Calcule a integral a seguir: A (3(x^3+1)√(x^2+1))/3+c,c ∈ R B (2(x^3+1)√(x^3+1))/3+c, c ∈ R C (2(x^2+1)√(x^2+1))/3+c,c ∈ R D (3(x^3+1)√(x^3+1))/3+c...
Calcule a integral a seguir:
A (3(x^3+1)√(x^2+1))/3+c,c ∈ R
B (2(x^3+1)√(x^3+1))/3+c, c ∈ R
C (2(x^2+1)√(x^2+1))/3+c,c ∈ R
D (3(x^3+1)√(x^3+1))/3+c,c ∈ R
A (3(x^3+1)√(x^2+1))/3+c,c ∈ R
B (2(x^3+1)√(x^3+1))/3+c, c ∈ R
C (2(x^2+1)√(x^2+1))/3+c,c ∈ R
D (3(x^3+1)√(x^3+1))/3+c,c ∈ R
A (3(x^3+1)√(x^2+1))/3+c,c ∈ R
B (2(x^3+1)√(x^3+1))/3+c, c ∈ R
C (2(x^2+1)√(x^2+1))/3+c,c ∈ R
D (3(x^3+1)√(x^3+1))/3+c,c ∈ R
A (3(x^3+1)√(x^2+1))/3+c,c ∈ R
B (2(x^3+1)√(x^3+1))/3+c, c ∈ R
C (2(x^2+1)√(x^2+1))/3+c,c ∈ R
D (3(x^3+1)√(x^3+1))/3+c,c ∈ R
💡 1 Resposta
Ed 
A integral da função fornecida é dada por: B) (2(x^3+1)√(x^3+1))/3+c, c ∈ R
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