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Chapter Problem 42P Step by step solution Step Determine the input voltage peak value for output signal extremes at the edge of clipping For an undistorted output, write the range of input voltage Substitute -10 for L. 1000 for 10 for L. -10 10 1000 1000 -10mV 10mV the output signal extremes at the edge of clipping for the input voltage peak value are 10mV Step Draw the output signal waveform as shown in Figure 1. 10 V- t 0 Θ Figure Step From Figure at time 4. the sinusoidal signal value is V sin 2π T =10 2π 10 π sin 10 (1) 2 Step of 9 When clipping is 90% of time, then 10% of time normal wave appears Determine the peak value of the output signal Replace 100 10 for 7 equation 10 Step Replace for in equation (1). 180 V sin π 10 V 0.15643 = =63.92 Step of 9 Determine the peak value of input signal A, Substitute 63.92 V for 1000 for A, 63.92 1000 =63.92 mV the peak value of input signal 63.92 mV Step When clipping is 99% then 1% of time normal wave appears Determine the peak value of the output Replace 100 for Step Replace for in equation = 10 10 0.157 =636.64 V Step Determine the peak value of input signal Substitute 636.64 V for 1000 for A, in equation 636.64 1000 =636.64 mV Therefore, the peak value of input signal 636.64 mV

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