What is the synchronous speed of a 6-pole, 50 Hz motor? The synchronous speed of a motor is defined by the rotation speed of the rotating field, w...
What is the synchronous speed of a 6-pole, 50 Hz motor?
The synchronous speed of a motor is defined by the rotation speed of the rotating field, which depends on the number of poles (p) of the motor and the frequency (f) of the network, in Hertz.
The motor speed is directly proportional to the frequency.
The rotating field travels a pair of poles (p) each cycle. Thus, as the winding has poles or 'p' pairs of poles, the speed of the field is given by the expression: NS = 120 x F / P.
500 rpm
1000 rpm
6000 rpm
The synchronous speed of a motor is defined by the rotation speed of the rotating field, which depends on the number of poles (p) of the motor and the frequency (f) of the network, in Hertz.
The motor speed is directly proportional to the frequency.
The rotating field travels a pair of poles (p) each cycle. Thus, as the winding has poles or 'p' pairs of poles, the speed of the field is given by the expression: NS = 120 x F / P.
500 rpm
1000 rpm
6000 rpm
💡 1 Resposta
Ed 
The synchronous speed of a 6-pole, 50 Hz motor is given by the expression: NS = 120 x F / P, where F is the frequency of the network in Hertz and P is the number of poles of the motor. Therefore, the synchronous speed of a 6-pole, 50 Hz motor is NS = 120 x 50 / 6 = 1000 rpm. Therefore, the correct answer is B) 1000 rpm.
Faça como milhares de estudantes: teste grátis o Passei Direto
Esse e outros conteúdos desbloqueados
16 milhões de materiais de várias disciplinas
Impressão de materiais
Agora você pode testar o
Passei Direto grátis
✏️ Responder
Para escrever sua resposta aqui, entre ou crie uma conta
Outros materiais
Perguntas relacionadas
Materiais relacionados
13 pág.
184 pág.
2 pág.
6 pág.
Compartilhar