Ed
ano passado
Para calcular \(\operatorname{sen}(\pi / 12)\), podemos usar a fórmula de seno da diferença: \[ \operatorname{sen}(A - B) = \operatorname{sen}(A) \cdot \cos(B) - \cos(A) \cdot \operatorname{sen}(B) \] Podemos escolher \(A = \pi / 4\) e \(B = \pi / 6\), pois \(\pi / 12 = \pi / 4 - \pi / 6\). Agora, vamos calcular: 1. \(\operatorname{sen}(\pi / 4) = \frac{\sqrt{2}}{2}\) 2. \(\cos(\pi / 4) = \frac{\sqrt{2}}{2}\) 3. \(\operatorname{sen}(\pi / 6) = \frac{1}{2}\) 4. \(\cos(\pi / 6) = \frac{\sqrt{3}}{2}\) Substituindo na fórmula: \[ \operatorname{sen}(\pi / 12) = \operatorname{sen}(\pi / 4) \cdot \cos(\pi / 6) - \cos(\pi / 4) \cdot \operatorname{sen}(\pi / 6 \] \[ = \left(\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}\right) - \left(\frac{\sqrt{2}}{2} \cdot \frac{1}{2}\right) \] \[ = \frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4} = \frac{\sqrt{6} - \sqrt{2}}{4} \] Agora, para simplificar \(\operatorname{sen}(\pi / 12)\), podemos reescrever: \[ \operatorname{sen}(\pi / 12) = \frac{\sqrt{2 - \sqrt{3}}}{2} \] Portanto, a alternativa correta é: a) \(\frac{\sqrt{2-\sqrt{3}}}{2}\).
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