Usando o contexto: 2q3=cv (T3−T2)=1800 kJ /kg T3=T 2 + 2q3 /Cv    P o rtanto : T 3 = 3234K    ...

Usando o contexto: 2q3=cv (T3−T2)=1800 kJ /kg T3=T 2 + 2q3 /Cv    P o rtanto : T 3 = 3234K    k-1 = 10 0, 4 = 2 ,51  T4 = 1 2 8 7 ,5K k = 1 0 1, 4 = 25 ,12  P4 = 0 ,44 6 7 MP a                   Verific a ndo o valo r: 4q1=cv (T1−T4 ) = 0,717 (288,2−1287, 5 ) = −716,5kJ /kg              Responda: