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Step 1 of 15 7.043P the figure 7.25(b) textbook The transconductance Substitute 100 for 25 mV Thus, 40mA/V Step 2 of 15 The resistance g. Substitute 40mA/V 100 for equation 100 Thus value of resistance Step 3 of 15 Output resistance Substitute 100 I mA in the equation 100 V Thus output resistance Step 4 of 15 Common emitter current gain Substitute 100 1 mA for 100 Thus Step 5 of 15 Determine the Substitute equation Thus 25 mV Determine product of Substitute 8. mA (25 mV) Thus Step 7 of 15 Hybrid shown E Figure 2 Determination the T-Model equivalent Determine th Substitute in equation =1.01 mA Thus emitter current 1.01 mA he resistance Substitute 1.01 mA 1.01 mA Thus, value resistance Determine the B+1 Substitute 100 equation 100 100+1 =0.99 Thus 0.99 Step 12 of 15 Determine current Substitute 25 mV for and for in equation 25mV 1.01 mA Step 13 of 15 ai, Substitute 0.99 and value of Step 14 of 15 shown Figure + Step 15 of 15 B E Therefore the designs of four small signa with are done

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