Cinética

Question

Partindo da expressão genérica da velocidade para a reação : aA + bB

⟷

cC + dD

V = -(1/a).(

Δ

[A]/

Δ t

) = -(1/b).(

Δ

[B]/

Δ t

) = (1/c).(

Δ

[C]/

Δ t

)= (1/d).(

Δ

[D]/

Δ t

)

A expressão da velocidade da reação : NH4 + NO2

⟷

N2 + 2 H2O ficará:

A

V = -(1/2).(&Delta;&Delta;[NH4]/&Delta;t&Delta;t) = -(1/2).(&Delta;&Delta;[NO2]/&Delta;t&Delta;t) = (1/2).(&Delta;&Delta;[N2]/&Delta;t&Delta;t)= (1/2).(&Delta;&Delta;[H2O]/&Delta;t&Delta;t) &Delta;t&Delta;t

B

V = (1/2).(&Delta;&Delta;[NH4]/&Delta;t&Delta;t) = (1/2).(&Delta;&Delta;[NO2]/&Delta;t&Delta;t) = -(1/2).(&Delta;&Delta;[N2]/&Delta;t&Delta;t)= -(1/2).(&Delta;&Delta;[H2O]/&Delta;t&Delta;t)

C

V = -(1).(&Delta;&Delta;[NH4]/&Delta;t&Delta;t) = -(1).(&Delta;&Delta;[NO2]/&Delta;t&Delta;t) = (1).(&Delta;&Delta;[N2]/&Delta;t&Delta;t)= (1/2).(&Delta;&Delta;[H2O]/&Delta;t&Delta;t)

D

V = (1).(&Delta;&Delta;[NH4]/&Delta;t&Delta;t) = (1).(&Delta;&Delta;[NO2]/&Delta;t&Delta;t) = -(1).(&Delta;&Delta;[N2]/&Delta;t&Delta;t)= -(1/2).(&Delta;&Delta;[H2O]/&Delta;t&Delta;t)

Rock 's · Answer

c)  V = -(1).(&Delta;[NH4]/&Delta;t) = -(1).(&Delta;[NO2]/&Delta;t) = (1).(&Delta;[N2]/&Delta;t)= (1/2).(&Delta;[H2O]/&Delta;t)

Anônimo · Answer

vlw irmão, obrigado!

RD Resoluções · Answer

Temos:

$\[\begin{align}
  & V~=~-\left( 1/a \right).\left( \Delta \left[ A \right]/\Delta t \right)\text{ } \ 
 & =~-\left( 1/b \right).\left( \Delta \left[ B \right]/\Delta t \right)\text{ } \ 
 & =~\left( 1/c \right).\left( \Delta \left[ C \right]/\Delta t \right) \ 
 & =~\left( 1/d \right).\left( \Delta \left[ D \right]/\Delta t \right)\text{ } \ 
 & \text{Equacionando:} \ 
 & V~=~-\left( 1 \right).(\frac{\Delta \Delta [N{{H}_{4}}]}{\Delta t\Delta t})\text{ } \ 
 & ~=-\left( 1 \right).(\frac{\Delta \Delta [N{{O}_{2}}]}{\Delta t\Delta t})\text{ } \ 
 & =~\left( 1 \right).(\frac{\Delta \Delta [{{N}_{2}}]}{\Delta t\Delta t}) \ 
 & \text{Portanto:} \ 
 & =~\left( 1/2 \right).(\frac{\Delta \Delta [{{H}_{2}}O]}{\Delta t\Delta t}) \ 
 &  \ 
\end{align}\]
$

A	V = -(1/2).( $Δ$ [NH4]/ $Δ t$ ) = -(1/2).( $Δ$ [NO2]/ $Δ t$ ) = (1/2).( $Δ$ [N2]/ $Δ t$ )= (1/2).( $Δ$ [H2O]/ $Δ t$ ) $Δ t$
	B	V = (1/2).( $Δ$ [NH4]/ $Δ t$ ) = (1/2).( $Δ$ [NO2]/ $Δ t$ ) = -(1/2).( $Δ$ [N2]/ $Δ t$ )= -(1/2).( $Δ$ [H2O]/ $Δ t$ )
	C	V = -(1).( $Δ$ [NH4]/ $Δ t$ ) = -(1).( $Δ$ [NO2]/ $Δ t$ ) = (1).( $Δ$ [N2]/ $Δ t$ )= (1/2).( $Δ$ [H2O]/ $Δ t$ )
	D	V = (1).( $Δ$ [NH4]/ $Δ t$ ) = (1).( $Δ$ [NO2]/ $Δ t$ ) = -(1).( $Δ$ [N2]/ $Δ t$ )= -(1/2).( $Δ$ [H2O]/ $Δ t$ )

Cinética

Química

UNINTER

💡 3 Respostas

✏️ Responder

Outros materiais

Outros materiais