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Problem 10.5 Prove the property of root-raised cosine pulse shape p(t) given by Eq. (10.32), using the following steps: (a) If is the Fourier transform representation of p(t), what is the Fourier transform representation of p(t-lT)? )( fR (b) What is the Fourier transform of ? What spectral shape does it have? ∫∞ ∞− −−= dtlTtptpq )()()( ττ (c) What q(τ)? What is q(kT)? Use these results to show that Eq. (10.32) holds. Solution (a) From the time-shifting property of Fourier transforms (see Section 2.2 ), we have that [ ] ( )flTjfRlTtp π2exp)()( −=−F (b) From the convolution property of Fourier transforms (See Section 2.2) we have that [ ] [ ] [ ] ( )flTjfR lTtptp qfQ π τ 2exp)( )()( )()( 2 −= −= = FF F (c) Since R(f) is the root-raised cosine spectrum, R2(f) is the raised cosine spectrum and so q(τ) corresponds to a raised cosine pulse. In particular, using the time-shifting property of inverse Fourier transforms )()( lTmq −= ττ where m(τ) is the raised cosine pulse shape. Using the properties of the raised cosine pulse shape (see Section 6.4) ( ) ( ) 1 0 ( ) q kT m kT lT k l k l k lδ = − =⎧= ⎨ ≠⎩ = − and Eq. (10.32) holds. Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.
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