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Problem 10.17. For a rectangular pulse shape, by how much does null-to-null transmission bandwidth increase, if the transmission rate is increased by a factor of three? Solution Without loss of generality, consider the baseband BPSK signal: ,)()( ∑ −= k k kTthbts where T is the symbol duration, bk = +1 or -1 for transmitted 1 or 0, respectively. The pulse h(t) is rectangular, ⎟⎠ ⎞⎜⎝ ⎛ −= T Ttth 2/rect)( . The Fourier transform H(f) of h(t) is 2 / 2( ) sinc( ) sin( ) j fT j fT H f T fT e fTT e fT π ππ π − − = ⋅ = . Inspecting a plot of the sinc function, we see the null-to-null transmission bandwidth of H(f) is B = 2/T. When the transmission rate is increased by a factor three, we have the new symbol duration . The null-to-null bandwidth / 3T T′ = 2 / 3B T B′ ′= = , increased by a factor of 3. Excerpts from this work may be reproduced by instructors for distribution on a not-for-profit basis for testing or instructional purposes only to students enrolled in courses for which the textbook has been adopted. Any other reproduction or translation of this work beyond that permitted by Sections 107 or 108 of the 1976 United States Copyright Act without the permission of the copyright owner is unlawful.
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