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Step of 6 2.009P It is given that the particular inverting operational amplifier circuit is an ideal one and having two 10 kΩ resistors. Assume that one resistor is in feedback path and one is at input path. Draw the topology of the expected inverting op-amp circuit diagram. i₂ v, + Figure 1 Step of 6 From the concept of virtual ground, the potential at inverting terminal is equal to the potential at non- inverting terminal. Since, the given op-amp is an ideal; currents entering into both the terminals are zero. The voltage at non-inverting terminal is at zero potential. Therefore, =0V Apply Kirchhoff's current law at node = v, since = 0 G Step of 6 Substitute 10 kΩ for and 10 kΩ for R2 in the expression of closed loop voltage gain, G. G = V/V Therefore, the expected closed loop voltage gain, G of the amplifier is - V/V Step of 6 It is given that; the input dc voltage is, v, = V Write the expression for output voltage using the closed loop gain expression. = Substitute -1 V/V for G and 1 V for = (-1 = V Therefore, the resulted output voltage, is -1V - V Step of 6 The 10 kΩ resistors are said to be 1% resistors having values somewhere in the range times the nominal value. The value of input voltage is, v, = V Write the expression for voltage gain. Substitute V for 1 = Step of 6 Determine the expected range of outputs as follows: -(1-0.01) (1+0.01) 1+0.01 1-0.01 0.99 -1.01 1.01 0.99 -0.98