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Solutions to Problems 115 (e) N (f) :SeCN CH₃ 40. Bimolecular displacement is first order in each component. (a) Rate = 2 X 10⁻⁸ mol = k(0.1 M)(0.1 M), so k = 2 X 10⁻⁶L (b) The three rates are (i) 4 X 10⁻⁸; (ii) 1.2 X 10⁻⁷; and (iii) 3.2 X 10⁻⁷ mol respectively. 41. (a) CH₃CH₂CH₂I (b) (CH₃)₂CHCH₂CN (c) CH₃OCH(CH₃)₂ (d) CH₃CH₂SCH₂CH₃ (e) CH₂Se(CH₂CH₃)₂⁺ (f) 42. (a) Starting material is R. H Br CH₃ Product is S. CH₂CH₃ (b) Starting material is H I CH₃ Product is (2R,3R)-2,3-diiodobutane. I H (c) Starting material is (1S,3R)-3-chlorocyclohexanol (the position of the OH group is understood to be C1). O OCCH₃ Product is (1S,3S)-3-hydroxycyclohexyl acetate. (d) Starting material is OCCH₃ Product is (1R,3S)-3-hydroxycyclohexyl acetate. 2 3