Resolva as Equações irracionais a seguir: 3√x = 12 √3x - 2 = 53√2x = 6

\[\eqalign{&3\sqrt{x}= 12 \\& \sqrt{x} = \dfrac{12}{3} \\& \sqrt{x} = 4 \\& (\sqrt{x})^2=4^2 \\& x^{\dfrac{1}{2} \cdot 2} = 16 \\& x = 16}\]

\[\eqalign{&\sqrt{3x} - 2 = 5 \\& \sqrt{3x}-2+2=5+2 \\& \sqrt{3x}=7 \\& (\sqrt{3x})^2=7^2 \\& (3x)^{\dfrac{1}{2} \cdot 2}=49 \\& 3x = 49 \\& \dfrac{3x}{3}=\dfrac{49}{3} \\& x =\dfrac{49}{3}}\]

\[\eqalign{&3\sqrt{2x} = 6 \\& \dfrac{3\sqrt{2x}}{3} = \dfrac{6}{3} \\& \sqrt{2x} = 2 \\& (\sqrt{2x})^2 = 2^2 \\& (2x)^{\dfrac{1}{2}\cdot 2} = 4 \\& 2x = 4 \\& \dfrac{2x}{2}=\dfrac{4}{2} \\& x = 2}\]