido <span class="_4 blank"> </span>que <span class="_4 blank"> </span>é <span class="_4 blank"> </span>chamado <span class="_4 blank"> </span>de <span class="_4 blank"> </span>HD <span class="_4 blank"> </span>e <span class="_4 blank"> </span>não <span class="_4 blank"> </span>a <span class="_4 blank"> </span>memória <span class="_4 blank"> </span>ROM. <span class="_3 blank"> </span>Na <span class="_4 blank"> </span>con\ue01fguração </div><div class="t m0 x6 h5 yd9 ff3 fs3 fc1 sc0 ls1 ws1">1,73GHz está <span class="_0 blank"></span>ao <span class="_0 blank"></span>lado do <span class="_0 blank"></span>processador<span class="_c blank"></span>, en<span class="_0 blank"></span>tão é <span class="_0 blank"></span>capacidade de <span class="_c blank"></span>processamento </div><div class="t m0 x6 h4 yda ff3 fs3 fc1 sc0 ls1 ws1">e não armazenamento (opção <span class="ff2">b</span>). <span class="_4 blank"> </span>O monitor (opção <span class="ff2">d</span>) não <span class="_4 blank"> </span>possui capacida-</div><div class="t m0 x6 h4 ydb ff3 fs3 fc1 sc0 ls1 ws1">de <span class="_4 blank"> </span>de <span class="_4 blank"> </span>armazenamento<span class="_0 blank"></span>, <span class="_4 blank"> </span>o 1GB <span class="_4 blank"> </span>é <span class="_4 blank"> </span>memória <span class="_4 blank"> </span>RAM. <span class="_4 blank"> </span>Na <span class="_4 blank"> </span>opção <span class="_4 blank"> </span><span class="ff2">e</span> <span class="_4 blank"> </span>Cor<span class="_0 blank"></span>e <span class="_4 blank"> </span>Duo <span class="_4 blank"> </span>indica </div><div class="t m0 x6 h5 ydc ff3 fs3 fc1 sc0 ls1 ws1">que há dois processador<span class="_0 blank"></span>es no mesmo <span class="ff4">chip</span>.</div><div class="t m0 x3 h4 ydd ff2 fs3 fc0 sc0 ls1 ws1">13. <span class="_0 blank"></span><span class="ff3 fc1">(Cesgranrio) <span class="_0 blank"></span>Durante <span class="_0 blank"></span>um pr<span class="_0 blank"></span>ocesso de <span class="_0 blank"></span>busca no <span class="_0 blank"></span>seu <span class="_0 blank"></span>microcomputador<span class="_c blank"></span>, </span></div><div class="t m0 x4 h5 yde ff3 fs3 fc1 sc0 ls1 ws1">com <span class="_0 blank"></span>Windo<span class="_0 blank"></span>ws XP em sua con\ue01fguração padrão<span class="_0 blank"></span>, um usuár<span class="_4 blank"> </span>io encontr<span class="_0 blank"></span>ou </div><div class="t m0 x4 h4 ydf ff3 fs3 fc1 sc0 ls1 ws1">alguns arquivos c<span class="_0 blank"></span>om a ex<span class="_4 blank"> </span>tensão <span class="ff2 ws6">cab</span>. A extensão <span class="ff2 ws6">cab</span> é um formato</div><div class="t m0 x4 h4 ye0 ff2 fs3 fc0 sc0 ls1 ws1">a) <span class="_5 blank"> </span><span class="ff3 fc1">de compactação de arquivos para distribuição de <span class="ff4 ws7">softwares</span>.</span></div><div class="t m0 x4 h4 ye1 ff2 fs3 fc0 sc0 ls1 ws1">b) <span class="_6 blank"> </span><span class="ff3 fc1">padrão para armazenament<span class="_0 blank"></span>o de imagens vetorizadas.</span></div><div class="t m0 x4 h4 ye2 ff2 fs3 fc0 sc0 ls1 ws1">c) <span class="_7 blank"> </span><span class="ff3 fc1">criptografado de vírus que inf<span class="_0 blank"></span>ec<span class="_4 blank"> </span>ta macros do <span class="_c blank"></span>Wor<span class="_0 blank"></span>d.