Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_440

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Step 4.001P (a) Connect the cathode of the diode to the positive terminal of the battery and draw the equivalent circuit. + - D D + 1 Ω 1.5 V Figure Since the cathode (-ve) of the diode is connected to the positive of the battery, the diode will be in reverse An ideal diode in reverse bias, acts as open circuit. Thus, the diode current is 0A Step of 5 Replace the diode with open circuit and draw the equivalent circuit. + - I D = 0 - + I 1 Ω 1.5 V Figure 2 Apply voltage law in the circuit as shown in Figure 2. Thus, the terminal voltage across the diode -1.5V Step of 5 (b) Connect the anode of the diode to the positive terminal of the battery and draw the equivalent - + K D D - + 1 Ω 1.5 V Figure 3 Since the anode (+ve) of the diode is connected to the positive of the battery, the diode will be in forward bias. An ideal diode in forward bias, acts as short circuit. Thus, the terminal voltage across the diode VD is 0V Step of 5 Replace the diode with short circuit and draw the equivalent circuit. = 0 - + I D - + 1 Ω 1.5 V Figure 4 Step of 5 Apply Kirchhoff's Voltage Law in the circuit as shown in Figure 4. Thus, the diode current is 1.5A