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Semiconductor Physics and Devices: Basic Principles, 4
th
 edition Chapter 12 
By D. A. Neamen Problem Solutions 
______________________________________________________________________________________ 
 
Chapter 12 
 
12.1 
 Sketch 
_______________________________________ 
 
12.2 
 Sketch 
_______________________________________ 
 
12.3 
(a) 
B
BBEn
S
x
nAeD
I 0 
 
    
4
3519
1080.0
10410518106.1




 
 15102.7  A 
(b) 








t
BE
SC
V
II

exp 
 (i)   





 
0259.0
58.0
exp102.7 15
CI 
 
510827.3  A 27.38 A 
 (ii)   





 
0259.0
65.0
exp102.7 15
CI 
 
410710.5  A 571.0 mA 
(iii)   





 
0259.0
72.0
exp102.7 15
CI 
 
310519.8  A 519.8 mA 
_______________________________________ 
 
12.4 
(a) 








t
BE
B
B
BEn
C
V
n
x
AeD
i

exp0 
 
  
4
19
3
1080.0
22106.1
102





 BEA
 
   






0259.0
60.0
exp102 4 
 410975.1  BEA cm 2 
(b) 
   
4
419
3
1080.0
10975.122106.1
105





 
   






0259.0
exp102 4 BE
 
   





 
0259.0
exp10738.1105 133 BE
 
 
 
 Then 
   












13
3
10738.1
105
ln0259.0BE 
 6237.0 BE V 
_______________________________________ 
 
12.5 
(a) 7.65
9850.01
9850.0
1







 
 (b) 
 (i) For 27.38CI A, 
 

5828.0
67.65
27.38
 C
B
I
I A 
 

85.38
9850.0
27.38
 C
E
I
I A 
 (ii) For 571.0CI mA, 
 008695.0
67.65
571.0
BI mA 
 695.8 A 
 5797.0
9850.0
571.0
EI mA 
 (iii) For 519.8CI mA, 
 1297.0
67.65
519.8
BI mA 
 649.8
9850.0
519.8
EI mA 
(c) 7.165
9940.01
9940.0


 
 (i) For 27.38CI A, 
 2310.0
7.165
27.38
BI A 
 50.38
9940.0
27.38
EI A 
 (ii) For 571.0CI mA, 
 003446.0
7.165
571.0
BI mA 
 446.3 A 
 5744.0
9940.0
571.0
EI mA