</span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pfa" class="pf w0 h0" data-page-no="a"><div class="pc pca w0 h0"><img fetchpriority="low" loading="lazy" class="bi xb y0 w7 he" alt="" src="https://files.passeidireto.com/e699e83d-17ed-4161-a514-7a8516ea464f/bga.png"><div class="c xc y2c w3 h0"><div class="t m0 xd h9 y2d ff3 fs7 fc0 sc0 ls1">10</div><div class="t m0 xb h9 y2e ff3 fs7 fc0 sc0 ls1 ws1">Resolução de questões \u2013 Noções de informática</div><div class="t m0 xe h9 y2a ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xf h9 y2b ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="c x10 y2c w4 h0"><div class="t m0 x9 h9 y2f ff3 fs7 fc1 sc0 ls1 ws1">Este material é parte integrante do <span class="_0 blank"></span>Videoaulas <span class="ff4">online </span>do IESDE BRASIL S.A.,</div><div class="t m0 xa h9 y30 ff3 fs7 fc1 sc0 ls1 ws1">mais informações www.videoaulasonline<span class="_0 blank"></span>.com.br</div></div><div class="t m0 x9 h4 y31 ff2 fs3 fc0 sc0 ls1 ws1">d) <span class="_6 blank"> </span><span class="ff3 fc1">utilizado pelo sistema operacional para armazenar <span class="ff4 ws3">logs</span> de erro<span class="_0 blank"></span>.</span></div><div class="t m0 x9 h4 y50 ff2 fs3 fc0 sc0 ls1 ws1">e) <span class="_5 blank"> </span><span class="ff3 fc1">utilizado pelo Excel par<span class="_0 blank"></span>a armazenar as suas planilhas.</span></div><div class="t m0 x11 h5 y6a ff3 fs3 fc1 sc0 ls1 ws1">Resposta: A</div><div class="t m0 x11 h5 y6b ff3 fs3 fc1 sc0 ls1 ws0">Comentário:</div><div class="t m0 x11 h4 y6c ff3 fs3 fc1 sc0 ls1 ws1">O <span class="_3 blank"> </span>tipo <span class="_3 blank"> </span>de <span class="_3 blank"> </span>arquivo <span class="_4 blank"> </span><span class="ff2 ws6">cab</span> <span class="_3 blank"> </span>são <span class="_1 blank"> </span>ar<span class="_0 blank"></span>quivos <span class="_3 blank"> </span>compactados <span class="_3 blank"> </span>para <span class="_3 blank"> </span>melhor <span class="_3 blank"> </span>distr<span class="_4 blank"> </span>ibui-</div><div class="t m0 x4 h4 ye3 ff3 fs3 fc1 sc0 ls1 ws1">ção de <span class="ff4 ws7">softwares</span> (opção <span class="ff2">a</span>). <span class="_0 blank"></span>I<span class="_4 blank"> </span>magens vet<span class="_0 blank"></span>orizadas (opção <span class="ff2">b</span>) são armazenadas </div><div class="t m0 x4 h5 ye4 ff3 fs3 fc1 sc0 ls1 ws1">sob <span class="_1 blank"> </span>padr<span class="_0 blank"></span>ões <span class="_1 blank"> </span>especí\ue01fcos <span class="_3 blank"> </span>das <span class="_1 blank"> </span>ferramentas <span class="_3 blank"> </span>de <span class="_1 blank"> </span>desenvolvimen<span class="_0 blank"></span>to <span class="_1 blank"> </span>das <span class="_3 blank"> </span>mesmas </div><div class="t m0 x4 h4 y9c ff3 fs3 fc1 sc0 ls1 ws1">(ex.: <span class="_3 blank"> </span>CorelDraw<span class="_0 blank"></span>-<span class="_4 blank"> </span>CDR). <span class="_3 blank"> </span>Os <span class="_1 blank"> </span>vírus <span class="_3 blank"> </span>(opção <span class="_3 blank"> </span><span class="ff2">c</span>) <span class="_1 blank"> </span>não <span class="_3 blank"> </span>possuem <span class="_1 blank"> </span>estrutura <span class="_4 blank"> </span>própria <span class="_1 blank"> </span>de </div><div class="t m0 x4 h5 y9d ff3 fs3 fc1 sc0 ls1 ws1">arquivo<span class="_0 blank"></span>, e sim <span class="_4 blank"> </span>estão embutidos <span class="_4 blank"> </span>em arquivos diversos<span class="_0 blank"></span>. <span class="_4 blank"> </span>Os <span class="ff4 ws3">logs</span> de <span class="_4 blank"> </span>erro de sis-</div><div class="t m0 x4 h4 y93 ff3 fs3 fc1 sc0 ls1 ws1">temas <span class="_4 blank"> </span>são <span class="_4 blank"> </span>geralmente <span class="_4 blank"> </span>armazenados <span class="_4 blank"> </span>em <span class="_4 blank"> </span>ex<span class="_4 blank"> </span>tensões <span class="_4 blank"> </span><span class="ff2 ws6">log</span> <span class="_4 blank"> </span>ou <span class="_4 blank"> </span><span class="ff2">err</span>. <span class="_3 blank"> </span>O <span class="_4 blank"> </span>padrão <span class="_4 blank"> </span>de </div><div class="t m0 x4 h4 y94 ff3 fs3 fc1 sc0 ls1 ws1">extensão do excel é <span class="ff2">xls</span>/<span class="ff2">xlsx</span>.