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Ph Ph h) NaOH 1. BH₃, THF 2.H₂O₂, NaOH 11.39 H H-O-H + Ph-C=CH Ph-C=CH₂ + H H H H :0-H H H I+ H-O-H + Ph-C-CH₃ Ph-C-CH₃ H-O: H enol 11.40 a) The left compound is has a faster rate because a tertiary carbocation intermediate is more stable than a secondary carbocation intermediate. b) The right compound has a faster rate because the electron-withdrawing nitro group destabilizes the carbocation intermediate. c) The right compound has a faster rate because the carbocation intermediate is resonance stabilized. + 11.41 a) The two chloronium ions that are formed in this reaction are enantiomers (non-superimposable H mirror images). H CH₃ CH₃CH₂ H C C H CH₃ 185