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Step 1 of 2 6.026E Refer to Figure 6.25(a) in the text book for the transistor circuit. Apply Kirchhoff's voltage law to the emitter-base loop. Substitute 1 for 10⁻³ = 9.3 kΩ Thus, the emitter resistance to establish a collector current of 1 mA is 9.3 kΩ - Step 2 of 2 Apply Kirchhoff's voltage law to the collector-base loop. Substitute 4V for and 10⁻³ A for Substitute 0.3 V for as the transistor is at the edge of saturation and 0.7 V for 10-4 = 10⁻³ = 6 10³ Ω = 6 kΩ Thus, the collector resistance Rc is 6