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Chapter 4 Chemical Quantities and Aqueous Reactions 67 2 molecules Cl₂ Solution: 4 molecules HCI X = 2 molecules Cl₂ 4 molecules HCI 2 molecules Cl₂ 5 molecules O₂ X = 10 molecules Cl₂ 1 molecule O₂ theoretical yield = 2 molecules Cl₂ Check: The units of the answer (molecules Cl₂) are correct. The answer is reasonable based on the limiting reactant in each mixture. 4.41 (a) Given: 4 mol Ti; 4 mol Cl₂ Find: theoretical yield TiCl₄ Conceptual Plan: mol Ti mol 1 mol smaller mol amount determines limiting reactant 1 mol Ti mol mol TiCl₄ 1 mol 2 mol Cl₂ 1 mol Solution: 4 X = 4 mol 1 mol 4 mol X 1 mol = 2 mol TiCl₄ 2 mol theoretical yield = 2 mol Check: The units of the answer (mol are correct. The answer is reasonable because Cl₂ produced the smaller amount of product and is the limiting reactant. (b) Given: 7 mol Ti; 17 mol Cl₂ Find: theoretical yield TiCl₄ Conceptual Plan: mol Ti mol TiCl₄ 1 mol TiCl₄ smaller mol amount determines limiting reactant 1 mol Ti mol Cl₂ mol TiCl₄ 1 mol 2 mol Cl₂ 1 mol Solution: 7 molTi X = 7 mol 1 17 X 1 mol = 8.5 mol TiCl₄ 2 theoretical yield = 7 mol TiCl₄ Check: The units of the answer (mol are correct. The answer is reasonable because Ti produced the smaller amount of product and is the limiting reactant. (c) Given: 12.4 mol Ti; 18.8 mol Cl₂ Find: theoretical yield TiCl₄ Conceptual Plan: mol Ti mol TiCl₄ 1 mol smaller mol amount determines limiting reactant 1 mol Ti mol Cl₂ mol TiCl₄ 1 mol 2 mol Cl₂ 1 mol TiCl₄ Solution: 12.4 Ti X = 12.4 mol 1 mol 18.8 X 1 2 mol = 9.40 mol theoretical yield = 9.40 mol Check: The units of the answer (mol are correct. The answer is reasonable because Cl₂ produced the smaller amount of product and is the limiting reactant. Copyright © 2017 Pearson Education, Inc.