callister7e sm ch03 57

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3-72 
 X-ray Diffraction: Determination of Crystal Structures 
 
 3.57 From the Table 3.1, aluminum has an FCC crystal structure and an atomic radius of 0.1431 nm. 
Using Equation 3.1, the lattice parameter a may be computed as 
 
 a=2 R 2 = (2) (0.1431 nm) 2 = 0.4048 nm 
 
Now, the interplanar spacing d110 maybe determined using Equation 3.14 as 
 
 
d110 =
a
(1)2 + (1)2 + (0)2
= 0.4048 nm
2
= 0.2862 nm 
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