</div><div class="t m0 x13 h4 y9e ff2 fs3 fc0 sc0 ls1 ws1">14. <span class="_0 blank"></span><span class="ff3 fc1">(Cesgranrio) A \ue01fgura abaix<span class="_0 blank"></span>o apresenta uma janela do W<span class="_0 blank"></span>indows Explo-</span></div><div class="t m0 x9 h5 y95 ff3 fs3 fc1 sc0 ls1 ws1">rer aber<span class="_4 blank"> </span>ta no Windo<span class="_0 blank"></span>ws Vista em sua <span class="_4 blank"> </span>con\ue01fguração padrão. Nota-se, na </div><div class="t m0 x9 h5 y3e ff3 fs3 fc1 sc0 ls1 ws1">\ue01fgura, que algumas pastas estão selecionadas.</div><div class="t m1 x7 h6 ye5 ff3 fs4 fc1 sc0 ls1 ws1">Ítalo Demarchi.</div><div class="t m0 x11 h5 ye6 ff3 fs3 fc1 sc0 ls3 ws1">P<span class="_0 blank"></span>ara <span class="_d blank"> </span>selecionar as <span class="_d blank"> </span>pastas <span class="_d blank"> </span>acima, par<span class="_4 blank"> </span>tindo<span class="_4 blank"> </span>-se de <span class="_d blank"> </span>uma <span class="_d blank"> </span>situação em <span class="_d blank"> </span>que </div><div class="t m0 x4 h5 ye7 ff3 fs3 fc1 sc0 ls3 ws1">apenas a pasta <span class="_4 blank"> </span>Documentos estava selecionada, uma <span class="_4 blank"> </span>sequência de passos <span class="_4 blank"> </span>foi </div><div class="t m0 x4 h5 ye8 ff3 fs3 fc1 sc0 ls3 ws1">executada: primeiro<span class="_0 blank"></span>, <span class="_4 blank"> </span>o cursor <span class="_4 blank"> </span>foi posicionado <span class="_4 blank"> </span>na pasta <span class="_4 blank"> </span>Cartões; <span class="_4 blank"> </span>a seguir<span class="_0 blank"></span>, <span class="_4 blank"> </span>man<span class="ls1">-</span></div><div class="t m0 x4 h4 ye9 ff3 fs3 fc1 sc0 ls3 ws1">tendo-se a <span class="ff2">tecla 1</span> pressionada, clicou-se na pasta <span class="ff2 ws8">Requisiç<span class="_0 blank"></span>ões<span class="ff3 ls1 ws1">; em<span class="_0 blank"></span> seg<span class="_0 blank"></span>uida<span class="_0 blank"></span>, a </span></span></div><div class="t m0 x4 h4 yea ff2 fs3 fc1 sc0 ls3 ws1">tecla 1<span class="ff3"> foi liberada; a seguir<span class="_c blank"></span>, mantendo-se a <span class="ff2">tecla 2</span> pressionada, clicou-se nas </span></div><div class="t m0 x4 h4 yeb ff3 fs3 fc1 sc0 ls3 ws1">pastas <span class="ff2 ws8">Diversos</span><span class="ls9"> e </span><span class="ff2 ws8">Relat<span class="_0 blank"></span>órios<span class="ff3 ls1 ws1">. C<span class="_0 blank"></span>omo <span class="_0 blank"></span>res<span class="_0 blank"></span>ulta<span class="_0 blank"></span>do<span class="_0 blank"></span>, t<span class="_0 blank"></span>oda<span class="_0 blank"></span>s as<span class="_0 blank"></span> pas<span class="_0 blank"></span>tas <span class="_0 blank"></span>ent<span class="_0 blank"></span>re <span class="_0 blank"></span>as <span class="_0 blank"></span>past<span class="_0 blank"></span>as </span></span></div><div class="t m0 x4 h4 yec ff2 fs3 fc1 sc0 ls3 ws7">Cartões<span class="ff3 lsa ws1"> e<span class="_4 blank"> </span> </span><span class="ws8">Requisições<span class="ff3 ws1">, <span class="_0 blank"></span>com ex<span class="_0 blank"></span>ceção das <span class="_0 blank"></span>pastas <span class="ff2 ws8">Diversos</span><span class="lsa"> e </span><span class="ff2 ws8">Relatórios</span>, <span class="_0 blank"></span>foram </span></span></div><div class="t m0 x4 h4 yed ff3 fs3 fc1 sc0 ls3 ws1">selecionadas. As <span class="ff2">teclas 1</span> e <span class="ff2 ls1 ws6">2<span class="_0 blank"></span><span class="ff3 ls3 ws1"> utilizadas foram, respectivamente:</span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div>
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