Soluções de Problemas de Dispositivos Semicondutores

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Semiconductor Physics and Devices: Basic Principles, 4
th
 edition Chapter 13 
By D. A. Neamen Problem Solutions 
______________________________________________________________________________________ 
 
(c)    GSbipODS VVVsatV  
 (i)    0860.0705.3 satVDS 
 845.2 V 
 (ii)     0.1860.0705.3 satVDS 
 845.1 V 
_______________________________________ 
 
13.5 
(a) 
2
2 2
2 ea
V
N
Nea
V
pOs
a
s
a
pO



 
 
   
  2419
14
1065.0106.1
75.21085.81.132




aN 
 
1510433.9  cm 3 
(b)  
  
  










26
1815
108.1
1010433.9
ln0259.0biV 
 280.1 V 
 280.175.2  bipOp VVV 
 47.1 V 
(c) 22 65.015.0 hha  
 50.02 h m 
 
 
2/1
2
2





 

a
GSSDbis
eN
VVV
h 
  241050.0  
 
   
   












1519
14
10433.9106.1
028.11085.81.132 GSV
 
   GSV  28.1105363.1105.2 99 
 347.0 GSV V 
(d) 
 
2/1
2
2





 

a
GSSDbis
eN
VVV
h 
  241065.0  
 
   
   












1519
14
10433.9106.1
28.11085.81.132 SDV
 
     SDV  28.1105363.11065.0 924 
 47.1 SDV V 
_______________________________________ 
 
13.6 
(a) 
2
2
ea
V
N
pOs
a

 
 
   
  2419
14
1065.0106.1
75.21085.87.112




 
 
or 
 aN
1510425.8  cm 3 
(b)  
  
  










210
1815
105.1
1010425.8
ln0259.0biV 
 8095.0 V 
 8095.075.2  bipOp VVV 
 9405.1 V 
(c) 22 65.015.0 hha  
 50.02  h m 
 
 
2/1
2
2





 

a
GSSDbis
eN
VVV
h 
  241050.0  
 
   
   












1519
14
10425.8106.1
08095.01085.87.112 GSV
 
   GSV  8095.010536.1105.2 99 
 8178.0 GSV V 
(d) 
 
2/1
2
2





 

a
GSSDbis
eN
VVV
h 
  241065.0  
 
   
   












1519
14
10425.8106.1
8095.01085.87.112 SDV
 
     SDV  8095.010536.11065.0 924 
 94.1 SDV V 
_______________________________________ 
 
13.7 
(a) 









2
ln
i
da
tbi
n
NN
VV 
  
  
  










210
1816
105.1
103102
ln0259.0 
 860.0 V 
 bipOp VVV  
 86.3860.00.3  pOpO VV V 
 Now 
2/1
2





 

a
pOs
eN
V
a 
 
   
  
2/1
1619
14
102106.1
86.31085.87.112











 
 
5100.5  cm 50.0 m