aplique a teoria de Bhaskara x²-10x+14=0​ ?

∆ = b² - 4ac

∆ = (-10)² - 4(1)(14)

∆ = 100 - 56

∆ = 44

x= -B ± √∆/2a

x = -(-10) ± √44/2

x= 10 + √44/2

Simplificando a raiz ficaria duas raiz de 11

x' = 5 + 2√11

x' = 5 - 2√11

x = -B ± √∆/2a

x = -(-10) ± √ (-10)² - 4.1.14 / 2

x = 10 ± √100 - 56 / 2

x = 10 ± √44 / 2

x' = 5 + 2√11

x' = 5 - 2√11