Transformações Físicas da Matéria

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112 4 PHYSICAL TRANSFORMATIONS OF PURE SUBSTANCES
of ln p is independent of the units of p due to the logarithm.
dp
dT
= pd ln p
dT
= p × d ln p
dy
× dy
dT
= p × d
dy
( − 10.418
y
+ 21.157 − 15.996y + 14.015y2 − 5.0120y3
+ 4.7334(1 − y)1.70) × d
dT
( T
Tc
)
= p
Tc
× (10.418
y2
− 15.996 + 28.030y − 15.0360y2
− 8.04678(1 − y)0.70)
= 105 Pa
593.95K
( 10.418
(0.645...)2
− 15.996 + 28.030(0.645...) − 15.0360(0.645...)2
− 8.04678(1 − 0.645...)0.70) = 2.84... × 103 PaK−1
�en
∆vapH = T∆vapV × dp
dT
= (383.54K) × ([30.3 − 0.12] × 10−3m3mol−1) × (2.84... × 103 PaK−1)
= 33.0 kJmol−1
I4.4 (a) �e data are plotted in Fig. 4.4.
100 120 140 160 180 200
0.0
2.0
4.0
T/K
p/
M
Pa
Figure 4.4
�ese data �t well to the cubic
p/MPa = (4.989×10−6 K−3)T3−(1.452×10−3 K−2)T2+(0.1461K−1)T−5.058
�is equation is used to plot the line on the graph.