1 (157)

Prévia do material em texto

157Chapter 10 Spectroscopic Measurements
Chapter 10
1. he following ive equations provide the relationships between the 
four variables included in this problem
E h E hc c E hc1o
m
o m o
m
o= = = = =
 For the irst row, given a wavelength of 4.50×10–9 m, we have
c
4.50 10 m
3.00 10 m/s 6.67 10 s9
8
16 1
#
#
#o
m
= = =-
-
1
4.50 10 m
1
100 cm
1 m 2.22 10 cm9
6 1
#
# #o
m
= = =-
-
E hc
4.50 10 m
(6.626 10 Js) (3.00 10 m/s)
4.42 10 J9
34 8
17
#
# #
#
m
= = =
-
-
 For the second row, given a frequency of 1.33×1015 s–1, we have
c
1.33 10 s
3.00 10 m/s 102.26 m15 1
8
7
#
#
#m o= = =-
-
.
.1
2 26
4 42
10 m
1
100 cm
1 m 10 cm7
4 1
#
# #o
m
= = =-
-
E h (6.626 10 Js) (1.33 10 s ) 8.81 10 J1534 1 19
# # #o= = =
- - -
 For the third row, given a wavenumber of 3215 cm–1, we have
1
cm
1
100 cm 10 m
3215
1 m 3.111
6
# #m
o
= = =-
-
c
3.11 10 m
3.00 10 m/s 9.65 10 s6
8
13 1
#
#
#o
m
= = =-
-
. .E h 9 65 6 39(6.626 10 Js) ( 10 s ) 10 J13 2034 1
# # #o= = =
- - -
 For the fourth row, given an energy of 7.20×10–19 J, we have
E
hc
7.20 10 J
(6.626 10 Js) (3.00 10 m/s)
2.76 10 m19
34 8
7
#
# #
#m = = =-
-
-
h
E
6.626 10 Js
7.20 10 J
1.09 10 s34
19
15 1
#
#
#o = = =-
-
-
1
2.76 10 m
1
100 cm
1 m 3.62 10 cm7
4 1
#
# #o
m
= = =-
-
2. he following two equations provide the relationships between the 
ive variables included in this problem
logA bC A Tf= =-
 For the irst row we ind that
A bC (1120 M cm )(1.00 cm)(1.40 10 M) 0.1571 1 4
#f= = =
- - -
T T10 10 0.697 or 69.7%.A 0 157
= = =
- -