Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_432

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Step 1 of 3 3.023P Calculate the power dissipation at break down region. In the break down region, the power dissipation is equals to the half of the rated value. = 0.125 W Determine the value of continuous current in the breakdown region. Substitute 0.125 W for and 12 V for V₂ in the equation. =0.01042 = 10.42 mA Thus, the value of continuous current in the breakdown region, is 10.42 mA Step 2 of 3 Determine the value of breakdown current when the power dissipation rated at 0.25 W. Substitute 0.25 W for and 12 V for in the equation. = = 20.83 mA Step 3 of 3 Determine the value of allowed average breakdown current when breakdown occurs for only 10 ms in every 20 = =41.66x10⁻³ Thus, the allowed average breakdown current, z(avg) is 41.66 mA